Why does a monotone increasing sequence bounded above converge to its supremum?
Conditions
- The sequence is monotone increasing.
- The sequence is bounded above.
- is the supremum of the set of sequence values.
- is an arbitrary positive tolerance.
Reasoning, step by step
- Identify the supremum of the sequence values, which exists by the Least Upper Bound Property.
- For any given , consider the value .
- Since is the *least* upper bound, cannot be an upper bound.
- Therefore, there must exist some term in the sequence such that .
- Use the monotonicity condition: for all , .
- Combine these inequalities to show that for all , .
- Conclude that the terms are trapped in the epsilon neighborhood of , proving .
Example
The video visually demonstrates this by plotting a rising dotted curve for , marking the red dashed line for the supremum , and the green dashed line for . It shows that once the curve crosses the green line at index , it remains trapped between the green and red lines for all subsequent indices.
Common misconceptions
- Believing that the sequence must reach the supremum exactly at some finite term.
- Thinking that the proof relies on the sequence being strictly increasing rather than just monotone increasing.
- Confusing the supremum with a maximum value that must be attained by the sequence.
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