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Why can P(AB) be directly replaced with P(B)P(B) in the conditional probability formula for this box problem?

Because event B (exactly two boxes are empty) is a subset of event A (at least one box is empty). If B occurs, A necessarily occurs. Therefore, the intersection AB is equal to B, and their probabilities are equal: P(AB) = P(B)P(B).

Conditions

  • A is defined as "at least one box is empty".
  • B is defined as "exactly two boxes are empty".
  • The sample space consists of all distributions of 4 distinct balls into 4 distinct boxes.

Reasoning, step by step

  1. Analyze the definitions of events A and B.
  2. Determine the logical relationship: "exactly two empty" implies "at least one empty".
  3. Conclude that B ⊆ A.
  4. Apply the set theory property: if B ⊆ A, then A ∩ B=BB = B.
  5. Substitute P(AB) with P(B)P(B) in the conditional probability formula.

Example

The video states: "Exactly two empty boxes implies at least one empty box, so B is contained in A and their intersection is B."

Common misconceptions

  • Assuming P(AB) always requires a separate complex counting process.
  • Thinking that A and B are independent events.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.