Sal Khan turns tangent slopes into a picture of the derivative of 2x³, then uses the graph 6x² to estimate slopes at other inputs. Includes original bilingual notes, chapters and editorial mathematical checks.
Reviewed learning material · Video analysis · English
Start with a curve, then ask how steep it is at each point. Sal Khan demonstrates this idea using f(x)=2x^3: seven orange controls encode tangent-slope estimates, and the revealed derivative graph is 6x^2. The slopes decrease toward the origin, reach 0, and then increase again. Reading the derivative graph also gives estimates at inputs outside the original sample set, including x=-0.5 and x≈-2.25. The lesson builds graphical intuition rather than proving the power rule. This page supplies original bilingual notes and clearly marked mathematical checks. The video demonstrates a historical interactive module; access to that original exercise is not guaranteed.
Before you watch
Cartesian graphs and function inputs
Slope of a line
Tangent direction at a point
Basic polynomial evaluation
Optional follow-up: the power rule for differentiation
Generated from the video's visuals and explanation; not verbatim speech.
The clip opens on an interactive calculus module built around a single question: how can one *see* what a derivative is? Visually, the screen already contains the essential data—a blue graph labeled f(x)=2x^3, seven movable control points, and a right-hand answer table listing quantities such as \frac{d}{dx}f(-2), \frac{d}{dx}f(-1.5), and so on. At this stage nothing deep has been computed yet; the purpose is orientation to the task.
The narrator then supplies the key definition driving the whole exercise: the derivative at a point is the slope of the tangent line there. This matters because the interface is not asking for secant slopes or average rates; it asks the viewer to infer instantaneous steepness from the local geometry of the curve. With that definition in hand, the problem narrows to a concrete operation—match each orange control to the tangent direction of the cubic at its designated x-value.
The demonstration proceeds point by point. First, attention shifts to x=-2. Initially the associated line is effectively flat, giving \frac{d}{dx}f(-2)=0, but that cannot be correct because the cubic is clearly steep there. By dragging the control upward, the line rotates until it matches the curve’s local direction. As this happens, the answer box updates numerically, turning the geometric act of aligning a line into a quantitative estimate of slope.
While working at x=-2, the notation itself becomes important. The expression \frac{d}{dx}f(-2) names the derivative evaluated at the input -2. The speaker’s phrasing briefly blurs input versus output, but the mathematical object on screen is clear: it is the tangent slope of f at the point whose x-coordinate is -2. Once the line is judged close enough to tangent, the accepted estimate is about 24, establishing the largest early positive value in the sequence.
The next two left-side samples continue the same logic with smaller magnitudes. Moving inward from -2 to -1.5 and then -1, the cubic remains increasing but becomes less steep. Accordingly, the newly adjusted tangent lines rotate downward relative to the previous ones, and the answer entries fall to roughly 13.5 and then about 6. These are not arbitrary guesses; they encode the observable fact that the curve’s instantaneous rate of rise diminishes as x approaches 0 from the left.
At x=0 the pattern reaches its critical transition. Here the best-fit tangent is horizontal, so \frac{d}{dx}f(0)=0. The narrator explicitly recognizes this as an inflection point, which teaches something subtler than mere calculation: a zero derivative does not have to signal a local maximum or minimum. On the graph of 2x^3, the curve passes smoothly through the origin while momentarily flattening, making the horizontal tangent compatible with ongoing upward motion on either side.
Crossing to positive x reverses the earlier monotonic trend in the slope estimates. At x=1, the tangent must tilt upward more strongly than at 0, yielding about 6. At x=1.5 the steepness grows further to around 13.5, and at x=2 it returns to about 24. The symmetry of these numbers is visually meaningful: because the original cubic is odd, its derivative behaves evenly, so paired inputs ±a receive nearly identical slope estimates.
By the end, the seven separately tuned points stop looking isolated. Their heights form a recognizable bowl-shaped profile above the x-axis, touching zero only at the origin. When the estimates are close enough, the software completes the conceptual jump from discrete samples to a continuous model: it draws a yellow curve through the points and labels it \frac{d}{dx}f(x)=6x^2. Thus the lesson closes by converting a tactile eyeballing exercise into an explicit formula for the derivative of the displayed cubic.
The clip opens on a completed Khan Academy derivative-intuition page. At top left the lesson identifies the function as f(x)=2x^3 and immediately displays its derivative as d/dx f(x)=6x^2. In the middle is a coordinate plane with the blue cubic curve, an orange parabolic curve, and short gray tangent-style marks; on the right is an Answer panel listing seven computed slopes. The narrator recaps the prior interaction: the learner had been asked to drag seven orange points up and down so that the associated tangent lines matched the local slopes of the blue curve.
He then explains the key conceptual upgrade. Because the seven guessed sample slopes were close enough to the true ones, the system responded by drawing the entire derivative curve rather than leaving only isolated checkpoints. From that moment forward, the orange graph should be understood as a continuous slope function: at any x in the displayed window, the vertical position of the orange curve gives the slope of the tangent line to f(x)=2x^3 at that same x.
Editorial numerical check: To illustrate this, the narrator chooses a point that was not one of the seven adjusted markers, namely x=-0.5. Looking upward to the orange derivative curve there, he visually estimates a value somewhat larger than 1. Using the displayed formula, this corresponds exactly to 6(-0.5)^2=1.5, confirming that his eyeballed reading is consistent with the analytic derivative.
Editorial numerical check: Next he considers a farther-out point, roughly x=-2.25. Again he reads the orange curve visually and says the slope appears to be about 30. Substituting into the formula gives 6(-2.25)^2=30.375, so the spoken approximation aligns well with the mathematical value. These examples show why the full derivative graph matters: it extends slope information smoothly across the whole interval, not just at the preselected sample abscissas.
The closing message is therefore that once the derivative curve is available, one possesses the slope of the tangent line—or equivalently the instantaneous rate of change of the original function—at every visible point. The exercise thus bridges concrete graphical fitting at a few points with abstract understanding of the derivative as a global function.
Knowledge cards
01
Derivatives
At a differentiable point, the derivative is the finite slope of the tangent line. The video turns that idea into a visual task: align a line with the curve locally, then read its slope as the derivative value. Editorial clarification: the existence of a tangent alone is insufficient if its slope is vertical; a finite derivative must exist.
f′(c)=slope of tangent line at x=c
02
Interpreting \frac{d}{dx}f(-2)
Expressions like \frac{d}{dx}f(-2) ask for the derivative at the input x=-2, not at a point where the output equals -2. In the interface, this quantity is represented by the vertical position of the control associated with x=-2 and by the live-updating entry in the answer column.
dxdf(x)x=−2
03
Graphical method for estimating derivatives
The procedure shown is: fix a sample x-value on the curve, drag the linked orange point until the attached line appears tangent, then read the resulting slope estimate from the answer panel. Repeating this across several inputs builds a scatter plot of derivative values that can suggest the full derivative graph.
04
Zero slope at the inflection point of 2x^3
At x=0, the tangent line to f(x)=2x^3 is horizontal, so the derivative is 0. The narrator identifies this as an inflection point, illustrating that a zero derivative can occur without a local extremum when concavity changes sign.
dxd(2x3)x=0=0
05
Symmetric derivative estimates around the origin
The accepted sample values progress approximately as 24, 13.5, 6, 0, 6, 13.5, 24 for x=-2,-1.5,-1,0,1,1.5,2. This symmetry reflects that the derivative of the odd function 2x^3 is an even function: opposite inputs give the same slope estimate.
f′(−a)=f′(a) for the sampled pairs shown
06
Derivative formula revealed for the example
Once the seven slope estimates are close enough, the software draws the derivative curve and labels it explicitly. For the displayed cubic, the final identified derivative is the quadratic function 6x^2, which matches the sampled values and the parabolic shape formed by the control points.
dxd(2x3)=6x2
07
Derivative as tangent-line slope
The graph supplies a tangent slope at each input. For this polynomial the derivative exists at every real input. Editorial clarification: ordinary derivatives are finite limits; a vertical tangent does not alone imply a finite derivative.
derivative at x0=slope of tangent line to f at x0
08
Displayed derivative of f(x)=2x^3
The formula displayed in the video is d/dx f(x)=6x^2 for f(x)=2x^3. The lesson reveals this result visually; it does not prove the general power rule.
f(x)=2x3,dxdf(x)=6x2
09
Seven checked derivative values
The selected inputs are -2, -1.5, -1, 0, 1, 1.5, and 2. The corresponding derivative values form a symmetric pattern because 6x^2 is even. Substitution into 6x^2 checks every displayed value.
The seven controls record separate slope estimates. The program then reveals its known derivative curve, allowing a viewer to read slopes at other inputs as well. Editorial clarification: finitely many sample points alone do not uniquely determine an arbitrary derivative function.
11
Visual estimation at x=-0.5
At x=-0.5 the narrator estimates a slope slightly above 1. Editorial numerical check: 6(-0.5)^2=1.5, consistent with that graphical estimate.
dxdf(−0.5)=6(−0.5)2=1.5
12
Visual estimation at x≈-2.25
Near x=-2.25 the spoken estimate is approximately 30. Editorial numerical check: 6(-2.25)^2=30.375, consistent with the rough graph reading.
dxdf(−2.25)=6(−2.25)2=30.375
Detailed learning notes
Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.
Symbols · 9
f(x)=2x^3
Clear evidence
Shown in the video
Evidence
Formula
Observation
Top-left text reads f(x) = 2x^3.
Symbol
f(x)=2x^3
Meaning
The cubic function graphed in blue on the coordinate plane.
Domain
All real x shown in the interactive window; no explicit domain restriction is stated.
\frac{d}{dx} f(a)
Clear evidence
Shown in the video
Evidence
Audio
Observation
The speaker discusses the entry for f(-2), while using wording that briefly mixes a function input with its output.
Formula
Observation
Answer panel shows \frac{d}{dx} f(-2).
Uncertainties
The spoken wording mixes output and input; the graph and answer panel identify the intended input x=-2.
Need to verify whether this is only a spoken imprecision rather than an intended mathematical claim.
Symbol
\frac{d}{dx} f(a)
Meaning
Derivative value of f at input a; visually represented by adjusting the orange point that sets the slope of the tangent line at x=a.
Domain
Used here for specific sample inputs such as a=-2,-1.5,-1,0,1,1.5,2.
answer entries \frac{d}{dx} f(c)
Approximate timing
Shown in the video
Evidence
Formula
Observation
Right-side answer list updates numerically as points are dragged: examples include \frac{d}{dx} f(-2)=24, \frac{d}{dx} f(0)=0, \frac{d}{dx} f(1)=6, \frac{d}{dx} f(1.5)=13.5, \frac{d}{dx} f(2)=24.
Animation
Observation
Values change continuously during dragging before settling near these numbers.
Uncertainties
Intermediate values around -1.5 and -1 fluctuate slightly while being eyeballed.
Some late frames show small deviations from exact multiples before final stabilization.
Symbol
answer entries \frac{d}{dx} f(c)
Meaning
Current estimated slopes assigned to each draggable point.
Domain
Seven selected x-values used by the exercise interface.
\frac{d}{dx} f(x)=6x^2
Clear evidence
Shown in the video
Evidence
Formula
Observation
Near the end, top area displays \frac{d}{dx} f(x) = 6x^2 alongside f(x)=2x^3.
Diagram
Observation
A yellow curve appears through the adjusted orange points.
Symbol
\frac{d}{dx} f(x)=6x^2
Meaning
Formula for the derivative function whose graph passes through the seven estimated tangent-slope points.
Domain
Displayed after enough accuracy has been reached in the interactive module.
f(x)
Clear evidence
Shown in the video
Evidence
Formula
Observation
Top-left text shows f(x) = 2x^3.
Symbol
f(x)
Meaning
The original cubic function whose graph is shown in blue.
Domain
Real x; displayed approximately on [-2.5, 2.5].
\frac{d}{dx} f(x)
Clear evidence
Shown in the video
Evidence
Formula
Observation
Top-left text shows d/dx f(x) = 6x^2.
Audio
Observation
Narrator says the orange dots were close enough to the actual derivative and that the whole curve represents the slope of the tangent line at any point.
Symbol
\frac{d}{dx} f(x)
Meaning
Derivative function of f, interpreted as the slope of the tangent line to f at each x-value.
Domain
Real x; displayed as an upward-opening parabola through (0,0).
x
Clear evidence
Shown in the video
Evidence
Diagram
Observation
Horizontal axis is labeled with values including -2.5, -2, -1.5, -1, -0.5, 0.5, 1, 1.5, 2, 2.5.
Symbol
x
Meaning
Input variable or horizontal coordinate used both for points on f and for evaluating derivative slopes.
The narrator verbally references a value around 2.5 while discussing x=-0.5, but it is unclear whether he means a y-level near 1.5 on the graph or another nearby gridline.
Symbol
y
Meaning
Output scale shared visually by the plotted curves and derivative values.
Seven selected input points where the exercise asks for tangent-line slopes / derivative values.
Knowledge points · 6
Definition of derivative via tangent-line slope
Clear evidence
Supplementary explanation
Evidence
Audio
Observation
The narration introduces the derivative through the local slope of a tangent line.
Formula
Observation
Instruction text states that the derivative of a function is defined as the slope of a line tangent to the curve at each point.
Definition
Explanation
The clip defines the derivative conceptually as the slope of the tangent line to the graph at a given point. This is presented as an intuitive definition tied directly to the graphical activity rather than through limits or algebraic rules.
Conditions
Editorial mathematical condition: the ordinary derivative requires a finite, existing limit of the difference quotient (equivalently a finite tangent slope at a differentiable point); a vertical tangent alone does not give a finite derivative.
Here demonstrated on the smooth polynomial curve f(x)=2x^3.
Derivative formula for f(x)=2x^3
Clear evidence
Shown in the video
Evidence
Formula
Observation
Top display changes to \frac{d}{dx} f(x)=6x^2 for f(x)=2x^3.
Diagram
Observation
Yellow parabola-like curve is drawn matching those derivative values.
Uncertainties
The video reveals the result but does not verbally derive the power rule step-by-step within this excerpt.
Formula
Explanation
For the displayed function f(x)=2x^3, the derivative is shown as 6x^2. The clip uses this as the target relationship between the original curve and the plotted slope estimates.
Conditions
Specific to f(x)=2x^3 in this example.
No proof of the general power rule is provided in the segment.
Prerequisites
Definition of derivative via tangent-line slope
Estimating derivatives by adjusting tangent lines
Clear evidence
Shown in the video
Evidence
Audio
Observation
Speaker explains moving orange dots up and down until they match the tangent-line slope.
Animation
Observation
Dragging each dot rotates its corresponding straight line toward tangency and updates numeric derivative estimates.
Formula
Observation
The interface asks the learner to drag 7 orange controls vertically to tune the associated tangent slopes.
Method
Explanation
The method demonstrated is purely visual: choose a point x=c on the curve, drag the associated control point until the attached line looks tangent, then read off the corresponding number \frac{d}{dx} f(c). Repeating this for several c produces discrete samples of the derivative function.
Conditions
Requires a visible graph with identifiable local steepness.
Accuracy depends on eye estimation unless checked against known formulas.
Prerequisites
Definition of derivative via tangent-line slope
Definition used in this module: derivative equals tangent-line slope
Clear evidence
Shown in the video
Evidence
Caption evidence
Observation
The on-screen explanation links each derivative value with the slope of a tangent at the same input.
Audio
Observation
Narrator explains that once you have the entire derivative curve, at any point this gives the slope of the tangent line.
Definition
Explanation
This clip uses the geometric definition of the derivative: for a differentiable function, the derivative at a point is the slope of the tangent line to the graph at that point. The interactive task reinforces this by asking the user to adjust lines so their slopes match the true local slopes of f(x)=2x^3.
Conditions
Applies when the tangent line exists at the point being considered.
Used here for polynomial functions over real inputs.
Narrator refers to having found the derivative at every point after matching the special points closely enough.
Uncertainties
The video displays the final formula directly rather than deriving it step-by-step within this excerpt.
Formula
Explanation
For the given function f(x)=2x^3, the derivative is shown as 6x^2. This matches the standard power-rule pattern for monomials: multiply by the exponent and reduce the exponent by one.
Conditions
Valid for f(x)=2x^3 on all real x.
Prerequisites
Definition used in this module: derivative equals tangent-line slope
Reading the full derivative curve as a slope function
Clear evidence
Shown in the video
Evidence
Audio
Observation
The narrator interprets the newly revealed graph as providing tangent slopes across the displayed interval.
Diagram
Observation
Orange parabola remains visible across the plot while narrator reads off approximate heights corresponding to slopes.
Method
Explanation
After only seven sample points are adjusted correctly, the interface reveals the complete derivative curve. The method then shifts from discrete guessing to continuous reading: pick any x on the domain, look vertically to the derivative graph, and interpret that height as the tangent slope of f at that same x.
Conditions
Requires recognizing that the vertical position of the derivative graph encodes slope, not just function output of f itself.
Prerequisites
Definition used in this module: derivative equals tangent-line slope
Claims and conditions · 4
Claim about the behavior at x=0
Clear evidence
Shown in the video
Evidence
Audio
Observation
At the origin the narrator identifies a horizontal tangent and describes the point as an inflection point.
Formula
Observation
Answer entry settles at \frac{d}{dx} f(0)=0.
Diagram
Observation
At x=0 the adjusted line becomes horizontal along the origin region.
Proposition
Statement
For the graphed function f(x)=2x^3, the speaker asserts that at x=0 the tangent slope is 0 and identifies the location as an inflection point.
Hypotheses
The function under discussion is the displayed f(x)=2x^3.
The observation is made from the interactive graph rather than from a formal curvature argument.
Quantifiers
Local statement at the single point x=0.
Claim that sufficiently accurate slope samples reveal the derivative curve
Clear evidence
Shown in the video
Evidence
Audio
Observation
The narrator explains that sufficiently accurate estimates trigger the program to reveal the derivative graph.
Animation
Observation
After multiple adjustments, a yellow curve connects the seven slope-control positions.
Formula
Observation
Final overlay shows \frac{d}{dx} f(x)=6x^2.
Uncertainties
The video demonstrates reconstruction of the derivative shape visually; it does not formally prove uniqueness from finitely many sampled points.
Proposition
Statement
If the user adjusts all seven orange points close enough to the true tangent slopes, the interface draws the derivative curve of the original function.
Hypotheses
Enough accuracy has been achieved in estimating the individual slopes.
The underlying function remains the same displayed f(x)=2x^3 throughout.
Quantifiers
Conditional practical claim about the interactive demonstration.
The orange curve represents the derivative function across the displayed interval
Clear evidence
Shown in the video
Evidence
Audio
Observation
The narrator treats the revealed curve as the derivative function throughout the visible graph.
Diagram
Observation
A smooth orange parabolic curve spans the plotting area and passes through the sampled derivative points.
Proposition
Statement
In this exercise, the orange curve is the graphical representation of d/dx f(x)=6x^2, giving the tangent-line slope of f at each displayed x.
Hypotheses
The underlying function is f(x)=2x^3.
The displayed top-left formula d/dx f(x)=6x^2 is accepted as correct.
Spoken examples are consistent with the displayed derivative formula
Approximate timing
Derived from the video
Evidence
Audio
Observation
At x=-0.5 the narrator estimates a little over 1; at x≈-2.25 he estimates about 30.
Formula
Observation
Using 6x^2 gives exactly 1.5 at x=-0.5 and 30.375 at x=-2.25.
Uncertainties
The spoken approximations are visual eyeballing statements, not exact symbolic evaluations printed on screen.
Proposition
Statement
The narrated rough readings correspond numerically to evaluating 6x^2 at those x-values.
Hypotheses
The derivative formula is 6x^2.
The referenced x-values are approximately -0.5 and -2.25.
Derivations and proofs · 4
Visual derivation of how the derivative changes across the chosen sample points
Clear evidence
Shown in the video
Evidence
Audio
Observation
Speaker narrates going from large positive slope at -2, decreasing through intermediate points, reaching zero at 0, then increasing again for positive x.
Formula
Observation
Stabilized readings include 24, roughly 13.5, roughly 6, 0, 6, 13.5, 24 across the ordered sample points.
Diagram
Observation
Tangent lines visibly flatten approaching x=0 and steepen away from it symmetrically.
Uncertainties
Exact intermediate eyeballed values vary frame-to-frame before acceptance.
This is an observed pattern-based derivation from the GUI, not a symbolic proof.
Visual argument
Steps
Expression
dxdf(−2)≈24
Explanation
Starting far left, the first tangent estimate corresponds to a very steep positive slope.
Justification
Observed from the updated answer field and the steep orange line at x=-2.
Shown in the video
Expression
dxdf(−1.5)≈13.5
Explanation
Moving rightward, the next tangent line is still positive but less steep than at -2.
Justification
Speaker remarks that the slope is decreasing yet still very positive; the answer panel later stabilizes near 13.5.
Shown in the video
Expression
dxdf(−1)≈6
Explanation
The third sample continues the trend of flattening while remaining above zero.
Justification
Audio describes further decrease to about five/six, and the final accepted reading is approximately 6.
Shown in the video
Expression
dxdf(0)=0
Explanation
At the middle sample the line becomes horizontal.
Justification
Explicitly stated as zero slope/flat and confirmed by the answer field.
Shown in the video
Expression
dxdf(1)≈6
Explanation
To the right of zero, the slope begins increasing again and matches the earlier magnitude at x=-1.
Justification
Audio notes the slope is now increasing; the displayed value reaches 6.
Shown in the video
Expression
dxdf(1.5)≈13.5
Explanation
Continuing rightward gives another larger positive slope, mirroring the left side.
Justification
Final stabilized numerical entry and symmetry of the constructed yellow curve support this.
Shown in the video
Expression
dxdf(2)≈24
Explanation
The last sample returns to a steep positive slope comparable to the first.
Justification
Accepted answer field shows 24 at x=2.
Shown in the video
Expression
Pattern: +,+,+,0,+,+,+
Explanation
Across these seven points the derivative decreases to 0 at x=0 and then increases symmetrically.
Justification
Derived from the sequence of observed values and their geometric arrangement on the screen.
Derived from the video
Conclusion
The visual evidence supports that the derivative of f(x)=2x^3 is nonnegative at the sampled points, vanishes at x=0, and grows as |x| moves away from 0, consistent with the revealed quadratic derivative 6x^2.
From sampled tangent slopes to the derivative graph
Clear evidence
Shown in the video
Evidence
Animation
Observation
Once the last few points are set accurately, a yellow curve is automatically drawn through them.
Formula
Observation
Overlay identifies the drawn curve as \frac{d}{dx} f(x)=6x^2.
Audio
Observation
The audio links accurate slope estimates to the automatic appearance of the derivative graph.
Uncertainties
The mechanism of automatic drawing is part of the software behavior, not mathematically justified inside the clip.
Visual argument
Steps
Expression
{(ci,mi)}i=17
Explanation
Each adjusted orange control encodes one pair (input c_i, estimated slope m_i).
Justification
Directly observed from the mapping between point position and answer-list values.
These are the approximate collected sample heights of the derivative.
Justification
Read from the stabilized answer fields near the end of the clip.
Shown in the video
Expression
(c,m)=(x,6x2)
Explanation
The displayed formula indicates that the sampled pairs lie on y=6x^2.
Justification
Shown explicitly in the top overlay once the derivative curve appears.
Shown in the video
Expression
yellow curve=dxdf(x)
Explanation
The software interprets sufficient agreement among the samples as completion and renders the full derivative graph.
Justification
Narration plus immediate appearance of the connected yellow curve.
Shown in the video
Conclusion
The seven tangent-slope estimates are used to reconstruct the graph of the derivative, which the program identifies as y=6x^2.
From seven checked sample slopes to a continuous derivative graph
Clear evidence
Shown in the video
Evidence
Audio
Observation
Narrator contrasts finding the derivative only at special movable orange-dot points with now knowing it at every point because the whole derivative was drawn.
Animation
Observation
Interactive setup mentions seven draggable orange points; the clip focuses on post-adjustment state with full orange curve visible.
Uncertainties
The precise moment when the answer-check action occurs is not shown inside this excerpt; the clip begins after the adjustment stage.
Intuitive argument
Steps
Expression
Explanation
Start with the known function f(x)=2x^3 and its graph in blue.
Justification
Directly shown in the top-left label and main plot.
Shown in the video
Expression
Explanation
Use seven selected x-values (-2, -1.5, -1, 0, 1, 1.5, 2) where the learner adjusts tangent-like line slopes until they match the true local slopes.
Justification
Stated in the instructional text and reflected in the Answer list on the right.
Shown in the video
Expression
Explanation
Once these samples are sufficiently accurate, the system reveals the entire derivative curve instead of only isolated points.
Justification
The narration explains that completing the slope estimates caused the program to display the full derivative graph.
Shown in the video
Expression
dxdf(x)=6x2
Explanation
The revealed curve corresponds to the derivative formula shown at top left.
Justification
Formula is visibly present beside f(x)=2x^3.
Shown in the video
Expression
Explanation
Then any chosen x can be read vertically against the orange curve to obtain the tangent slope of f there.
Justification
Narrator demonstrates this by estimating values at x=-0.5 and x≈-2.25.
Shown in the video
Conclusion
The exercise teaches that checking finitely many representative tangent slopes can lead to recognition of the full derivative function, which then supplies slope information continuously.
Checking the narrated eyeballed values against 6x^2
Clear evidence
Derived from the video
Evidence
Audio
Observation
The speaker estimates a slope slightly above 1 at x=-0.5 and a slope near 30 at x≈-2.25.
Formula
Observation
Top-left formula gives d/dx f(x)=6x^2.
Uncertainties
These computations are analyst-added checks using the displayed formula; the video itself does not write out the algebraic substitution steps.
Numerical verification
Steps
Expression
dxdf(−0.5)=6(−0.5)2=6⋅0.25=1.5
Explanation
Evaluate the displayed derivative at x=-0.5.
Justification
Substitution into 6x^2.
Derived from the video
Expression
dxdf(−2.25)=6(−2.25)2=6⋅5.0625=30.375
Explanation
Evaluate the displayed derivative at x=-2.25.
Justification
Substitution into 6x^2.
Derived from the video
Expression
Explanation
Compare with the narrator’s verbal approximations: slightly above 1 and about 30.
Justification
Matches the qualitative spoken estimates closely.
Derived from the video
Conclusion
The spoken visual estimates agree with the analytic values implied by the displayed derivative formula.
Worked examples · 2
Worked demonstration: estimating the derivative of f(x)=2x^3 from tangent slopes
Clear evidence
Shown in the video
Evidence
Audio
Observation
Continuous narration walking through the whole interactive task.
Diagram
Observation
Graph of f(x)=2x^3 with seven adjustable tangent controls.
Animation
Observation
Successive dragging of points and updating of answer entries.
Uncertainties
This first 180-second analysis segment ends during a sentence; the original 238-second video continues. The later segment supplies the concluding commentary.
Early seconds contain mostly setup/interface description before substantive manipulation begins.
Problem
Given the graph of f(x)=2x^3, use seven draggable orange points to estimate the derivative at selected x-values and thereby discover the shape of the derivative function.
Given
Function displayed: f(x)=2x^3.
Seven sample inputs available in the interface: -2, -1.5, -1, 0, 1, 1.5, 2.
Task instruction: move each orange point up/down to adjust the slope of the corresponding tangent line.
Approximate \frac{d}{dx}f(c) at the listed sample points and observe the resulting derivative curve.
Steps
Expression
Introduce idea: f′(c)=slope of tangent at x=c
Explanation
Before manipulating anything, the narrator frames the entire exercise as finding local tangent slopes.
Justification
Spoken explanation and on-screen instructions both state this definition.
Shown in the video
Expression
dxdf(x)x=−2≈24
Explanation
First, the point at x=-2 is raised until its line looks tangent to the steep left branch of the cubic.
Justification
Observed during the initial drag sequence; final accepted value shown as 24.
Shown in the video
Expression
dxdf(x)x=−1.5≈13.5
Explanation
Next, the adjacent point is lowered relative to the previous one because the curve is still rising but less steeply.
Justification
Narrator comments that the slope is decreasing yet still very positive; stable answer near 13.5.
Shown in the video
Expression
dxdf(x)x=−1≈6
Explanation
The third left-side sample is reduced further, reflecting continued flattening toward the origin.
Justification
Speech mentions about five/six, and the interface ultimately records approximately 6.
Shown in the video
Expression
dxdf(x)x=0=0
Explanation
At the center point, the tangent line is made horizontal.
Justification
Explicitly called out as zero slope and also identified verbally as an inflection point.
Shown in the video
Expression
dxdf(x)x=1≈6
Explanation
On the right side of the origin, the slope starts increasing again and mirrors the earlier value at x=-1.
Justification
Audio notes increase after zero; answer field shows 6.
Shown in the video
Expression
dxdf(x)x=1.5≈13.5
Explanation
The next right-side point rises higher, matching the symmetric left-side sample at -1.5.
Justification
Final settled reading and symmetric placement of the eventual yellow curve.
Shown in the video
Expression
dxdf(x)x=2≈24
Explanation
The far-right endpoint is set to a steep positive slope analogous to the far-left starting point.
Justification
Last adjustment before completion; accepted value 24.
Shown in the video
Expression
Revealed derivative curve: y=6x2
Explanation
With all seven samples close enough, the system draws the derivative graph connecting them.
Justification
Software animation plus top overlay formula \frac{d}{dx}f(x)=6x^2.
Shown in the video
Answer
The completed approximation yields sample derivative values approximately 24, 13.5, 6, 0, 6, 13.5, 24 at x=-2,-1.5,-1,0,1,1.5,2 respectively, and the interface reveals the derivative curve \frac{d}{dx}f(x)=6x^2.
Verification
Within the clip, verification is internal to the module: once the points are close enough, the correct derivative curve is automatically drawn and labeled. No separate external check is performed beyond the software feedback.
Khan Academy interactive derivative intuition problem
Clear evidence
Shown in the video
Evidence
Caption evidence
Observation
The interface requests vertical adjustment of 7 orange slope controls.
Caption evidence
Observation
The task is to align each trial line with the graph locally and estimate the derivative d/dx f[x] at that input.
Diagram
Observation
Blue graph of f(x)=2x^3, orange derivative-related points/curve, gray tangent-style segments, and Answer panel listing seven derivative values.
Uncertainties
The clip does not show the initial unadjusted state before dragging, nor the click sequence leading to the completed display.
Problem
Given f(x)=2x^3, determine the derivative at several selected points by adjusting tangent-line slopes until they visually match the curve’s local slopes.
Given
Function f(x)=2x^3 is plotted in blue.
There are 7 selectable/orange points.
Target x-values listed on the right are -2, -1.5, -1, 0, 1, 1.5, 2.
Goal
Find \frac{d}{dx}f(x) at the specified points and understand the resulting derivative curve.
Steps
Expression
Explanation
Identify the local slope needed at each marked x-value on the blue curve.
Justification
Instructional text defines derivative as tangent-line slope at each point.
Read the completed answers from the right-hand panel.
Justification
Values are explicitly displayed in the Answer section.
Shown in the video
Expression
dxdf(x)=6x2
Explanation
Recognize that the seven checked values lie on the parabola shown in orange and equal the general derivative formula displayed at top left.
Justification
Combines visible formula, plotted curve symmetry, and tabulated values.
Derived from the video
Answer
The derivative values at the requested points are 24, 13.5, 6, 0, 6, 13.5, 24 respectively, and the overall derivative is 6x^2.
Verification
Each listed value agrees with direct substitution into 6x^2: 6(-2)^2=24, 6(-1.5)^2=13.5, 6(-1)^2=6, 6(0)^2=0, etc.
Visual events · 5
Initial static layout of the derivative-intuition exercise
Clear evidence
Shown in the video
Evidence
Diagram
Observation
Blue cubic curve centered at origin; seven gray/orange control markers aligned horizontally; right panel lists seven derivative expressions initially at 0.
Formula
Observation
Visible headings include f(x)=2x^3 and instructional text about adjusting tangent-line slopes.
Objects
blue graph of f(x)=2x^3
seven draggable control points
horizontal default tangent lines
right-side answer list initialized to 0
Changes
Mouse cursor hovers around the canvas and points without major value changes yet.
Invariants
Underlying function remains f(x)=2x^3.
Sample locations remain fixed at the seven chosen x-values.
Interpretation
The opening view establishes that the task is to assign slopes to preselected points on a fixed curve, not to move the points themselves along the curve.
Adjustment of the tangent slope at x=-2
Clear evidence
Shown in the video
Evidence
Animation
Observation
Hovering highlights one marker and its line turns orange; dragging upward makes the corresponding line steeper.
Formula
Observation
Answer entry for \frac{d}{dx} f(-2) climbs from 0 into the low twenties and then stabilizes at 24.
Uncertainties
Exact path of intermediate numeric updates varies frame-by-frame.
Objects
control point at x=-2
its orange tangent line
corresponding answer row \frac{d}{dx} f(-2)
Changes
Line rotates counterclockwise/upward as the point is dragged vertically.
Numeric derivative estimate increases from 0 to about 24.
Invariants
Point stays associated with x=-2.
Curve itself does not move.
Interpretation
Vertical displacement of the control encodes slope magnitude; larger height means steeper positive tangent.
Sequence of tangent-slope refinements across the remaining six points
Clear evidence
Shown in the video
Evidence
Animation
Observation
Subsequent points are edited left-to-right, producing progressively flatter lines toward x=0 and then steeper lines again afterward.
Formula
Observation
Rows update sequentially to approximations including 13.5, 6, 0, 6, 13.5, 24.
Diagram
Observation
Orange/gold tangent segments accumulate across the plot.
Uncertainties
Minor fluctuations occur before some rows settle exactly.
Objects
six additional control points
their rotating tangent lines
live-updating answer column
Changes
Slopes decrease monotonically from the leftmost sample to 0 at x=0.
Slopes then increase monotonically from x=0 to the rightmost sample.
The collection of adjusted heights increasingly suggests a U-shaped pattern.
Invariants
Same base function f(x)=2x^3 throughout.
Same seven evaluation abscissas throughout.
Interpretation
The changing line orientations make the abstract derivative visible as a field of local slopes sampled at discrete inputs.
Automatic revelation of the derivative graph
Clear evidence
Shown in the video
Evidence
Animation
Observation
A yellow curve suddenly appears through the previously placed orange points.
Formula
Observation
Top overlay adds \frac{d}{dx} f(x)=6x^2 beside f(x)=2x^3.
Audio
Observation
The narrator acknowledges completion as the full derivative graph appears.
Uncertainties
The precise threshold tolerance triggering the reveal is not disclosed.
Objects
yellow derivative curve
seven finalized control points
top formula overlay
Changes
Discrete slope samples become connected into a continuous-looking graph.
Screen gains explicit identification of the derivative formula.
Invariants
Original blue cubic remains unchanged beneath the new overlay.
Selected x-values stay the same.
Interpretation
The interface converts locally estimated tangent slopes into a global picture of the derivative function.
Completed interactive view of derivative exercise
Clear evidence
Shown in the video
Evidence
Diagram
Observation
Throughout the excerpt the layout stays fixed: title/instructions and formulas top left, large Cartesian plot center-left, Answer/hints/help panels on the right.
Animation
Observation
No major scene change occurs; only mouse cursor movement changes location over the graph and sidebars.
Uncertainties
Sampling may miss tiny transient UI flashes between frames.
Objects
Blue cubic curve for f(x)=2x^3
Orange parabolic derivative curve for 6x^2
Gray short tangent-style line segments
Coordinate axes with numeric ticks
Answer panel with seven derivative values
Mouse cursor moving over graph regions
Changes
Cursor moves among left-negative region, origin vicinity, and upper-right portion of the graph.
Narration shifts attention from previously adjustable orange points to reading arbitrary points along the full derivative curve.
Invariants
The displayed formulas remain f(x)=2x^3 and d/dx f(x)=6x^2.
The Answer list remains unchanged during this excerpt.
The orange curve continues to represent slope values across the visible domain.
Interpretation
Visually, the clip emphasizes transition from finite sampled tangency adjustments to continuous interpretation of the derivative graph: the same orange curve simultaneously encodes all tangent slopes of the blue cubic.
Misconceptions · 3
Possible conflation of input and output in speech
Clear evidence
Shown in the video
Evidence
Audio
Observation
One spoken description treats the selected argument as though it were a function output.
Formula
Observation
Displayed notation is \frac{d}{dx} f(-2), meaning evaluate derivative at input -2.
Uncertainties
It is unclear whether this was momentary verbal shorthand or genuine confusion; the mathematics on screen is unambiguous.
Misconception
The loose wording could make a learner look for f(x)=-2 instead of the intended input x=-2.
Clarification
The notation \frac{d}{dx} f(-2) refers to the derivative at the input value x=-2, not at a place where the output f(x) happens to be -2. In this clip, the relevant point on the graph is the one with abscissa -2.
Zero slope does not require a local maximum or minimum here
Clear evidence
Shown in the video
Evidence
Audio
Observation
At x=0 the speaker emphasizes that the slope is zero and calls the spot an inflection point.
Diagram
Observation
The curve crosses through the origin while having a horizontal tangent there.
Misconception
Learners might assume a horizontal tangent always marks a peak or valley.
Clarification
In this example, x=0 has derivative 0 but is described as an inflection point, showing that a tangent can be horizontal even when the graph neither attains a local max nor min there.
Mistaking derivative knowledge for only the seven checked sample points
Clear evidence
Shown in the video
Evidence
Audio
Observation
Narrator stresses that although we did not move a dot around at -0.5, the full derivative still tells us the slope there.
Misconception
One might think the derivative has been found only at the seven specially manipulated points.
Clarification
The video explicitly broadens the idea: once the whole derivative curve is known, it gives the tangent-line slope at every point in the displayed range, not merely at the originally dragged locations.
Concept relations · 6
Definition of derivative via tangent-line slope → Estimating derivatives by adjusting tangent lines
Clear evidence
Derived from the video
Evidence
Audio
Observation
Definition of derivative as tangent slope precedes the hands-on adjustment process.
Animation
Observation
Entire interaction consists of setting slopes of tangent lines.
Application
Explanation
The graphical method directly applies the definition that a derivative equals the slope of the tangent line at a point.
Estimating derivatives by adjusting tangent lines → Derivative formula for f(x)=2x^3
Clear evidence
Derived from the video
Evidence
Animation
Observation
Collected slope samples lead to the automatic drawing of a curve.
Formula
Observation
That curve is then named \frac{d}{dx} f(x)=6x^2.
Application
Explanation
Repeated application of the sampling method reveals the overall derivative function for the specific example f(x)=2x^3.
Definition of derivative via tangent-line slope → Derivative formula for f(x)=2x^3
Clear evidence
Supplementary explanation
Evidence
Formula
Observation
Concrete instance shown: derivative of 2x^3 is 6x^2.
Uncertainties
General power rule is background knowledge supplied by the analyst, not explicitly taught in this excerpt.
Application
Explanation
Editorial relationship: the displayed result d/dx(2x^3)=6x^2 applies the derivative-as-tangent-slope idea to this cubic. The standard power rule explains the formula, but its general proof is background knowledge and is not presented in this segment.
Definition used in this module: derivative equals tangent-line slope → Derivative formula for the displayed cubic
Clear evidence
Derived from the video
Evidence
Caption evidence
Observation
Definition text ties derivative to tangent slope.
Formula
Observation
Specific displayed pair f(x)=2x^3 and d/dx f(x)=6x^2.
Application
Explanation
The general definition of derivative-as-slope is instantiated concretely for the cubic function by the displayed formula 6x^2.
Derivative formula for the displayed cubic → Reading the full derivative curve as a slope function
Clear evidence
Derived from the video
Evidence
Audio
Observation
Narrator uses the whole derivative curve to estimate slopes at new x-values such as -0.5 and -2.25.
Application
Explanation
Knowing the explicit derivative formula makes the reading method meaningful: the orange graph is precisely the set of values produced by 6x^2.
Definition used in this module: derivative equals tangent-line slope → Khan Academy interactive derivative intuition problem
Clear evidence
Shown in the video
Evidence
Caption evidence
Observation
Instructions define derivative as tangent slope and ask the user to adjust slopes accordingly.
Proof dependency
Explanation
The interactive task depends on the stated geometric definition of derivative; without interpreting derivative as tangent slope, the drag-the-lines activity loses meaning.
Find an answer · 9
How does this Khan Academy clip define a derivative intuitively?
Clear evidence
Derived from the video
Evidence
Audio
Observation
Definition spoken plainly as slope of tangent line.
Knowledge points
Definition of derivative via tangent-line slope
What does the notation d/dx f(-2) mean in this exercise?
Clear evidence
Derived from the video
Evidence
Formula
Observation
Notation \frac{d}{dx} f(-2) shown in answer list.
Audio
Observation
Speaker attempts to explain the notation aloud.
Knowledge points
Definition of derivative via tangent-line slope
Possible conflation of input and output in speech
Why does the derivative of 2x^3 equal 0 at x=0 even though the graph keeps crossing upward?
Clear evidence
Derived from the video
Evidence
Audio
Observation
Speaker says the slope is zero and calls it an inflection point.
Diagram
Observation
Horizontal tangent at x=0.
Knowledge points
Claim about the behavior at x=0
Zero slope does not require a local maximum or minimum here
How do the seven estimated tangent slopes combine to produce the graph of 6x^2?
Clear evidence
Derived from the video
Evidence
Animation
Observation
Adjusted points trigger appearance of derivative curve.
Formula
Observation
Final label \frac{d}{dx} f(x)=6x^2.
Knowledge points
Estimating derivatives by adjusting tangent lines
From sampled tangent slopes to the derivative graph
Derivative formula for f(x)=2x^3
What numerical derivative values does the module accept for f(x)=2x^3 at x=-2,-1.5,-1,0,1,1.5,2?
Clear evidence
Derived from the video
Evidence
Formula
Observation
Stable answer values at selected inputs.
Knowledge points
Worked demonstration: estimating the derivative of f(x)=2x^3 from tangent slopes
answer entries \frac{d}{dx} f(c)
What does the orange parabola represent in this Khan Academy derivative intuition exercise?
Clear evidence
Derived from the video
Evidence
Audio
Observation
Narrator says the whole slope of the derivative was drawn and describes it as the slope of the tangent line at any point.
Knowledge points
Definition used in this module: derivative equals tangent-line slope
Derivative formula for the displayed cubic
Reading the full derivative curve as a slope function
How do I use the derivative graph to find the tangent slope at a point that was not one of the seven checked points?
Clear evidence
Derived from the video
Evidence
Audio
Observation
Narrator demonstrates reading a slope at x=-0.5 even though no dot was moved there.
Knowledge points
Reading the full derivative curve as a slope function
From seven checked sample slopes to a continuous derivative graph
Why is the derivative of f(x)=2x^3 shown as 6x^2?
Clear evidence
Derived from the video
Evidence
Formula
Observation
Top-left displays d/dx f(x)=6x^2 for f(x)=2x^3.
Uncertainties
The derivation itself is not shown in this excerpt.
Knowledge points
Derivative formula for the displayed cubic
Checking the narrated eyeballed values against 6x^2
Where do the numbers 24, 13.5, 6, 0 come from in the answer box?
Clear evidence
Derived from the video
Evidence
Caption evidence
Observation
Answer panel lists seven specific derivative values.
Knowledge points
Khan Academy interactive derivative intuition problem
Derivative formula for the displayed cubic
Checking the narrated eyeballed values against 6x^2
Coverage and review notes
Covered · Introductory context naming the derivative intuition module and crediting Ben Eater; little distinct mathematical content beyond framing the tool.
Covered · Core conceptual statement that derivative means tangent-line slope, followed by identification of the graphed function f(x)=2x^3.
Covered · Demonstration begins with explaining the orange controls and tuning the tangent at x=-2.
Covered · Middle progression through x=-1.5, -1, and 0, including interpretation of notation and recognition of zero slope/inflection behavior.
Covered · Right-half adjustments show the slope increasing again after the origin and building the symmetric pattern.
Covered · Actual frames at 177, 179 and 180 seconds show the revealed derivative formula 6x^2, the derivative curve and all seven values continuously. The 180-second boundary is an analysis segmentation boundary; narration continues in the remaining 58 seconds of the 238-second video. Software tolerance and formal power-rule proof are outside this introductory segment, not missing media.
Covered · Opening explanation recalls that earlier work used seven movable orange points and introduces the already-revealed derivative picture.
Covered · Main teaching segment: narrator interprets the full derivative curve and estimates slopes at additional x-values beyond the checked sample points. The last source frame occurs before nominal 58 seconds because full file duration is 237.954; coverage endpoint uses verified rounded duration 238.
Candidate from reviewed en material v1: At a differentiable point, the derivative is the finite slope of the tangent line. The video turns that idea into a visual task: align a line with the curve locally, then read its slope as the derivative value. Editorial clarification: the existence of a tangent alone is insufficient if its slope is vertical; a finite derivative must exist.