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What is the relationship between the dot product of a vector with itself and its length?

The dot product of a vector a\mathbf{a} with itself, a⋅a\mathbf{a} \cdot \mathbf{a}, is equal to the square of its length (norm), ∥a∥2\|\mathbf{a}\|^2.

Conditions

  • The vector is a real coordinate vector.
  • The length is the Euclidean norm.

Reasoning, step by step

  1. Calculate the dot product a⋅a\mathbf{a} \cdot \mathbf{a} by summing the squares of its components.
  2. Calculate the length ∥a∥\|\mathbf{a}\| by taking the square root of the sum of the squares of its components.
  3. Square the length ∥a∥2\|\mathbf{a}\|^2.
  4. Compare the two results to see they are identical.

Example

For a vector a=(a1,a2,...,an)\mathbf{a} = (a_1, a_2, ..., a_n), a⋅a=a12+a22+...+an2\mathbf{a} \cdot \mathbf{a} = a_1^2 + a_2^2 + ... + a_n^2, which is exactly ∥a∥2\|\mathbf{a}\|^2.

Common misconceptions

  • Thinking a⋅a\mathbf{a} \cdot \mathbf{a} is the length itself, not the squared length.
  • Confusing the dot product with the cross product magnitude.
  • Believing this relationship only holds for unit vectors.

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