The greatest value of ∣Rn(s)∣ in the region Re(s)≥1+a is achieved at the boundary point s=(1+a)+0i. This is proven by chaining two inequalities: first, the triangle inequality bounds the complex modulus by the real tail, ∣Rn(σ+it)∣≤Rn(σ); second, the term-by-term comparison for real arguments shows that Rn(σ)≤Rn(1+a) when σ≥1+a.
Conditions: The region is the closed half-plane Re(s)≥1+a with a>0.; s=σ+it is a complex variable.; Rn(s)=∑k=n+1∞ks1 is the tail sum of the zeta series.
The greatest value of ∣Rn(s)∣ in the region Re(s)≥1+a is achieved at the boundary point s=(1+a)+0i. This is proven by chaining two inequalities: first, the triangle inequality bounds the complex modulus by the real tail, ∣Rn(σ+it)∣≤Rn(σ); second, the term-by-term comparison for real arguments shows that Rn(σ)≤Rn(1+a) when σ≥1+a.
Conditions: The region is the closed half-plane Re(s)≥1+a with a>0.; s=σ+it is a complex variable.; Rn(s)=∑k=n+1∞ks1 is the tail sum of the zeta series.
The lecture rewrites the tail sum Rn(s) by substituting s=σ+it, yielding terms of the form kσ1e−it(logk). It then applies the triangle inequality, which states that the absolute value of a sum is at most the sum of the absolute values.
Conditions: s=σ+it where σ>1.; Rn(s)=∑k=n+1∞ks1 is the tail of the zeta series.; The triangle inequality is applied to the infinite series.
The lecture rewrites the tail sum Rn(s) by substituting s=σ+it, yielding terms of the form kσ1e−it(logk). It then applies the triangle inequality, which states that the absolute value of a sum is at most the sum of the absolute values.
Conditions: s=σ+it where σ>1.; Rn(s)=∑k=n+1∞ks1 is the tail of the zeta series.; The triangle inequality is applied to the infinite series.