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Answers for “如何将向量乘以标量?”

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The mathematician generalizes the concept to any object that supports sensible addition and scalar multiplication operations.

Conditions: Abstract linear algebra context

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Scalar multiplication preserves the relation because multiplying the equation x3=x1+x2x_3 = x_1 + x_2 by a scalar cc yields cx3=cx1+cx2cx_3 = cx_1 + cx_2. This shows that the third component of the scaled vector cxcx equals the sum of its first and second components.

Conditions: xx is a vector in the set satisfying x3=x1+x2x_3 = x_1 + x_2.; cc is a real scalar.; Scalar multiplication is defined componentwise.

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The length is multiplied by the absolute value of the scalar ∣c∣|c|. Specifically, 0<∣c∣<10 < |c| < 1 shortens the vector, ∣c∣>1|c| > 1 stretches it, and c=0c=0 yields the zero vector.

Conditions: Scalar multiplication operation; Considering magnitude/length changes

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To add vectors, you add their corresponding components. This means if you have two vectors, you sum the first component of each to get the first component of the result, and similarly for the second component.

Conditions: The vectors must have the same dimension (e.g., both are 2D or both are 3D).; The components are aligned by position (first with first, second with second).

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Multiplying a 3x3 matrix by a vector (x,y,z)(x, y, z) scales each column of the matrix (which represents a transformed basis vector) by the corresponding input coordinate and sums the results. This works because linear transformations preserve addition and scalar multiplication.

Conditions: Matrix is 3x3 representing a linear transformation; Input vector has coordinates (x,y,z)(x, y, z); Transformation is linear

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First, calculate the dot products y⋅u=20y \cdot u = 20 and u⋅u=5u \cdot u = 5. The scalar coefficient is 20/5=420/5 = 4.

Conditions: y=(7,6)y = (7,6); u=(2,1)u = (2,1)