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Answers for “正则施图姆-刘维尔问题具有哪些谱性质?”

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Regular Sturm-Liouville problems have an infinite spectrum λn→∞\lambda_n \to \infty, and their eigenfunctions are orthogonal and total. Because they are orthogonal and total, they can form an orthonormal basis (ONB) after normalization.

Conditions: The Sturm-Liouville problem is regular (X=[a,b]X=[a,b] and p(x)≠0p(x) \neq 0 for all x∈Xx \in X).

Find a method

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Dirichlet boundary conditions correspond to setting the derivative coefficients to zero (α2=β2=0\alpha_2 = \beta_2 = 0), leaving conditions on the values of yy at the endpoints. Neumann boundary conditions correspond to setting the function coefficients to zero (α1=β1=0\alpha_1 = \beta_1 = 0), leaving conditions on the derivatives.

Conditions: The general boundary conditions are α1y(a)+α2y′(a)=0\alpha_1 y(a) + \alpha_2 y'(a) = 0 and β1y(b)+β2y′(b)=0\beta_1 y(b) + \beta_2 y'(b) = 0.; Dirichlet: α2=β2=0\alpha_2 = \beta_2 = 0.; Neumann: α1=β1=0\alpha_1 = \beta_1 = 0.

Meet the concept

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A Sturm-Liouville problem is regular exactly when its domain is the finite closed interval X=[a,b]X=[a,b] and the coefficient pp does not vanish anywhere on XX (p(x)≠0p(x) \neq 0 for all x∈Xx \in X). A problem is singular when either the domain XX is infinite/unbounded or the coefficient pp vanishes at some point x0x_0 in XX.

Conditions: Regular: X=[a,b]X=[a,b] and p(x)≠0p(x) \neq 0 for all x∈Xx \in X.; Singular: XX is infinite, or p(x0)=0p(x_0)=0 for some x0∈Xx_0 \in X.; For unbounded XX, boundary conditions are interpreted using limits.

Understand why

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Sturm-Liouville problems are the general class of boundary value problems that arise when the separation of variables technique is applied to a PDE or an initial-boundary value problem. They are also situated as part of the extension of the spectral theorem to infinite dimensions.

Conditions: The context is solving PDEs or initial-boundary value problems using separation of variables.