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Why does the geometric series with first term 1 and ratio 1/21/2 converge to a finite limit despite having infinitely many terms?

The series converges because its partial sums SnS_n approach a specific finite value, which is 2. As shown in the video, the formula for the partial sum is Sn=2(1−12n+1)S_n = 2(1 - \frac{1}{2^{n+1}}). Since the term 12n+1\frac{1}{2^{n+1}} approaches 0 as nn goes to infinity, the entire expression approaches 2.

Conditions

  • First term a=1a=1
  • Common ratio r=1/2r=1/2

Reasoning, step by step

  1. Identify the parameters: first term is 1, ratio is 1/21/2.
  2. Observe the behavior of the partial sums SnS_n as nn increases.
  3. Apply the derived formula Sn=2(1−2−(n+1))S_n = 2(1 - 2^{-(n+1)}).
  4. Evaluate the limit as n→∞n \to \infty, where 2−(n+1)→02^{-(n+1)} \to 0.
  5. Conclude that the sum stabilizes at 2.

Example

The script states: 'Start with a geometric series whose first term is 1 and ratio is 1/21/2. Its partial sums approach 2.' It further provides the explicit formula: 'Sn=2(1−2−(n+1))S_n=2(1−2^{−(n+1)})'.

Common misconceptions

  • Believing that adding infinitely many numbers always results in infinity.
  • Confusing the number of terms (n+1n+1) with the index nn when calculating limits.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.