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Why divide by 5 for the variance in this problem?

The variance is divided by 5 because the dataset is explicitly identified as a full population of 5 numbers. In population variance, the denominator is the total number of data points (n=5n=5). If this were a sample used to estimate a population variance, the common Bessel-corrected sample variance would divide by n−1=4n-1=4, but that inferential setting does not apply here.

Conditions

  • The dataset is a complete population, not a sample.
  • The number of data points nn is 5.

Reasoning, step by step

  1. Identify the nature of the data from the problem statement: it is a 'population data'.
  2. Recall the formula for population variance: σ2=∑(xi−xˉ)2n\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n}.
  3. Substitute the number of data points, n=5n=5, into the denominator.
  4. Conclude that dividing by 5 is correct for calculating the exact variance of this specific population.

Example

The problem stem explicitly writes 'population data' with 5 numbers: 6, 7, 8, 9, 10. The video calculates the variance as σ12=105=2\sigma_1^2 = \frac{10}{5} = 2, using 5 in the denominator.

Common misconceptions

  • Confusing population standard deviation with sample standard deviation, mistakenly thinking the denominators are the same.
  • Applying the n−1n-1 correction factor (Bessel's correction) to a full population dataset.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.