Skip to content
← All questions

How does the proof demonstrate that every common divisor of a and b also divides the least positive linear combination d?

The proof demonstrates this by showing that d is a linear combination of a and b. Since any common divisor divides both a and b, it must also divide any integer linear combination of them, including d.

Conditions

  • d is the least positive linear combination of a and b.
  • c is a common divisor of a and b.

Reasoning, step by step

  1. Recall that d can be written as d = au + bv for some integers u and v.
  2. Let c be any common divisor of a and b, meaning c divides a and c divides b.
  3. Apply the property of divisibility: if c divides a and b, then c divides any linear combination au + bv.
  4. Conclude that c divides d.
  5. Combine this with the fact that d divides a and b to show d is the greatest common divisor.

Example

The script states: 'Thus d divides both; every common divisor also divides d.'

Common misconceptions

  • Thinking that only the greatest common divisor divides linear combinations.
  • Believing that d must be equal to a or b to be divisible by common divisors.
  • Confusing the direction of divisibility between d and its divisors.

Watch the explanation

Connected concepts

Explore next

Related questions

Meet the concept

↗
Find a method

↗
Meet the concept

↗
Find a method

↗
Find a method

↗

Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.