Skip to content
← All questions

Is dVdV always equal to dx dy dzdx \, dy \, dz in triple integrals?

No, dVdV is not always equal to dx dy dzdx \, dy \, dz. In Cartesian coordinates, dV=dx dy dzdV = dx \, dy \, dz, but in other coordinate systems, such as cylindrical or spherical coordinates, the expression for dVdV changes to account for the geometry of the coordinate grid.

Conditions

  • The current setup uses rectangular/Cartesian coordinates.
  • In other coordinate systems, such as polar-type coordinates mentioned verbally, dVdV may take a different form.

Reasoning, step by step

  1. Identify the coordinate system being used.
  2. For Cartesian coordinates, use dV=dx dy dzdV = dx \, dy \, dz.
  3. For other coordinate systems, derive or look up the appropriate expression for dVdV.
  4. Substitute the correct dVdV into the triple integral.

Example

The speaker says dVdV is the same thing as width times height times depth, and adds that dVdV does not always have to be dx dy dzdx \, dy \, dz if other coordinates are used.

Common misconceptions

  • Confusing dVdV with only the Cartesian product dx dy dzdx \, dy \, dz.
  • Assuming the volume element is the same in all coordinate systems.

Watch the explanation

Explore next

Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.