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Answers for “为什么 e^y 的存在使方程成为非线性的?”

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First, apply the quotient rule for exponents with the same base to rewrite e2x−ye^{2x-y} as e2x/eye^{2x}/e^y. Replace y' with dy/dxdy/dx to get dy/dx=e2x/eydy/dx = e^{2x}/e^y.

Conditions: The equation is a first-order differential equation.; The exponent rule am/an=am−na^m/a^n = a^{m-n} is applicable.