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Calculus / Chinese

Taylor series

Charles队长 · Bilibili · 0:30

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The explanation, unpacked.

Reviewed learning material · Video analysis · English
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An animation builds the Maclaurin approximations of eˣ from degree zero through degree four, with a close-up near the expansion point.

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Chapters

0:00The exponential series0:08Adding polynomial terms0:26Inspecting the local approximation

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

The exponential has all derivatives equal to itself. At zero each derivative equals one, so its Maclaurin coefficients are 1/n1/n!. The animation writes ex=∑n=0∞xn/n!e^x=\sum_{n=0}^{\infty}x^n/n! and compares finite partial sums with the original curve.

The constant approximation is S0(x)=1S_0(x)=1. Adding x gives the tangent line S1(x)=1+xS_1(x)=1+x. The quadratic, cubic and quartic terms successively match more derivatives at zero. Their local shapes improve even though their global shapes differ from the exponential.

The close-up makes the local approximation visible. For this function the series converges at every fixed real x, uniformly on each fixed bounded interval. This does not promise a uniformly small error over the entire real line or a strictly smaller error at every point after every added term.

Knowledge cards

01

The exponential Maclaurin series

The coefficients are derivatives at zero divided by factorials. All these derivatives equal one for the exponential. Smoothness alone does not guarantee that an arbitrary function equals its Taylor series.

ex=∑n=0∞xnn!=1+x+x22!+x33!+…e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots
02

Degree-zero approximation

The constant term matches the value at zero, but carries no slope information.

S0(x)=1S_0(x) = 1
03

The tangent approximation

The first two terms match both value and derivative at zero, giving the tangent line.

S1(x)=1+xS_1(x) = 1 + x
04

Adding a higher-order term

Each additional term matches another derivative at zero. Higher-degree polynomial behavior far from zero can still differ sharply from the exponential.

Sn(x)=Sn−1(x)+xnn!S_n(x) = S_{n-1}(x) + \frac{x^n}{n!}
05

Convergence and its limits

The exponential series converges pointwise on the real line and uniformly on each fixed bounded interval. Neither finite graphics nor pointwise convergence imply a uniform error bound on the whole real line.

lim⁡N→∞∣ex−SN(x)∣=0\lim_{N \to \infty} |e^x - S_N(x)| = 0

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  • Taylor series Explanation
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    An animation builds the Maclaurin approximations of eˣ from degree zero through degree four, with a close-up near the expansion point.

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