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What is the antiderivative of u\sqrt{u} used here?

The antiderivative of u\sqrt{u} is found by rewriting the square root as a fractional power, u1/2u^{1/2}, and then applying the power rule for integration. The power rule states that ∫undu=un+1n+1\int u^n du = \frac{u^{n+1}}{n+1}. For n=1/2n = 1/2, this yields u3/23/2\frac{u^{3/2}}{3/2}, which simplifies to 23u3/2\frac{2}{3}u^{3/2}.

Conditions

  • The integrand is u\sqrt{u}, which is equivalent to u1/2u^{1/2}.
  • The power rule for integration is applicable.
  • u≥0u \ge 0 for the real-valued square root form.

Reasoning, step by step

  1. Rewrite the integrand u\sqrt{u} as u1/2u^{1/2}.
  2. Apply the power rule for integration: add 1 to the exponent to get 3/23/2.
  3. Divide by the new exponent 3/23/2.
  4. Simplify the expression u3/23/2\frac{u^{3/2}}{3/2} by multiplying by its reciprocal, resulting in 23u3/2\frac{2}{3}u^{3/2}.

Example

The instructor explains that the antiderivative of u1/2u^{1/2} is u3/2u^{3/2} divided by 3/23/2, which is multiplying by 2/32/3. The board shows the antiderivative as 23u3/2\frac{2}{3}u^{3/2}.

Common misconceptions

  • Forgetting to add 1 to the exponent when applying the power rule.
  • Incorrectly dividing by the original exponent instead of the new exponent.
  • Failing to simplify the complex fraction 13/2\frac{1}{3/2} to 23\frac{2}{3}.

Watch the explanation

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.