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What general form does the first PDE force for f(W,t)f(W,t)?

Solving the first PDE fW=σff_W = \sigma f forces the general form f(W,t)=φ(t)eσWf(W,t) = \varphi(t)e^{\sigma W}, where φ(t)\varphi(t) is an arbitrary function of time.

Conditions

  • fW=σff_W = \sigma f holds.
  • σ\sigma is constant.

Reasoning, step by step

  1. Start with the ODE fW=σff_W = \sigma f treating tt as a parameter.
  2. Integrate with respect to WW to get f(W,t)=CeσWf(W,t) = C e^{\sigma W}.
  3. Allow the integration constant CC to depend on tt, denoting it as φ(t)\varphi(t).
  4. Conclude the separated form f(W,t)=φ(t)eσWf(W,t) = \varphi(t)e^{\sigma W}.

Example

The board writes 'f(W,t)=φ(t)eσWf(W,t) = \varphi(t) e^{\sigma W}' after solving the first PDE.

Common misconceptions

  • Assuming the integration constant is a true constant independent of tt.
  • Forgetting the exponential dependence on WW.

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