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Why does the Euclidean algorithm move the old divisor and remainder into the next line?

The Euclidean algorithm moves the old divisor to the left-hand side (new dividend) and the old remainder to the smaller-number position (new divisor) to recursively reduce the problem. This shift ensures that each subsequent division step operates on smaller numbers while preserving the greatest common divisor of the original pair, continuing until a remainder of zero is reached.

Conditions

  • The algorithm is applied to two positive integers.
  • The previous remainder is not zero.
  • The process continues until a remainder of 0 is obtained.

Reasoning, step by step

  1. Complete a division step, such as 45=10⋅4+545 = 10 \cdot 4 + 5.
  2. Take the previous divisor (10) and move it to the left-hand side of the next equation.
  3. Take the previous remainder (5) and move it to the divisor position in the next equation.
  4. Perform the new division: 10=5⋅2+010 = 5 \cdot 2 + 0.
  5. Repeat the shift pattern until the remainder is 0.

Example

Arrows are drawn under the previous line to show 10 moving left and 5 moving into the next divisor position. The speaker says to take the number in this position and move it to where the left-hand-side number was, then take the remainder and move it to where the smaller number was.

Common misconceptions

  • Moving the quotient to the next step instead of the remainder.
  • Keeping the original dividend as the new dividend.
  • Believing the algorithm stops after the first division regardless of the remainder.

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