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How do the limits change when using u-substitution in a definite integral?

When using u-substitution in a definite integral, the original limits of integration in terms of xx must be converted into new limits in terms of uu. This is done by substituting the original xx-bounds into the substitution equation u(x)u(x). For the arc-length integral with xx ranging from 00 to 32/932/9 and u=1+94xu = 1 + \frac{9}{4}x, the lower limit becomes u=1+94(0)=1u = 1 + \frac{9}{4}(0) = 1, and the upper limit becomes u=1+94(329)=9u = 1 + \frac{9}{4}(\frac{32}{9}) = 9.

Conditions

  • The integral is a definite integral.
  • A substitution u=u(x)u = u(x) is being used.
  • The original limits of integration are given in terms of xx.

Reasoning, step by step

  1. Identify the original lower and upper limits of integration in terms of xx.
  2. Write down the substitution equation relating uu to xx.
  3. Substitute the original lower xx-limit into the equation to find the new lower uu-limit.
  4. Substitute the original upper xx-limit into the equation to find the new upper uu-limit.
  5. Rewrite the definite integral using the new uu-limits and the transformed integrand.

Example

In the worked example, the instructor states, "And then we just have to change the bounds of integration." He substitutes x=0x=0 to get u=1u=1, and x=32/9x=32/9 to get u=9u=9, converting the integral bounds from [0,32/9][0, 32/9] in xx to [1,9][1, 9] in uu.

Common misconceptions

  • Forgetting to change the bounds of integration when switching from dxdx to dudu.
  • Substituting the xx-limits into the wrong equation or failing to evaluate the arithmetic correctly.
  • Evaluating the definite integral using the original xx-limits after transforming the integrand to uu.

Watch the explanation

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