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Answers for “为什么欧几里得算法将旧的除数和余数移入下一行?”

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Understand why

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The Euclidean algorithm moves the old divisor to the left-hand side (new dividend) and the old remainder to the smaller-number position (new divisor) to recursively reduce the problem. This shift ensures that each subsequent division step operates on smaller numbers while preserving the greatest common divisor of the original pair, continuing until a remainder of zero is reached.

Conditions: The algorithm is applied to two positive integers.; The previous remainder is not zero.; The process continues until a remainder of 0 is obtained.

Find a method

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To start the Euclidean algorithm for gcd⁡(10,45)\gcd(10,45), you write the larger number as the smaller number multiplied by an unknown quotient plus an unknown remainder. Specifically, you set up the division equation 45=10⋅q+r45 = 10 \cdot q + r.

Conditions: The inputs are positive integers.; The larger number is placed on the left-hand side of the equation.; The quotient is an integer and the remainder satisfies 0≤r<100 \le r < 10.

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In the Euclidean algorithm, the previous divisor becomes the new dividend (placed on the left side of the equation), and the previous remainder becomes the new divisor (placed on the right side). This recursive shift carries the numbers forward so that each step divides the former divisor by the former remainder, continuing until a remainder of zero is reached.

Conditions: The algorithm is applied to positive integers.; The previous remainder is not zero.; The process follows the standard division-with-remainder format a=b⋅q+ra = b \cdot q + r.

Understand why

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Once the new remainder is 0, the division is exact, meaning the current divisor perfectly divides the previous dividend. The algorithm's termination rule states that the greatest common divisor of the original pair is the last nonzero remainder, which is the divisor of this final exact division.

Conditions: The Euclidean algorithm has been applied to two positive integers.; A division step has produced a remainder of 0.; The inputs are 10 and 45.

Meet the concept

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In the step 45=10⋅q+r45 = 10 \cdot q + r, qq represents the quotient, which counts how many whole times the smaller number (10) fits into the larger number (45). rr represents the remainder, which is the leftover amount after subtracting those whole multiples.

Conditions: The equation is part of the division-with-remainder step of the Euclidean algorithm.; The inputs are positive integers.; The remainder satisfies 0≤r<100 \le r < 10.