Parent function
A parent function is the simplest representative form of a family of functions. In this clip, the quadratic parent function is shown as , and its basic graph is sketched as an upward-opening parabola.
SVMathTeach · YouTube · 4:50
This introductory Algebra 2 whiteboard clip defines a parent function, illustrates it with , and lists common transformations of a function graph: horizontal and vertical shifts, reflections, and vertical stretches or compressions. It then works Example A in full, translating 4 units left and 3 units down to obtain . The speaker emphasizes the key rule that a left shift is written with plus inside the function argument. Examples B and C are shown on the board but are not solved within this segment. This introductory algebra whiteboard clip teaches how to rewrite under common transformations. It works through three examples: (A) translate 4 units left and 3 down to get ; (B) translate 5 units right and reflect across the x-axis to get ; and (C) translate 5 units right and reflect across the y-axis to get . The key rules emphasized are that horizontal shifts go inside the parentheses with the opposite sign, vertical shifts go outside the function, x-axis reflection negates the whole function, and y-axis reflection negates only x.
Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.
Generated from the video's visuals and explanation; not verbatim speech.
The clip opens on a digital whiteboard headed “2-6 Functions, Equations, and Graphs” with the subheading “FAMILIES OF FUNCTIONS.” The speaker introduces the topic as families of functions and immediately frames the lesson around a base object that will later be modified.
The first mathematical idea is the parent function. The speaker defines it verbally as “the simplest form of a function,” and the board reinforces this by writing the example . A small upward-opening parabola is sketched beside the formula, visually connecting the algebraic rule to its standard graph.
Next, the lesson broadens from the single example to a classification of transformations. The handwritten outline names shifts left, right, up, and down; reflections; and vertical stretches plus compressions. In speech, the presenter explains that these operations move or reshape the graph of the parent function, including making it “skinnier and taller” or “shorter and kind of squatter.”
The speaker then transitions from definitions to practice, saying that three examples will stand in for a fuller textbook chart. The board scrolls to a worked-problem section labeled “(Ex) Write the equation for the transformation of the graph ,” followed by parts (A), (B), and (C). Only part (A) is actually solved in this segment.
Part (A) asks for the equation after translating the graph 4 units left and 3 units down. Before solving, the speaker highlights the main conceptual trap: intuitively, “left” suggests a negative coordinate, but that intuition does not directly determine the symbolic form inside the function.
The derivation proceeds from the base equation . First, the horizontal translation is encoded inside the argument: because the shift is 4 units left, the speaker writes and explicitly states that left uses plus. This is the central rule emphasized in the clip.
Second, the vertical translation is handled outside the function. Moving 3 units down is represented by appending , yielding the final equation . The answer is boxed on the board, and the speaker identifies this boxed expression as the required equation for the transformed graph.
At the end of the segment, the board still shows the prompts for parts (B) and (C): “translate 5 units right, reflect across the x-axis” and “translate 5 units right, reflect across the y-axis.” The speaker begins to move on to letter B, but no solution for B or C is completed within the provided clip.
The clip opens on a digital whiteboard with three transformation prompts already written: (A) translate 4 units left, 3 down; (B) translate 5 units right, reflect across the x-axis; and (C) translate 5 units right, reflect across the y-axis. Part (A) is already completed as , which serves as a reference for the rules being discussed.
The instructor starts solving part (B) from the base relation . Because the prompt says “5 units right,” he applies the horizontal-translation rule inside the argument and writes . He explicitly stresses that the sign is opposite the intuitive direction: right corresponds to subtraction inside the parentheses.
He then separates the next operation from ordinary vertical shifting. While mentioning that up/down changes are simpler outside adjustments, he introduces reflection as a different kind of modification that requires a negative sign in a specific location.
For reflection across the x-axis, the explanation is that points on top flip to the bottom relative to the x-axis. This is reinforced by an orange sketch showing a curve above a horizontal line and its mirror image below the line. The algebraic consequence is to place a negative sign in front of the entire function, turning into .
With part (B) finished, the board now displays the completed transformed equation , boxed for emphasis. The instructor frames this as a preliminary step in the broader topic of function transformations.
He moves to part (C), noting that it is almost the same as part (B) except for the type of reflection. Again starting from , he first applies the same horizontal shift of 5 units right, producing .
For reflection across the y-axis, he says the negative sign must be introduced in a different place: only the input variable becomes negative. Thus the expression changes from to , and the final boxed answer for part (C) is .
The closing summary contrasts the rules directly: horizontal movement goes inside the parentheses with the opposite sign, vertical movement is handled outside the function, reflection across the x-axis negates the whole function, and reflection across the y-axis negates only inside the argument.
A parent function is the simplest representative form of a family of functions. In this clip, the quadratic parent function is shown as , and its basic graph is sketched as an upward-opening parabola.
The lesson classifies transformations of a function graph into horizontal and vertical shifts, reflections, and vertical stretches or compressions. These are presented as operations performed on the parent function’s graph.
For a horizontal translation, the shift is inserted inside the function argument with . The clip specifically teaches that moving left by 4 units is written as , not as a minus sign in that position.
For a vertical translation, the change is appended outside the function. Moving down by 3 units is represented by subtracting 3, giving the terminal term in the transformed equation.
Starting from , the graph is translated 4 units left and 3 units down. Applying the inside-argument rule and then the outside-function rule produces the final equation , which is boxed on the board.
Students often associate “left” with a negative number and therefore expect a minus sign. The speaker explicitly corrects this by showing that a leftward horizontal shift uses addition inside the function argument.
Parts (B) and (C) are visible on the board as additional transformation problems involving a rightward translation and reflections across the x-axis or y-axis, but neither is solved within this clip.
Horizontal shifts are made inside the function argument. A shift left by units gives , and a shift right by units gives . The instructor emphasizes that the sign inside the parentheses is opposite the verbal direction.
Vertical shifts are made outside the function. Moving up by units adds to the whole function, and moving down by units subtracts . Example (A) uses this rule to append after .
Reflecting across the x-axis changes the sign of every output value. Algebraically, the negative sign is placed in front of the entire function. The orange sketch illustrates a curve above the axis flipping to below it.
Reflecting across the y-axis changes the sign of the input variable only. The negative sign is placed on inside the argument, not in front of the whole function. In the worked example, becomes .
Starting from , translate 4 units left and 3 units down. The left shift gives , and the downward shift appends outside the function.
Starting from , translate 5 units right and reflect across the x-axis. The right shift gives , and the x-axis reflection places a negative sign in front of the whole function.
Starting from , translate 5 units right and reflect across the y-axis. The right shift gives , and the y-axis reflection changes only to inside the argument.
A frequent error is to write for a rightward shift. The clip explicitly warns that horizontal movement uses the opposite sign inside the parentheses: right means , left means in the examples shown.
The clip distinguishes two reflection rules by placement of the negative sign. For the x-axis, the negative is outside the function as in . For the y-axis, the negative is on the input variable as in .
Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.
The handwritten notation uses at the start of the parent-function example and again in the worked transformation equation.
The speaker says “whether that’s written as y equals or f of x,” linking to the dependent-variable notation.
y
Dependent variable or output value of a function.
Real-valued outputs are implied by the graphing context; no explicit domain is stated.
The board shows beside the parent-function example and inside the transformed equation .
The speaker refers to “f of x” as an alternative way to write the function.
Function notation for the value of the function at input ; here used first as the parent function and then as the base expression being transformed.
The parent-function example is written as , and the horizontal shift is inserted into .
The speaker discusses moving left/right relative to the input position and writes the shift inside the parentheses with .
x
Independent variable or input value of the function.
The board shows as the example parent function.
The speaker says “let’s imagine we had something like x squared” and calls it the simplest version.
Quadratic parent-function rule used as the concrete example of a parent function.
The worked equation becomes after the speaker explains the left shift.
The speaker says “if I want to move it left, I use plus.”
+4
Horizontal-shift term inserted inside the function argument to represent a translation 4 units left.
The final boxed equation is .
The speaker says “three down is just minus three.”
-3
Vertical-shift term appended outside the function to represent a translation 3 units down.
The board repeatedly shows the base relation written as .
The original function relation before applying the listed transformations.
General function notation; no explicit domain is stated in the clip.
The variable x appears inside the transformed expressions such as , , and .
The instructor says horizontal movement goes inside the parentheses and uses x with a number.
x
The input variable of the function, modified for horizontal translations and reflection across the y-axis.
Input variable in the function argument.
The function name f is used throughout the worked examples.
f
The given function being transformed.
Unspecified general function.
Part (A) text includes translate 4 units left, and the worked formula contains .
The instructor refers to moving left and using the opposite sign inside the parentheses.
4
The horizontal shift amount in part (A).
Positive constant used in a translation.
Part (A) text includes 3 down, and the worked formula ends with -3.
The instructor discusses up/down adjustments as outside-the-function changes.
3
The vertical shift amount in part (A).
Positive constant used in a vertical translation.
Parts (B) and (C) both include translate 5 units right, and the worked formulas contain x-5.
The instructor says five units to the right and then uses the opposite sign inside the parentheses.
5
The horizontal shift amount in parts (B) and (C).
Positive constant used in a translation.
The speaker says, “most functions will have what is called a parent function,” and defines it as “the simplest form of a function.”
The board writes as the example.
A simple upward-opening parabola is sketched next to the formula.
A parent function is the simplest representative form of a family of functions. In this clip, the quadratic parent function is illustrated by , whose basic graph is a parabola.
Used as the starting function before transformations are applied.
The example shown is quadratic, but the spoken definition is general.
The speaker lists possible changes: shift left/right, up/down, reflect across the x- or y-axis, stretch vertically, or compress vertically.
The board text reads “Transformations = Shifts left, right, up, down / reflections / Vertical stretches + Compressions.”
The clip introduces transformations as operations applied to a parent function’s graph. The named categories are translations (left, right, up, down), reflections, and vertical stretches or compressions.
These are presented as general ways to modify the graph of a parent function.
Only horizontal and vertical translations are actually solved within this clip.
The speaker explicitly warns that moving left is not represented by a negative sign outside the function; instead, “if I want to move it left, I use plus.”
The worked equation inserts the shift inside the argument as .
For a horizontal translation, the shift amount is placed inside the function argument with . In this clip, translating 4 units left is encoded as , so the transformed expression begins as .
Applies to horizontal shifts of the graph of .
The clip demonstrates only the left-shift case explicitly.
The speaker says “three down is just minus three.”
The final equation appends outside the function: .
For a vertical translation, the shift amount is added or subtracted outside the function. In this clip, moving 3 units down is represented by appending , giving .
Applies to vertical shifts of the graph of .
The clip demonstrates the downward case explicitly.
The instructor explains that when moving left or right, the change goes inside the parentheses and the plus or minus is opposite of what you would expect.
Translate 4 units left is written as ; translate 5 units right is written as .
For a horizontal shift, modify the input variable inside the function argument. A shift to the left by h units corresponds to replacing x by , while a shift to the right by h units corresponds to replacing x by x-h. The instructor emphasizes that the sign inside the parentheses is opposite the intuitive direction word.
The transformation is applied to the input variable x.
The shift amount is a positive constant h.
The instructor contrasts horizontal changes with up/down changes and treats vertical shifts as easier adjustments outside the function.
Part (A) shows 3 down as an appended -3 outside the function: .
For a vertical shift, add or subtract a constant outside the function. Moving down by k units subtracts k from the whole function value, while moving up by k units adds k. In the worked example, 3 down is represented by appending -3 after .
The transformation is applied after evaluating the function.
The shift amount is a positive constant k.
The instructor says that if you are reflecting across the x-axis, something on top flips over to the bottom, so you put a negative sign in front of the entire function.
Part (B) changes from to -f(x-5).
An orange sketch shows a curve above a horizontal line flipping to below it.
Reflecting a graph across the x-axis changes the sign of every output value. Algebraically, this is done by placing a negative sign in front of the entire function, not inside the argument. The instructor visually describes this as the top of the graph flipping over to the bottom.
The reflection is across the x-axis.
The negative sign applies to the whole function value.
The instructor says that when reflecting across the y-axis, you only make the x negative.
Part (C) changes from to .
Reflecting a graph across the y-axis changes the sign of the input variable only. Algebraically, this means replacing x by -x inside the function argument while leaving the outside of the function unchanged. In the worked example, the translated expression becomes .
The reflection is across the y-axis.
The negative sign is applied only to the input variable x.
The speaker states that when moving left, one should use plus rather than minus, calling this the key point that causes issues.
The worked solution writes for a translation 4 units left.
To translate the graph of four units left, replace by , producing .
The starting graph has equation .
The intended transformation is a horizontal translation 4 units left.
For the specific example shown in the clip.
The speaker says “three down is just minus three.”
The final boxed equation is .
To translate the graph of three units down, append to the function, producing ; combined with the left shift, the result is .
The starting graph has equation .
The intended transformation includes a vertical translation 3 units down.
For the specific example shown in the clip.
The instructor states that for left/right movement, the plus or minus inside the parentheses is opposite of what you would expect.
Left 4 becomes , and right 5 becomes x-5 in the worked examples.
When translating a function horizontally, the sign inserted with x inside the parentheses is opposite the verbal direction: left uses + and right uses -.
The transformation is a horizontal translation of .
The shift amount is positive.
For the horizontal translations demonstrated in this clip.
The instructor says that reflecting across the x-axis means putting a negative sign in front of the entire function.
The worked result for part (B) is -f(x-5).
To reflect a graph across the x-axis, multiply the entire function by -1.
The reflection is across the x-axis.
For the function-transformation setting shown in the clip.
The instructor says that when reflecting across the y-axis, you only make the x negative.
The worked result for part (C) is .
To reflect a graph across the y-axis, replace x by -x inside the function argument.
The reflection is across the y-axis.
For the function-transformation setting shown in the clip.
The speaker builds the answer step by step from the base idea , first handling the left shift and then the down shift.
The board shows the progression from to .
Start from the given parent-form equation for the untransformed graph.
This is the base function specified in the problem statement on the board.
Apply the horizontal translation 4 units left by inserting inside the function argument.
The speaker explicitly states that moving left uses plus inside the parentheses.
Apply the vertical translation 3 units down by subtracting 3 outside the function.
The speaker states that “three down is just minus three.”
The transformed equation for translating four units left and three units down is .
The board shows the prompt translate 5 units right, reflect across the x-axis, and the worked answer develops into -f(x-5).
The instructor narrates the right shift first and then the x-axis reflection.
Start from the original function relation shown on the board.
Base function given in the problem setup.
Apply the horizontal translation 5 units to the right by subtracting 5 from x inside the argument.
Horizontal translation rule: right by h gives x-h.
Apply the reflection across the x-axis by placing a negative sign in front of the whole function.
Reflection across the x-axis changes the sign of the output values.
The transformed equation for part (B) is .
The board shows the prompt translate 5 units right, reflect across the y-axis, and the worked answer develops into .
The instructor repeats the right-shift step and then says to make only the x negative for the y-axis reflection.
Start again from the original function relation.
Base function given in the problem setup.
Apply the horizontal translation 5 units to the right.
Horizontal translation rule: right by h gives x-h.
Apply the reflection across the y-axis by changing only the x term to -x inside the argument.
Reflection across the y-axis replaces x by -x.
The transformed equation for part (C) is .
The board text reads “(Ex) Write the equation for the transformation of the graph ” and “(A) translate 4 units left, 3 down.”
The speaker reads the prompt aloud and solves part A.
The final handwritten answer is boxed as .
Write the equation for the transformation of the graph when it is translated 4 units left and 3 units down.
Original graph: .
Transformation: 4 units left.
Transformation: 3 units down.
Find the equation of the transformed graph.
Begin with the original function notation given in the problem.
This is the starting equation stated on the board.
Encode the leftward horizontal shift by adding 4 inside the argument.
The speaker identifies this as the key rule: left means plus inside .
Encode the downward vertical shift by subtracting 3 outside the function.
The speaker directly states that 3 down corresponds to .
The final equation matches the boxed handwritten result on the board.
The board shows “(B) translate 5 units right, reflect across the x-axis.”
The speaker says “Let’s try the second one. Letter B. Translate…” but the clip ends before the solution is completed.
No worked steps or final equation for part B appear within the provided clip.
The exact intended answer is not shown in this segment.
Write the equation for the transformation of the graph when it is translated 5 units right and reflected across the x-axis.
Original graph: .
Transformation: 5 units right.
Transformation: reflect across the x-axis.
Find the equation of the transformed graph.
The problem statement is visible on the board, but no solution steps are completed in this clip.
The video reaches the end of the segment while introducing part B.
Not completed within this clip.
Only the prompt is present; no final answer is displayed before the clip ends.
The board shows “(C) translate 5 units right, reflect across the y-axis.”
The speaker does not solve part C in this clip.
No worked steps or final equation for part C appear within the provided clip.
The exact intended answer is not shown in this segment.
Write the equation for the transformation of the graph when it is translated 5 units right and reflected across the y-axis.
Original graph: .
Transformation: 5 units right.
Transformation: reflect across the y-axis.
Find the equation of the transformed graph.
The problem statement is visible on the board, but no solution steps are completed in this clip.
The segment ends before part C is addressed.
Not completed within this clip.
Only the prompt is present; no final answer is displayed before the clip ends.
The board shows (A) translate 4 units left, 3 down and the completed answer .
The instructor discusses left/right movement going inside the parentheses and up/down movement as an outside adjustment.
Given , write the transformed equation for a translation 4 units left and 3 units down.
Original function:
Horizontal shift: 4 units left
Vertical shift: 3 units down
Produce the transformed formula.
Move 4 units left by adding 4 inside the function argument.
Horizontal translation rule: left by h gives .
Move 3 units down by subtracting 3 outside the function.
Vertical translation rule: down by k gives -k outside the function.
The final boxed expression on the board matches the stated transformations.
The board shows (B) translate 5 units right, reflect across the x-axis and the completed answer .
The instructor explicitly says to go opposite for the right shift and then put a negative sign in front of the entire function for the x-axis reflection.
Given , write the transformed equation after translating 5 units right and reflecting across the x-axis.
Original function:
Horizontal shift: 5 units right
Reflection: across the x-axis
Produce the transformed formula.
Translate 5 units right by subtracting 5 from x inside the argument.
Horizontal translation rule: right by h gives x-h.
Reflect across the x-axis by multiplying the whole function by -1.
Reflection across the x-axis changes the sign of all outputs.
The final boxed expression on the board is -f(x-5).
The board shows (C) translate 5 units right, reflect across the y-axis and the completed answer .
The instructor says that for the y-axis reflection, only the x becomes negative.
Given , write the transformed equation after translating 5 units right and reflecting across the y-axis.
Original function:
Horizontal shift: 5 units right
Reflection: across the y-axis
Produce the transformed formula.
Translate 5 units right by subtracting 5 from x inside the argument.
Horizontal translation rule: right by h gives x-h.
Reflect across the y-axis by replacing x with -x inside the argument.
Reflection across the y-axis changes the sign of the input variable only.
The final boxed expression on the board is .
The page header reads “2-6 Functions, Equations, and Graphs” and “FAMILIES OF FUNCTIONS.” Below it are handwritten notes: “Parent function” and “Transformations = Shifts left, right, up, down / reflections / Vertical stretches + Compressions.”
The speaker writes next to “Parent function.”
Title text
Handwritten section heading
Parent-function note
Transformations list
The parent-function example is added during the opening explanation.
The overall lesson topic remains families of functions and transformations.
The visual organization establishes that the lesson will define a parent function and then classify common transformations of its graph.
A small upward-opening parabola is drawn beside .
The speaker says the example “would be a parabola, nice and simple.”
Parabola sketch
Formula
A simple U-shaped curve is added to visualize the parent function.
The sketch represents the untransformed parent graph only.
The drawing links the algebraic rule to its standard graphical shape, a parabola.
Under part (A), the equation is built progressively until the final boxed form appears.
The final answer is enclosed in a pink box.
Problem text for (A)
Handwritten equation
Pink box around the final answer
The equation develops from the base form to the fully transformed form .
The original prompt remains “translate 4 units left, 3 down.”
The visual writing sequence shows how each verbal transformation rule is encoded symbolically in the final equation.
An orange horizontal line is drawn, then a curved shape above it, followed by a mirrored curved shape below it.
The instructor says that if something is on top, it would flip over and end up on the bottom because this is the x-axis.
orange horizontal line representing the x-axis
upper orange curve
lower orange curve
A curve above the line is drawn first.
A matching curve below the line is added to show the flipped position.
The horizontal line stays fixed as the mirror axis.
The sketch is used to represent sign change of output values.
The drawing visually supports the rule that reflection across the x-axis sends positive-height portions of the graph to negative-height portions, corresponding to multiplying the whole function by -1.
Different parts of the board use blue, pink/magenta, orange, and green ink for prompts, intermediate terms, and final boxed answers.
The instructor mentions switching colors when discussing different transformation pieces.
Exact color assignment varies across moments and is not fully labeled on screen.
blue handwritten formulas
pink/magenta emphasis on vertical-shift discussion
orange emphasis for x-axis reflection work
green emphasis for y-axis reflection work
The board accumulates three worked examples from top to bottom.
Final answers are boxed in colored outlines.
The original prompts remain visible while the solutions are built underneath them.
The color coding helps separate horizontal-shift ideas, vertical-shift ideas, and the two different reflection rules.
The speaker says that when thinking of moving left from the origin, one naturally thinks of negative 4, “but that’s not what this is,” and then emphasizes that left uses plus inside the function.
Because moving left on a number line corresponds to negative values, students may expect a left translation to be written with a minus sign.
For horizontal translations of , a shift left is represented by adding inside the argument, as in , not by subtracting there.
The instructor explicitly warns that when thinking of right, one may think plus, but the needed sign is the opposite.
Learners may expect a rightward horizontal translation to be written with +x.
The clip states that horizontal movement goes inside the parentheses and the sign is opposite the intuitive direction: right uses x-h, left uses .
The instructor distinguishes x-axis reflection from y-axis reflection by where the negative sign is placed.
Part (B) uses -f(x-5), while part (C) uses .
Learners may confuse which reflection requires a negative outside the function and which requires a negative on x inside the function.
Reflection across the x-axis puts the negative in front of the entire function, while reflection across the y-axis puts the negative only on x inside the argument.
The speaker first defines the parent function and then immediately lists transformations that can be applied to it.
The board places “Parent function” above the list of transformation types.
The notion of a parent function is needed before discussing transformations, because transformations are described as changes made to the graph of that simplest base function.
After listing transformations generally, the speaker narrows to the specific rule for horizontal shifts in Example A.
The general category “Shifts left, right” becomes the concrete expression in the worked example.
The broad category of transformations includes horizontal translations, and the clip then specifies the rule for encoding a leftward shift inside the function argument.
The general list includes up/down shifts, and the worked example applies the down-shift rule explicitly.
The general category becomes the concrete appended term in .
Vertical translations are one member of the transformation family introduced earlier, and the clip demonstrates the downward case by appending outside the function.
Example A uses the rule directly by writing for a left shift.
Example A applies the horizontal-shift rule to turn the verbal instruction “4 units left” into the symbolic term inside the function.
Example A uses the rule directly by appending for a downward shift.
Example A applies the vertical-shift rule to turn the verbal instruction “3 down” into the symbolic term outside the function.
The instructor contrasts inside-the-parentheses changes for left/right with outside changes for up/down.
Part (A) combines with -3 outside.
Horizontal translations modify the input inside f( ), while vertical translations modify the output outside f( ).
The worked examples compare -f(x-5) and .
The instructor explicitly says these are almost exactly the same except for where the negative sign goes.
Both are reflections, but the x-axis reflection negates the whole function value, whereas the y-axis reflection negates only the input variable.
Part (B) is built from a right shift followed by an x-axis reflection.
Example (B) applies the horizontal translation rule to obtain .
Part (B) ends as -f(x-5).
Example (B) applies the x-axis reflection rule by placing a negative sign in front of the whole function.
Part (C) is built from a right shift followed by a y-axis reflection.
Example (C) applies the horizontal translation rule to obtain .
Part (C) ends as .
Example (C) applies the y-axis reflection rule by changing x to -x inside the argument.
The speaker defines parent function and gives as the example.
The board lists shifts, reflections, and vertical stretches/compressions.
The speaker explicitly contrasts the intuitive “negative 4” idea with the actual rule of using plus for a left shift.
The worked answer for part A is shown as .
Parts B and C are visible as prompts, but the clip ends before their solutions are written.
The instructor repeatedly says the sign inside the parentheses is opposite the direction word.
The instructor explains the top-to-bottom flip and places the negative in front of the whole function.
The instructor says only the x becomes negative for reflection across the y-axis.
The board shows combined transformations such as , -f(x-5), and .
The instructor notes that the last two problems are almost exactly the same except for the reflection type.
The final answers differ as -f(x-5) versus .
Covered · Opening title and spoken introduction to the topic of families of functions.
Covered · Definition of parent function with the example and a parabola sketch.
Covered · Overview of transformation types: shifts, reflections, vertical stretches and compressions.
Covered · Transition to worked examples; the speaker notes that three examples will be used and that one point will cause issues.
Covered · Reading of Example A and setup of the common misconception about leftward movement.
Covered · Step-by-step derivation of for Example A; prompts for Examples B and C are visible but not solved before the clip ends.
Covered · The board shows parts (A), (B), and (C); the instructor begins part (B) by writing the rightward horizontal translation .
Covered · The instructor explains x-axis reflection, sketches the flip, and completes part (B) as -f(x-5).
Covered · The instructor works part (C), first writing and then changing it to , followed by a spoken summary contrasting the rules.
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