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What are the kernel and range of the linear map T(x₁,x₂,x₃)=(x₁−x₂,2x₃)?

The kernel is spanned by the vector (1,1,0), and the range is all of the two-dimensional codomain. The nullity is one and the rank is two.

Conditions

  • The linear map is defined as T(x₁,x₂,x₃)=(x₁−x₂,2x₃).
  • The domain is three-dimensional and the codomain is two-dimensional.

Reasoning, step by step

  1. Identify the kernel by finding vectors where T(x)=0T(x)=0.
  2. Solve x₁−x₂=0 and 2x₃=0 to find the basis (1,1,0).
  3. Identify the range by observing the output dimensions.
  4. Conclude the range spans the entire two-dimensional codomain.
  5. Determine the nullity as the dimension of the kernel (1).
  6. Determine the rank as the dimension of the range (2).

Example

For T(x₁,x₂,x₃)=(x₁−x₂,2x₃), the kernel is spanned by (1,1,0) and the range is all of the two-dimensional codomain. The nullity is one and the rank is two.

Common misconceptions

  • Assuming the kernel contains more than one basis vector.
  • Believing the range is a proper subset of the codomain when it is actually the entire space.

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