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Why School B's Normal Curve Is Right of School A's Due to Higher Mean

Why is School B's normal curve drawn to the right of School A's when comparing their score distributions?

School B's normal curve is drawn to the right of School A's because the mean determines the horizontal position of the normal curve. Since School B's mean score of 65 is greater than School A's mean score of 60, the center and peak of School B's curve are located to the right of School A's center on the score axis.

Conditions

  • The horizontal axis represents scores and increases to the right.
  • The score distributions of both schools are close to normal distributions.

Reasoning, step by step

  1. Identify the mean score for School A, which is 60.
  2. Identify the mean score for School B, which is 65.
  3. Compare the two means: 65>6065 > 60.
  4. Apply the property that the mean determines the horizontal position of the normal curve.
  5. Conclude that School B's curve center is to the right of School A's curve center.

Example

The video states: 'School A has mean 60, below School B’s 65, so the thick curve’s center is left of the thin curve’s center.'

Common misconceptions

  • Believing that the curves have disjoint supports; both normal densities still have support on the entire real line.
  • Thinking that a higher mean implies a taller curve; the mean only controls horizontal position, not height.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.