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How is the intercept b0b_0 calculated once the slope b1b_1 is known?

The intercept b0b_0 is calculated by substituting the mean point (xˉ,yˉ)(\bar{x}, \bar{y}) and the known slope b1b_1 into the regression equation y^=b0+b1x\hat{y} = b_0 + b_1x, and then solving algebraically for b0b_0. In the example, substituting x=3x=3, y^=4\hat{y}=4, and b1=0.6b_1=0.6 yields 4=b0+0.6(3)4 = b_0 + 0.6(3), which simplifies to b0=2.2b_0 = 2.2.

Conditions

  • The slope b1b_1 has already been computed.
  • The sample means xˉ\bar{x} and yˉ\bar{y} are known.
  • The regression line is assumed to pass through (xˉ,yˉ)(\bar{x}, \bar{y}).

Reasoning, step by step

  1. Write the general regression equation y^=b0+b1x\hat{y} = b_0 + b_1x.
  2. Substitute the mean values x=xˉx = \bar{x} and y^=yˉ\hat{y} = \bar{y} into the equation.
  3. Substitute the computed slope b1b_1 into the equation.
  4. Perform the multiplication to simplify the term b1xˉb_1\bar{x}.
  5. Subtract the product from yˉ\bar{y} to isolate b0b_0.

Example

The video writes 4=b0+.6(3)4 = b_0 + .6(3), simplifies it to 4=b0+1.84 = b_0 + 1.8, and subtracts 1.8 from both sides to get 2.2=b02.2 = b_0.

Common misconceptions

  • Substituting an arbitrary data point instead of the mean point.
  • Forgetting to multiply the slope by the x-value before isolating the intercept.
  • Assuming the intercept is simply the mean of the y-values.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.