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How do you begin the Euclidean algorithm for gcd(1701;3768)?

To begin the Euclidean algorithm for gcd⁡(1701,3768)\gcd(1701, 3768), place the larger number (3768) on the left side of the division equation and the smaller number (1701) as the divisor. Write 3768=1701⋅q+r3768 = 1701 \cdot q + r. Calculating this division yields a quotient of 2 and a remainder of 366, giving the first step 3768=1701⋅2+3663768 = 1701 \cdot 2 + 366.

Conditions

  • The inputs are positive integers.
  • The larger number is used first on the left-hand side.
  • The quotient is an integer and the remainder satisfies 0≤r<17010 \le r < 1701.

Reasoning, step by step

  1. Identify the two integers, 1701 and 3768.
  2. Place the larger number (3768) on the left side of the equation.
  3. Set it equal to the smaller number (1701) multiplied by an unknown quotient qq plus an unknown remainder rr.
  4. Determine how many whole times 1701 fits into 3768, which gives the quotient q=2q = 2.
  5. Calculate the leftover amount, which gives the remainder r=366r = 366.
  6. Write the completed first division line: 3768=1701⋅2+3663768 = 1701 \cdot 2 + 366.

Example

The board shows 3768=1701×2+3663768 = 1701 \times 2 + 366. The narration describes 3768 divided by 1701 with quotient 2 and remainder 366.

Common misconceptions

  • Starting with the smaller number on the left side.
  • Forgetting to carry the remainder forward to the next step.
  • Assuming the algorithm requires factoring the numbers first.

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