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Answers for “为什么最小的正线性组合 d 能被 a 和 b 整除?”

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The proof demonstrates this by showing that d is a linear combination of a and b. Since any common divisor divides both a and b, it must also divide any integer linear combination of them, including d.

Conditions: d is the least positive linear combination of a and b.; c is a common divisor of a and b.

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It contradicts minimality because the remainder can be expressed as a linear combination of a and b. If the remainder is positive and smaller than d, it belongs to the set of positive linear combinations, violating the definition of d as the smallest such value.

Conditions: d is defined as the least positive integer linear combination of a and b.; The remainder r is obtained by dividing a or b by d.; r is positive and r<dr < d.

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The well-ordering principle guarantees this by ensuring that any nonempty set of positive integers has a smallest element. Since the set of positive linear combinations is nonempty, it must contain a minimum value.

Conditions: Integers a and b are not both zero.; The set consists of positive values of the form au+bv where u and v are integers.