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What is the solution to the example system 2x+3y=62x+3y=6 and x−2y=−4x-2y=-4?

The example 2x+3y=62x+3y=6 and x−2y=−4x-2y=-4 has solution (0,2).

Conditions

  • The system consists of the equations 2x+3y=62x+3y=6 and x−2y=−4x-2y=-4.

Reasoning, step by step

  1. Substitute x=0x=0 and y=2y=2 into the first equation: 2(0)+3(2)=62(0)+3(2)=6, which holds.
  2. Substitute x=0x=0 and y=2y=2 into the second equation: 0−2(2)=−40-2(2)=-4, which holds.
  3. Conclude that (0,2) is the solution.

Example

The script states: 'The example 2x+3y=62x+3y=6 and x−2y=−4x-2y=-4 has solution (0,2).'

Common misconceptions

  • Assuming the solution is (2,0) due to ordering confusion.
  • Believing there are multiple solutions for this specific consistent independent system.

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