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What is the structure of the solution set for a consistent nonhomogeneous linear system Ax=b?

If x₀ is one particular solution, all solutions have the form x₀+z where z is any vector in the kernel of A (i.e., Az=0). The solution set is an affine translate of the kernel and does not necessarily pass through the origin.

Conditions

  • The system Ax=b is consistent.
  • x₀ is a specific solution such that Ax₀=b.

Reasoning, step by step

  1. Find one particular solution x₀ to the equation Ax=b.
  2. Identify the kernel of A, which consists of all vectors z such that Az=0.
  3. Express the general solution as the sum of the particular solution and any vector from the kernel: x=xx = x₀ + z.
  4. Recognize that this set forms an affine subspace shifted away from the origin if b≠0b \ne 0.

Example

The script states: 'If x₀ is one solution, all solutions have the form x₀+z with Az=0. A nonhomogeneous solution set is an affine translate of the kernel and need not pass through the origin.'

Common misconceptions

  • Believing that the solution set always passes through the origin.
  • Thinking that the kernel itself is the solution set for nonhomogeneous systems.
  • Confusing the particular solution with the general solution.

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