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How do you apply integration by parts to the integral of xexx e^x?

For ∫xex dx\int x e^x \, dx, choose u=xu=x and dv=ex dxdv=e^x \, dx. This gives du=dxdu=dx and v=exv=e^x. Applying the formula yields xex−∫ex dxxe^x - \int e^x \, dx, which simplifies to xex−ex+Cxe^x - e^x + C. This result is verified by differentiation.

Conditions

  • The integrand is xexx e^x.
  • The method is integration by parts.

Reasoning, step by step

  1. Set u=xu=x and dv=ex dxdv=e^x \, dx.
  2. Compute du=dxdu=dx and v=exv=e^x.
  3. Apply the integration by parts formula: uv−∫v duuv - \int v \, du.
  4. Substitute the terms: xex−∫ex dxxe^x - \int e^x \, dx.
  5. Evaluate the remaining integral: ∫ex dx=ex\int e^x \, dx = e^x.
  6. Combine results and add the constant of integration: xex−ex+Cxe^x - e^x + C.
  7. Verify by differentiating the result to recover xexx e^x.

Example

The script states: 'For xeˣ, choose u=xu=x and dv=eˣdx, so du=dx and v=ev=eˣ. The result is xeˣ−eˣ+C, verified by differentiation.'

Common misconceptions

  • Choosing u=exu=e^x and dv=x dxdv=x \, dx, which leads to a more complex integral.
  • Forgetting the constant of integration CC.
  • Incorrectly integrating exe^x as xex−1x e^{x-1}.

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