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The boundary line is solid because the inequality includes equality. Since x can be less than or equal to -2, the points on the line $x = -2$ are part of the solution set.

Conditions: The inequality is non-strict (≤).; The boundary line is $x = -2$.

The boundary line is solid because the inequality includes equality. Since x can be less than or equal to -2, the points on the line $x = -2$ are part of the solution set.

Conditions: The inequality is non-strict (≤).; The boundary line is $x = -2$.

The region above $y = -4$ is shaded because the inequality $y > -4$ requires the y-coordinate to be greater than -4. On a standard coordinate plane, larger y-values are located above the horizontal line $y = -4$.

Conditions: The inequality restricts y.; The boundary is a horizontal line $y = -4$.

The region above $y = -4$ is shaded because the inequality $y > -4$ requires the y-coordinate to be greater than -4. On a standard coordinate plane, larger y-values are located above the horizontal line $y = -4$.

Conditions: The inequality restricts y.; The boundary is a horizontal line $y = -4$.

The boundary line is dashed because the inequality is strict. Since x is greater than 3 but not equal to 3, the points on the line $x = 3$ are excluded from the solution set.

Conditions: The inequality is strict (>).; The boundary line is $x = 3$.

The boundary line is dashed because the inequality is strict. Since x is greater than 3 but not equal to 3, the points on the line $x = 3$ are excluded from the solution set.

Conditions: The inequality is strict (>).; The boundary line is $x = 3$.