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How does the amplitude of the resultant wave behave when two equal-frequency sinusoids with arbitrary phase difference superpose?

The amplitude of the resultant sinusoid lies between the absolute difference and the sum of the individual amplitudes, specifically bounded by ∣A1−A2∣≤A≤A1+A2|A_1 - A_2| \le A \le A_1 + A_2. Both the amplitude and the phase position of the resultant wave change relative to the inputs.

Conditions

  • Two sinusoids have equal frequency.
  • There is an arbitrary phase difference ϕ\phi between them.
  • Amplitudes are non-zero (A1=2,A2=0.8A_1=2, A_2=0.8 in the demo).

Reasoning, step by step

  1. Observe the bottom coordinate system demonstrating superposition with an arbitrary phase difference.
  2. Note that the blue wave (A=2A=2) combines with a phase-shifted red wave (A=0.8A=0.8).
  3. Analyze the resulting green wave, which exhibits changes in both amplitude and phase position.
  4. Recall the general formula for the resultant amplitude: A=A12+A22+2A1A2cos⁡ϕA=\sqrt{A_1^2+A_2^2+2A_1A_2\cos\phi}.
  5. Conclude that the amplitude varies continuously depending on ϕ\phi, staying within the bounds defined by complete constructive and destructive interference.

Example

From 00:14 to 00:21, the bottom coordinate system shows a blue wave (A=2A=2) combining with a phase-shifted red wave (A=0.8A=0.8). The script notes the production of a green wave exhibiting changes in both amplitude and phase position. The card provides the formula A=A12+A22+2A1A2cos⁡ϕA=\sqrt{A_1^2+A_2^2+2A_1A_2\cos\phi}.

Common misconceptions

  • Believing that the equilibrium position shifts during superposition (it does not; only amplitude and phase change).
  • Assuming the resultant amplitude is simply the arithmetic mean of the two amplitudes regardless of phase.

Watch the explanation

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.