Custom binary operation
The video defines a special operation by the rule . The symbol here is not ordinary multiplication; it names a binary operation that takes two inputs and returns one output.
MrMathsTeacher · YouTube · 4:45
This introductory algebra whiteboard clip defines a custom binary operation by the rule and demonstrates how to evaluate expressions with it. The instructor first computes by substituting and , obtaining . The lesson then moves to the nested expression , explaining that the inner bracket is replaced by the previously found value so the problem becomes . The same rule is applied again with and , yielding the setup . The clip stops before the final arithmetic for part (ii) is completed. This 135-second whiteboard segment continues a lesson on a custom binary operation defined by . The visible board already contains part (i), . In this clip, the presenter completes part (ii), ()*4, by first replacing with -7 and then evaluating (-7)*. Next, the presenter solves part (iii), (-8)*(), by reusing the earlier result , rewriting the expression as (-8)*(-7), and applying the definition again to get . The main teaching points are direct substitution into the rule, careful identification of the first operand as a and the second as b, and evaluating inner parentheses before outer operations.
Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.
Generated from the video's visuals and explanation; not verbatim speech.
The lesson begins with a handwritten rule on the board: . The speaker identifies this as a binary operation, meaning it acts on two inputs and produces one output.
For part (i), the expression to evaluate is . The instructor rewrites the general rule and prepares to substitute the specific numbers into the positions of and .
The substitution is made explicit: the first number, , is assigned to , and the second number, , is assigned to . This gives .
The arithmetic is then expanded step by step. The square is written as , producing , and then simplified to .
Part (ii) introduces the nested expression . Before continuing, the speaker reminds the viewer that a binary operation must be applied to two quantities at a time.
Since the inner bracket has already been evaluated as , the whole expression is reduced by replacing that bracket with , turning into .
The same defining rule is applied again, now with and . This yields the setup .
The clip ends after this substitution step; the final simplification of is not shown within the provided segment.
The clip opens with the definition still visible at the top left: If , evaluate (i) , (ii) ()*4, and (iii) (-8)*(). Part (i) has already been solved on the board as .
On the right side, the worked solution for part (ii) is being completed. Since , the expression ()*4 is rewritten as (-7)*4.
Applying the rule with and gives . The presenter computes and , so the line becomes -14 - 16.
Combining the two negative terms yields -30, and this value is written as the final answer for part (ii) on the left column.
The presenter then moves to part (iii), (-8)*(). The key step is to simplify the bracketed expression first.
Because part (i) already showed that , the term () is replaced by -7, turning the whole expression into (-8)*(-7).
Before substituting, the presenter explicitly identifies the roles of the operands: the first number is a and the second number is b. This reinforces that the custom operation is order-sensitive.
Now apply the definition again with and . This gives .
The arithmetic is expanded step by step: , and (-7)^. Therefore the expression becomes -16 - 49.
Adding the two negative quantities gives -65, which is stated as the final answer for part (iii) and then written on the left side of the board.
By the end of the segment, all three answers are visible together: (i) -7, (ii) -30, and (iii) -65. The lesson closes by summarizing that these are the required evaluations.
The video defines a special operation by the rule . The symbol here is not ordinary multiplication; it names a binary operation that takes two inputs and returns one output.
To compute , substitute and into the rule. This gives . The worked example shows both the substitution step and the arithmetic simplification.
When moving to , the speaker explains that a binary operation must be handled with two numbers at a time. Therefore the nested expression is first reduced so that the outer operation also has exactly two inputs.
Because part (i) already showed , the bracketed term in can be replaced by . The problem then becomes the simpler binary operation .
Apply the same rule again with the new inputs and . The expression becomes . The clip stops at this setup and does not show the final numerical answer.
The video defines a nonstandard operation using the symbol *. For any input pair, the first entry is substituted for a and the second entry for b in the formula . This rule is then used to evaluate all three examples.
To evaluate an expression under the given rule, identify x as the first operand and y as the second operand, then compute . The presenter stresses this order repeatedly, especially in part (iii).
When a custom operation appears inside parentheses, simplify the inner expression first and substitute its numerical result into the outer operation. This is shown when ()*4 becomes (-7)*4 and when (-8)*() becomes (-8)*(-7).
Using the earlier result , rewrite ()*4 as (-7)*4. Then apply the definition: .
First replace by -7, giving (-8)*(-7). Then apply the rule with and : .
Unlike ordinary multiplication, this custom operation is not symmetric. Swapping the two inputs changes the result because a is doubled while b is squared and subtracted. The red labels a and b on the board are used to prevent this mistake.
Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.
The left side of the given rule is written as .
The speaker says, "We are given a binary operation a star b".
a
First input to the binary operation *; in part (i) it is 1, and in part (ii) it is replaced by -7.
numeric inputs used in the examples
The left side of the given rule is written as .
The speaker says, "b is equal to 3" for part (i), and later "b is now 4" for part (ii).
b
Second input to the binary operation *; in part (i) it is 3, and in part (ii) it is 4.
numeric inputs used in the examples
The board shows the custom operation symbol between a and b as *.
The speaker calls it "a binary operation" and reads expressions such as "one star three".
*
Custom binary operation symbol defined by the rule on the board; not ordinary multiplication.
binary operation on two numbers
The worked line ends with = -7.
The speaker says, "which is negative seven".
-7
Value of from part (i), then reused as the first input in part (ii).
integer result of the example computation
The board shows the definition , and the presenter repeatedly identifies the first number as a.
At 01:04-01:10 the speaker says, "Once again the first number is a."
a
First operand of the custom binary operation *.
Real numbers in the worked examples; the video does not state a formal domain.
The board shows the definition , and the presenter repeatedly identifies the second number as b.
At 01:04-01:10 the speaker says, "and the second number is b."
b
Second operand of the custom binary operation *.
Real numbers in the worked examples; the video does not state a formal domain.
The title line on the left reads "If " and all three parts use the symbol * between two quantities.
Throughout the clip the speaker verbally calls it "star" while evaluating expressions such as , (-7)*4, and (-8)*(-7).
*
A custom binary operation defined by , not ordinary multiplication.
Applied to pairs of numbers appearing in the examples.
Left side shows (i) ; right side shows .
The value of the custom operation with and .
Numeric expression evaluated in part (i).
Left side shows (ii) ()*; right side shows (-7)*.
()*4
Nested application of the custom operation: first compute , then operate the result with 4.
Numeric expression evaluated in part (ii).
Left side shows (iii) (-8)*(); right side rewrites it as (-8)*(-7) and evaluates to -65.
At 01:54-01:58 the speaker says, "What is our final answer? Our final answer will be negative sixty five."
(-8)*()
Nested application of the custom operation: first replace by -7, then compute (-8)*(-7).
Numeric expression evaluated in part (iii).
The speaker says, "We are given a binary operation a star b is equal to 2 multiplied by a minus b to the power 2."
The board displays If .
The video defines a custom binary operation by the rule . The speaker explicitly identifies this as a binary operation, meaning it takes two inputs and returns one output. In the examples, the first input is substituted for and the second input for .
The operation is applied to two inputs.
In the shown examples the inputs are numbers.
The speaker says, "We are using this binary operation as our guide and we will substitute values of a and b."
Red arrows are drawn from the symbolic rule to the numeric inputs in part (i), and later labels and are written above the numbers in part (ii).
To evaluate an expression involving , the video rewrites the defining rule and substitutes the specific numbers for and . This is demonstrated first with , where and , and then again with , where and .
Use the same defining rule each time the operation is evaluated.
Identify which number occupies the first-input position and which occupies the second-input position.
The speaker says, "But if you look at part one we worked out one star three already and we got negative seven. So we are replacing the bracket term one star three by negative seven star four."
Part (ii) on the left is , and the worked solution begins by rewriting it as .
For , the video first evaluates the inner bracket to get , then replaces the bracketed subexpression by that value and continues with . This shows how a nested custom operation is reduced step by step to a single binary operation.
Evaluate the innermost bracket first.
Replace the completed subexpression by its numerical result before applying the outer operation.
The persistent board heading reads "If evaluate".
The whole clip consists of applying this rule to three expressions.
The video introduces a nonstandard binary operation denoted by * and defines it by the rule . In each example, the first entry of the pair is substituted for a and the second entry for b. The operation is then evaluated arithmetically.
The symbol * is a defined operation, not ordinary multiplication.
For an expression , substitute x for a and y for b.
The examples use integer inputs.
Each worked line replaces a and b directly: becomes , (-7)*4 becomes , and (-8)*(-7) becomes .
At 01:04-01:10 the speaker explicitly states that the first number is a and the second number is b.
To evaluate any expression using this custom operation, identify the left argument as a and the right argument as b, then substitute them into . The video demonstrates this same method in all three parts.
Order matters: the left operand is a and the right operand is b.
Parentheses are used when substituting negative numbers.
Part (ii) uses the earlier result before computing (-7)*4.
Part (iii) rewrites (-8)*() as (-8)*(-7) before applying the rule again.
At 00:44-00:53 the speaker says, "If we go back to our answer for part one, we got negative seven for one star three. So we are replacing the bracketed term by negative seven."
When the custom operation appears inside parentheses, the inner expression must be evaluated first and its numerical result substituted into the outer operation. The clip shows this in both (ii) and (iii).
A bracketed subexpression containing * must be simplified before the outer * is applied.
Previously computed results may be reused.
The speaker says, "we want to work with two numbers because we are using a binary operation and binary implies two of something."
A binary operation works with two inputs.
The operation under discussion is called binary.
For the operation being used in this lesson.
The right side shows (i) , then , then = 2 x 1 - 3 x 3, then = .
The speaker says, "So 1 star 3 will be equal to ... a is equal to 1 and b is equal to 3 ... 2 times 1 minus 3 squared ... which gives 2 take away 9 which is negative 7."
Start from the defining rule for the custom operation.
Given definition on the board.
Substitute and into the rule.
Direct substitution into the definition.
Expand the square as .
Arithmetic expansion of exponent notation.
Compute the products and subtract.
Standard integer arithmetic.
The value of is .
The left side lists (ii) ; the worked line on the right begins with (ii) -7*.
The speaker says, "we are replacing the bracket term one star three by negative seven star four" and then "instead of 2a, we can see that a is now negative seven and b is now four."
The final numerical answer for part (ii) is not reached within the provided clip.
Begin with the nested expression from part (ii).
Problem statement on the board.
Replace the inner bracket by its previously computed value .
Use the result from part (i).
Apply the same defining rule with and .
Substitution into .
Within this clip, is reduced to and rewritten as ; the final simplification is not shown.
Right side shows (-7)*.
From 00:00-00:22 the speaker narrates the arithmetic: 2 times negative 7, subtract 4 times 4, giving negative 14 minus 16 equals negative 30.
Use the already established result from part (i) as the inner value.
Prior worked example shown on the board.
Replace the bracketed term by -7.
Substitution of a previously computed value.
Apply the definition with and .
Definition of the custom operation.
Compute and .
Arithmetic evaluation.
Combine the two negative terms.
Addition of signed numbers.
()*.
Right side shows (-8)*(-7) = .
From 00:39-01:58 the speaker explains replacing by -7, then substituting into the rule and obtaining negative sixty five.
Recall the result from part (i).
Previously computed value on the board.
Replace the bracketed expression by -7.
Substitution using the inner result.
Apply the definition with and .
Definition of the custom operation.
Compute and (-7)^.
Arithmetic evaluation, including squaring a negative number.
Combine the two negative terms.
Addition of signed numbers.
(-8)*() = -65.
Left side lists (i) ; right side solves it to -7.
The speaker says, "We are asked to evaluate 1 star 3" and concludes, "which is negative 7".
Evaluate using the rule .
First input is 1
Second input is 3
Find the numerical value of .
Substitute and into the definition.
Definition of the custom binary operation.
Rewrite the square as repeated multiplication.
Arithmetic notation.
Evaluate the products and subtract.
Integer arithmetic.
-7
The board and narration both state the final result as negative seven.
Left side lists (ii) ()*4; right side rewrites it as -7*.
The speaker says, "we are replacing the bracket term one star three by negative seven star four" and then substitutes , .
The clip stops before the arithmetic is completed, so the final value of part (ii) is not visible or audible here.
Evaluate using the same rule, after first finding .
From part (i),
Outer second input is 4
Reduce to a single application of the operation and substitute into the rule.
Start from the nested expression.
Problem statement on the board.
Replace the inner bracket by the result from part (i).
Substitution of a previously computed value.
Apply the defining rule with and .
Direct substitution into .
The setup shown in the clip is ; the final simplified value is not reached within this segment.
The visible work confirms the reduction and substitution, but no concluding arithmetic is shown before the clip ends.
Left side lists (i) ; right side shows .
Using , evaluate .
Definition:
Expression:
Find the numerical value of .
Substitute and into the definition.
Direct application of the custom operation rule.
Evaluate the product and the square.
Basic arithmetic.
Subtract to obtain the final value.
Arithmetic simplification.
-7
The board writes the final result as -7 beside part (i).
Left side lists (ii) ()*; right side shows (-7)*.
Using , evaluate ()*4.
Definition:
From part (i),
Expression: ()*4
Find the numerical value of ()*4.
Replace the inner bracketed term by its known value -7.
Substitution of a previously computed result.
Apply the definition with and .
Custom operation rule.
Compute the product and the square.
Arithmetic evaluation.
Combine the terms.
Signed-number addition.
-30
The board writes the final result as -30 beside part (ii).
Left side lists (iii) (-8)*(); right side rewrites it as (-8)*(-7) and evaluates to -65.
At 01:54-01:58 the speaker states the final answer is negative sixty five.
Using , evaluate (-8)*().
Definition:
From part (i),
Expression: (-8)*()
Find the numerical value of (-8)*().
Replace the bracketed term by -7.
Use the result from part (i).
Apply the definition with and .
Custom operation rule.
Compute and (-7)^2.
Arithmetic, including squaring a negative number.
Combine the two negative terms.
Signed-number addition.
-65
The board writes the final result as -65 beside part (iii).
The whiteboard is split by a vertical line, with the problem statement on the left and worked solutions on the right.
left problem column
right solution column
vertical divider line
The right column gains handwritten solution steps over time while the left column remains the problem list.
The defining rule and the three listed parts stay visible on the left throughout the clip.
The layout separates the given task from the step-by-step working, making the substitution process easier to follow.
Red arrows are drawn from the symbolic rule toward the numbers in while the speaker identifies and .
rule
expression
red arrows
Arrows appear to connect the abstract variables to the concrete numbers.
The underlying formula remains unchanged.
The visual annotation emphasizes positional substitution: the first number corresponds to and the second to .
The letters and are written above the numbers in during the explanation of part (ii).
expression
labels and
The previously solved inner result becomes the new first input, and the labels are placed above the numbers.
The same defining rule is still being applied.
This visual step shows that after reducing the bracket, the outer expression is again just a binary operation with a first and second input.
The whiteboard is split by a vertical black line: the left side lists the problem statement and final answers for (i), (ii), and (iii), while the right side shows the step-by-step working.
Left column with problem statement and answers
Right column with worked solutions
Vertical divider line
As the clip progresses, the right column gains the detailed computations for parts (ii) and (iii).
The left column is completed with the final answers -30 and -65.
The definition remains visible at the top throughout.
The three requested expressions remain listed on the left throughout.
The layout separates the task statement from the solution process, making the substitution steps easy to track.
Red handwritten labels a and b appear above operands in the worked examples, including the line for (-8)*(-7).
Red letter a
Red letter b
Blue worked expressions
The labels are used to indicate which number plays the role of a and which plays the role of b in each application of the rule.
The first position is consistently marked as a and the second as b.
The color coding visually reinforces the substitution rule and the importance of order.
The board uses inside the custom rule , while ordinary multiplication is written separately as and in the worked lines.
Because the symbol appears, a learner may treat as standard multiplication.
Here names a special binary operation defined by the formula ; ordinary multiplication is handled separately in the arithmetic steps.
The speaker stresses that a binary operation uses two numbers and then identifies which number is and which is in each example.
Part (ii) treats as the first input and as the second input in .
One might think the two numbers can be inserted into the formula in either order.
The video consistently assigns the left operand to and the right operand to , so means and , not the reverse.
At 01:04-01:10 the speaker emphasizes, "Once again the first number is a and the second number is b."
Red labels a and b are written over the first and second operands in the worked lines.
One might treat like ordinary multiplication and think the order of the two inputs does not matter.
The video explicitly tracks the first number as a and the second as b, because the rule depends on their positions.
At 00:44-00:53 the speaker says they go back to part one and replace the bracketed term by negative seven before continuing.
Part (iii) is rewritten as (-8)*(-7) before applying the definition again.
One might try to apply the definition directly to (-8)*() without simplifying the parenthesis first.
The worked solution first computes and only then evaluates (-8)*(-7).
After stating the rule, the speaker says they will substitute values of and .
The worked line directly transforms into .
The substitution method is the practical way to apply the defined binary operation to concrete inputs.
The speaker explains that because was already worked out, the bracket term can be replaced by before continuing.
The solution rewrites as and then applies the rule again.
Nested evaluation depends on first using substitution on the inner expression, then substituting that result into the outer expression.
The speaker says, "binary implies two of something" while discussing why the expression must be handled as two numbers.
The claim about binary operations supports why the rule is applied to an ordered pair of inputs in each example.
Every worked line begins by turning an expression into .
The substitution method is the direct procedural use of the defined operation .
Parts (ii) and (iii) both require an inner result before the outer substitution can be made.
Nested evaluation relies on first knowing how to substitute values into the operation rule.
Part (ii) uses the value -7 obtained in part (i) as the new left operand.
The computation of ()*4 depends on the earlier result .
Part (iii) rewrites (-8)*() as (-8)*(-7) using the result from part (i).
The computation of (-8)*() also depends on the previously found value .
Opening narration states the given binary operation and formula.
Board shows If .
Worked solution for part (i) ends at -7.
Speaker narrates the substitution and arithmetic for .
Speaker explains replacing the bracket term by in .
Right side shows .
The speaker says binary implies two of something.
The custom rule uses while ordinary multiplication is written with in the arithmetic lines.
The board heading states "If ".
The speaker says the first number is a and the second number is b.
The speaker replaces the bracketed term by -7 before continuing.
The board shows (ii) ()* with the full derivation on the right.
The board shows (-8)*(-7) = .
Covered · The clip opens with the written rule and spoken identification of the binary operation.
Covered · Part (i) is solved by substitution and arithmetic to obtain -7.
Covered · Part (ii) is introduced, the inner result is reused, and the outer expression is rewritten as ; the clip ends before final simplification.
Covered · The board already shows part (i) completed as -7, and the clip finishes the arithmetic for part (ii), reaching -30.
Covered · The presenter writes the final answer -30 for part (ii) on the left and transitions toward part (iii).
Covered · Part (iii) is explained by reusing , rewriting (-8)*() as (-8)*(-7), substituting into the rule, and computing -65.
Covered · The final answer -65 is written on the left, and the presenter closes by saying these are the answers.
Reviewed English material v5: card "Custom binary operation" at 0:00 — The video defines a special operation by the rule . The symbol here is not ordinary multiplication; it names a binary operation that takes two inputs and returns one output.