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Dividing by n2n^2 to Evaluate Limits of Rational Partial Sums

Why divide numerator and denominator by n2n^2 when evaluating the limit of SnS_n?

Dividing by the highest power of nn in the denominator (which is n2n^2) isolates the asymptotic behavior of each term. It transforms lower-order terms into fractions with nn in the denominator, which clearly tend to 0 as n→∞n \to \infty, revealing that the numerator dominates and the limit is infinity.

Conditions

  • The expression is a quotient of polynomials in nn.
  • The limit is taken as n→∞n \to \infty.
  • The highest power of nn in the denominator is n2n^2.

Reasoning, step by step

  1. Expand the denominator to identify the highest power of nn.
  2. Divide both the numerator and the denominator by this highest power (n2n^2).
  3. Observe the behavior of each term as n→∞n \to \infty.
  4. Conclude that terms with nn in the denominator approach 0, while the simplified numerator grows without bound.

Example

Dividing 2n3n2+3n+2\frac{2n^3}{n^2+3n+2} by n2n^2 yields 2n1+3n+2n2\frac{2n}{1+\frac{3}{n}+\frac{2}{n^2}}. As n→∞n \to \infty, 3n→0\frac{3}{n} \to 0 and 2n2→0\frac{2}{n^2} \to 0, so the denominator approaches 1 while the numerator 2n→∞2n \to \infty.

Common misconceptions

  • Believing that dividing by n2n^2 changes the value of the limit.
  • Assuming the denominator's growth forces the whole fraction to 0 without checking the numerator's degree.

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