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Answers for “为什么 |R_n(s)| 在半平面 Re(s) >= 1+a 中的最大值在边界 s = 1+a 处取得?”

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The lecture rewrites the tail sum Rn(s)R_n(s) by substituting s=σ+its=\sigma+it, yielding terms of the form 1kσe−it(log⁡k)\frac{1}{k^{\sigma}}e^{-it(\log k)}. It then applies the triangle inequality, which states that the absolute value of a sum is at most the sum of the absolute values.

Conditions: s=σ+its = \sigma + it where σ>1\sigma > 1.; Rn(s)=∑k=n+1∞1ksR_n(s) = \sum_{k=n+1}^{\infty} \frac{1}{k^s} is the tail of the zeta series.; The triangle inequality is applied to the infinite series.