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What is the standard deviation of the data 6, 7, 8, 9, 10?

The standard deviation of this population dataset is 2\sqrt{2}, which is approximately 1.41. This is found by first calculating the mean (8), then the population variance (2), and finally taking the square root of the variance.

Conditions

  • The data 6, 7, 8, 9, 10 is treated as a complete population.
  • The number of data points is 5.

Reasoning, step by step

  1. Calculate the mean: 6+7+8+9+105=8\frac{6+7+8+9+10}{5} = 8.
  2. Calculate the population variance: σ12=(6−8)2+(7−8)2+(8−8)2+(9−8)2+(10−8)25=4+1+0+1+45=105=2\sigma_1^2 = \frac{(6-8)^2+(7-8)^2+(8-8)^2+(9-8)^2+(10-8)^2}{5} = \frac{4+1+0+1+4}{5} = \frac{10}{5} = 2.
  3. Calculate the standard deviation by taking the non-negative square root of the variance: σ1=2≈1.41\sigma_1 = \sqrt{2} \approx 1.41.

Example

The video displays the three-line solution: Mean = 8; σ12=2\sigma_1^2 = 2; σ1=2≈1.41\sigma_1 = \sqrt{2} \approx 1.41.

Common misconceptions

  • Reporting the variance (2) as the final answer instead of the standard deviation (2\sqrt{2}).
  • Using the sample variance formula (dividing by 4) which would yield 2.5≈1.58\sqrt{2.5} \approx 1.58.
  • Rounding intermediate steps incorrectly before taking the final square root.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.