Why does the exact choice of sample point not affect the final volume?
In the limiting process where the partition becomes infinitely fine (), the exact location of the sample point inside each subrectangle does not matter. While different choices of will yield different finite Riemann sums (approximations), the limit of these sums as the subrectangles shrink to zero size is independent of the specific interior point chosen.
Conditions
- Applies in the limit as the partition norm .
- Each must be chosen inside its corresponding subrectangle.
Reasoning, step by step
- Acknowledge that for a finite partition, the choice of affects the sum's value.
- Consider the limit process where subrectangles become infinitesimally small.
- Recognize that as the subrectangle area approaches zero, the variation in function values within it also approaches zero.
- Conclude that the limiting volume is independent of the specific sample point choice.
Example
The lecturer states at the beginning of the formal definition segment: 'where exactly you choose the , inside of the rectangle is not going to actually matter' in the limit. The 2D diagram shows a yellow point labeled inside a red rectangle, illustrating that it can be anywhere inside.
Common misconceptions
- Believing that a specific rule (like always choosing the bottom-left corner) is required for the exact volume.
- Thinking that the finite sum's dependence on the sample point means the exact integral also depends on it.
- Assuming the sample point must be the centroid or a specific geometric center.
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