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In the epsilon-delta definition game, which quantity is chosen first, epsilon or delta?

In the logical structure of the definition, ϵ\epsilon is chosen first. It represents the prescribed tolerance for the output. δ\delta is chosen second, in response to the specific ϵ\epsilon, to guarantee that the input range maps into the output range. The order is: 'give ϵ>0\epsilon > 0', then 'find δ>0\delta > 0'.

Conditions

  • The definition is viewed as a challenge or game.
  • ϵ\epsilon is the independent variable in the logical quantification.
  • δ\delta depends on the chosen ϵ\epsilon.

Reasoning, step by step

  1. A challenger selects an arbitrary ϵ>0\epsilon > 0.
  2. The responder must find a δ>0\delta > 0 that works for that specific ϵ\epsilon.
  3. The validity of the limit depends on the responder's ability to find such a δ\delta for *every* possible ϵ\epsilon.
  4. Conclude that ϵ\epsilon precedes δ\delta in the logical order.

Example

The board explicitly writes 'give ϵ>0\epsilon > 0' followed by 'They'll give a δ\delta'. The speaker describes this as: 'you define what you want by giving me an epsilon... I can get you as close as you want... by giving you a range around the point that x is approaching'.

Common misconceptions

  • Thinking that δ\delta is chosen first and ϵ\epsilon follows.
  • Believing that δ\delta is independent of ϵ\epsilon; in fact, δ\delta is a function of ϵ\epsilon.
  • Confusing the temporal order of drawing on the graph with the logical order of the definition.

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