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Probability & statistics · English

Die rolling probability with independent events | Precalculus | Khan Academy

Solve the three-even-rolls problem with a fair six-sided die, independent events and the multiplication rule, with bilingual learning notes.

Reviewed learning material · Video analysis · English

Work through a complete Khan Academy dice problem: on a fair six-sided die, the even faces 2, 4 and 6 give a single-roll probability of 3/6=1/2. Assuming three mutually independent rolls, multiply three one-half factors to obtain 1/8 for an even result on every roll. Editorial notes distinguish fairness from independence and clarify that pairwise independence alone does not justify a three-event product.

Before you watch

  • Basic fractions and simplification
  • Concept of even and odd numbers
  • Basic understanding of probability
  • Concept of a fair six-sided die

Chapters

0:00Problem Statement0:11Probability of a Single Even Roll1:02Independent Events Introduction1:14Combine the three even-roll events1:21Setting Up the Equation for Three Rolls2:05Applying the Multiplication Rule for Independent Events2:07Calculating the Final Probability

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

Find the probability of an even result on all three rolls, using the fair six-sided, independent-roll model.

First find the probability of one even roll; the board writes an event description inside P.

The possible faces are 1, 2, 3, 4, 5 and 6. In the fair-die model, these outcomes are equally likely.

Circle the favorable faces 2, 4 and 6.

There are 3 favorable faces out of 6 equally likely faces, giving 3/6=1/2.

The lesson now introduces independence to connect the three rolls. This is a separate assumption from fairness.

With independent rolls, knowing past outcomes does not change the next-roll probability. The video briefly addresses a related gambling misconception.

Continue from the single-roll result 1/2: the even faces remain 2, 4 and 6, and the target is an even result on each of three rolls.

The combined event requires all three even outcomes. Mutual independence of the trials supports multiplying the probabilities; fairness alone would not do so.

For mutually independent events, the probability that all occur is the product of their individual probabilities. Pairwise independence alone is insufficient for this three-event rule.

The board completes 1/2×1/2×1/2=1/8: all three rolls are even with probability 1/8 in the stated model.

Knowledge cards

01

Classical Probability Formula

For experiments with equally likely outcomes, the probability of an event E is the ratio of the number of favorable outcomes to the total number of possible outcomes.

P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
02

Independence

For two events, independence means one event does not change the other event probability. Repeated rolls in this example are assumed independent; a fair die alone does not imply this.

03

Sample Space of a Six-Sided Die

The set of all possible outcomes when rolling a standard six-sided die numbered 1 to 6.

Ω={1,2,3,4,5,6}\Omega = \{1, 2, 3, 4, 5, 6\}
04

Independent Events

The three-roll product uses mutual independence, which is stronger than pairwise independence. The lesson applies this model to repeated die rolls.

05

Multiplication Rule for Independent Events

If A, B and C are mutually independent, their intersection probability equals P(A)×P(B)×P(C).

P(A∩B∩C)=P(A)×P(B)×P(C)P(A \cap B \cap C) = P(A) \times P(B) \times P(C)
06

Example: Rolling Even Numbers Three Times

A fair six-sided die gives an even-roll probability of 1/2. Under three mutually independent rolls, the probability all are even is 1/2×1/2×1/2=1/8.

P(even 3 times)=12×12×12=18P(\text{even 3 times}) = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}

Detailed learning notes

Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.

Symbols · 4

P

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The letter P is written to denote probability.

Symbol

P

Meaning

Probability of an event.

Domain

Probability notation.

even roll on 6-sided die

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The phrase 'even roll on 6-sided die' is written inside parentheses after P.

Symbol

even roll on 6-sided die

Meaning

The event that a single roll of a fair six-sided die produces an even number.

Domain

Event description in probability notation.

P(even roll on 6-sided die)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    P(even roll on 6-sided die) = 3/6 = 1/2

Symbol

P(even roll on 6-sided die)

Meaning

Probability of rolling an even number on a single roll of a fair six-sided die.

Domain

[0, 1]

P(rolling even 3 times)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    P(rolling even 3 times)

Symbol

P(rolling even 3 times)

Meaning

Probability of rolling an even number three consecutive times with a fair six-sided die.

Domain

[0, 1]

Knowledge points · 4

Classical Probability Formula

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    Narration compares the total face count with the even-face count.

  2. Formula
    Observation

    The expression P(even roll on 6-sided die) = 3/6 is written.

  3. Diagram
    Observation

    The numbers 1 through 6 are listed vertically, and 2, 4, and 6 are circled.

Formula
Explanation

For a finite sample space of equally likely outcomes, count favorable outcomes and divide by the total.

Formula
P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
Conditions
  1. All outcomes must be equally likely.

Independence

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The presenter introduces independent rolls before setting up the combined event.

Uncertainties
  1. This opening interval introduces independence; the full video completes the multiplication after this interval.

Definition
Explanation

Events are independent if the occurrence of one event does not affect the probability of the other event occurring.

Conditions
  1. The three rolls are mutually independent. Fairness alone does not establish independence.

Independent Events

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The presenter invokes independence to justify multiplying the roll probabilities.

Definition
Explanation

For this three-roll model, assume mutual independence: the probabilities for intersections of any subset factor into the individual probabilities. Pairwise independence alone is insufficient for the three-event product.

Conditions
  1. The three rolls are mutually independent. Fairness alone does not establish independence.

Multiplication Rule for Independent Events

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    P(rolling even 3 times) = P(even roll on 6-sided die) × P(even roll on 6-sided die) × P(even roll on 6-sided die)

  2. Audio
    Observation

    The narration builds a product of three single-roll probabilities under the independent-roll model.

Formula
Explanation

Mutual independence of A, B and C is sufficient for the three-event intersection probability to equal the product of their marginal probabilities.

Formula
P(A∩B∩C)=P(A)×P(B)×P(C)P(A \cap B \cap C) = P(A) \times P(B) \times P(C)
Conditions
  1. A, B and C are mutually independent; pairwise independence alone is not sufficient.

Prerequisites
  1. Independent Events
Derivations and proofs · 2

Derivation of Probability for a Single Even Roll

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The calculation counts six possible faces and three even faces.

  2. Formula
    Observation

    The equation P(even roll on 6-sided die) = 3/6 = 1/2 is written step-by-step.

  3. Diagram
    Observation

    Numbers 1-6 are listed; 2, 4, 6 are circled to show favorable outcomes.

Visual argument
Steps
  1. Expression
    {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\}
    Explanation

    Identify all possible outcomes of rolling a standard six-sided die.

    Justification

    Definition of the sample space for a six-sided die.

    Shown in the video
  2. Expression
    {2,4,6}\{2, 4, 6\}
    Explanation

    Identify the outcomes that satisfy the condition of being an even number.

    Justification

    Condition specified in the problem statement.

    Shown in the video
  3. Expression
    P(even)=36P(\text{even}) = \frac{3}{6}
    Explanation

    Calculate the probability by dividing the number of favorable outcomes by the total number of outcomes.

    Justification

    A fair six-sided die: each face has equal probability.

    Supplementary explanation
  4. Expression
    36=12\frac{3}{6} = \frac{1}{2}
    Explanation

    Simplify the fraction.

    Justification

    Arithmetic simplification.

    Shown in the video
Conclusion

For a fair six-sided die, three of the six equally likely faces are even, giving probability 1/2.

Calculation of Probability

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    = 1/2 × 1/2 × 1/2 = 1/8

  2. Audio
    Observation

    The final calculation multiplies three one-half factors to obtain one-eighth.

Numerical verification
Steps
  1. Expression
    P(all three even)=P(even)×P(even)×P(even)P(\text{all three even})=P(\text{even})\times P(\text{even})\times P(\text{even})
    Explanation

    Apply the multiplication rule for independent events.

    Justification

    The three rolls are mutually independent. Fairness alone does not establish independence.

    Supplementary explanation
  2. Expression
    =12×12×12=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}
    Explanation

    Substitute the probability of a single even roll (1/2) into the equation.

    Justification

    Given in the problem statement.

    Shown in the video
  3. Expression
    =18=\frac{1}{8}
    Explanation

    Calculate the final product.

    Justification

    Arithmetic calculation.

    Shown in the video
Conclusion

Under fair, mutually independent rolls, the probability that all three are even is 1/8.

Worked examples · 2

Probability of Rolling Even Numbers Three Times

Clear evidence
Supplementary explanation
Evidence
  1. Caption evidence
    Observation

    The opening task asks for three even outcomes when rolling a die with faces numbered one through six.

  2. Audio
    Observation

    The opening task asks for three even outcomes when rolling a die with faces numbered one through six.

Uncertainties
  1. This 0–74-second setup interval stops before the final calculation; the continuation in the full video supplies the result.

Problem

Find the probability of rolling even numbers three times, using a six-sided die numbered from 1 to 6.

Given
  1. A fair six-sided die: each face has equal probability.

  2. Target event: every one of the 3 rolls is even.

  3. The three rolls are mutually independent. Fairness alone does not establish independence.

Goal

Determine the probability of the target event occurring in all three trials.

Steps
  1. Expression
    P(even)=36=12P(\text{even}) = \frac{3}{6} = \frac{1}{2}
    Explanation

    Calculate the probability of rolling an even number on a single roll.

    Justification

    Break down the compound event into simpler, single-trial events.

    Shown in the video
  2. Explanation

    Recognize that the three rolls are independent events.

    Justification

    The three rolls are mutually independent. Fairness alone does not establish independence.

    Supplementary explanation
Answer

The setup establishes a per-roll probability of 1/2 and an independent-roll model; the final product appears in the continuation.

Verification

Three favorable faces out of six equally likely faces gives 3/6=1/2; this verifies the single-roll part only.

Probability of Rolling Even Numbers Three Times

Clear evidence
Supplementary explanation
Evidence
  1. Caption evidence
    Observation

    The displayed problem concerns an even result on every one of three successive rolls.

  2. Formula
    Observation

    P(even roll on 6-sided die) = 3/6 = 1/2

  3. Formula
    Observation

    P(rolling even 3 times) = P(even roll on 6-sided die) × P(even roll on 6-sided die) × P(even roll on 6-sided die) = 1/2 × 1/2 × 1/2 = 1/8

Problem

Find the probability of rolling even numbers three times, using a six-sided die numbered from 1 to 6.

Given
  1. A fair six-sided die: each face has equal probability.

  2. The probability of a single even roll is 1/2.

  3. The three rolls are mutually independent. Fairness alone does not establish independence.

Goal

Calculate the probability of rolling an even number three consecutive times.

Steps
  1. Expression
    P(all three even)=P(even)×P(even)×P(even)P(\text{all three even})=P(\text{even})\times P(\text{even})\times P(\text{even})
    Explanation

    Since the rolls are independent events, multiply the probability of a single even roll by itself three times.

    Justification

    The three rolls are mutually independent. Fairness alone does not establish independence.

    Supplementary explanation
  2. Expression
    =12×12×12=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}
    Explanation

    Substitute the given probability of a single even roll.

    Justification

    Given in the problem statement.

    Shown in the video
  3. Expression
    =18=\frac{1}{8}
    Explanation

    Perform the multiplication.

    Justification

    Arithmetic calculation.

    Shown in the video
Answer

1/8

Verification

The result is consistent with the visual representation of the calculation on the whiteboard.

Visual events · 2

Visualizing Sample Space and Favorable Outcomes

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    Numbers 1 through 6 appear sequentially in a vertical list.

  2. Animation
    Observation

    Circles are drawn around the numbers 2, 4, and 6.

Objects
  1. Numbers 1-6

  2. Circles

Changes
  1. Numbers appear one by one.

  2. Specific numbers (2, 4, 6) are highlighted with circles.

Invariants
  1. The list remains vertical.

  2. The numbers 1, 3, 5 remain uncircled.

Interpretation

The visual represents the total possible outcomes of a die roll and highlights the subset of outcomes that are even numbers.

Highlighting and Copy-Pasting Terms

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    The presenter uses a dashed box to highlight and copy-paste the term 'P(even roll on 6-sided die)' multiple times to build the multiplication expression.

Objects
  1. Dashed box

  2. Text 'P(even roll on 6-sided die)'

Changes
  1. The dashed box moves to enclose the term.

  2. The term is copied and pasted to form a longer equation.

Invariants
  1. The value of the term remains 1/2.

Interpretation

This visual action emphasizes that the same probability is being multiplied for each independent roll.

Misconceptions · 1

Gambler's Fallacy in Independent Events

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The presenter rejects the belief that previous rolls change the next roll under independence.

Uncertainties
  1. The video mentions this misconception briefly; it does not present a general treatment of dependent trials.

Misconception

Believing that past independent events influence the probabilities of future independent events.

Clarification

Under the mutually independent-roll model, knowing previous results does not change the probability of the next even result. Fairness and independence are separate assumptions.

Concept relations · 2

Independence → Probability of Rolling Even Numbers Three Times

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The lesson connects the single-roll calculation to independence of repeated rolls.

Uncertainties
  1. The multiplication is developed later in the complete video, beyond this opening interval.

Application
Explanation

Independence supplies the model assumption used to multiply the three probabilities in this example.

Independent Events → Multiplication Rule for Independent Events

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The narration uses independence as the model assumption for the product calculation.

Prerequisite
Explanation

Mutual independence is the sufficient model assumption used for this product calculation.

Find an answer · 4

How is the probability of an even result found for a fair six-sided die?

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    P(even roll on 6-sided die) = 3/6 = 1/2 is derived.

Knowledge points
  1. Classical Probability Formula
  2. Derivation of Probability for a Single Even Roll

What independence assumption is used for repeated die rolls?

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The presenter explains the independent-roll assumption.

Knowledge points
  1. Independence

How do you calculate the probability of rolling an even number three times with a six-sided die?

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    The displayed task is to obtain an even number on each of three rolls.

Knowledge points
  1. Multiplication Rule for Independent Events
  2. Probability of Rolling Even Numbers Three Times

Why can we multiply the probabilities of individual die rolls?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The presenter invokes independence for the multiplication step.

Knowledge points
  1. Independent Events
  2. Multiplication Rule for Independent Events
Coverage and review notes

Covered · Problem statement is read and displayed.

Covered · Setting up the probability notation for a single roll.

Covered · Calculating the probability of a single even roll using classical probability.

Covered · This requested0–74sec segment covers the transition to three independent rolls. The complete source continues after74sec; the multiplication calculation is outside this segment, not missing within its requested interval.

Covered · All mathematical content in the clip is covered.

Covered · Actual full-source146.3sec frame (relative72.3) preserves the completed1/8 equation; final requested second has the same finished calculation.

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  • Probability Explanation
    Why this connection?

    Work through a complete Khan Academy dice problem: on a fair six-sided die, the even faces 2, 4 and 6 give a single-roll probability of 3/6=1/2. Assuming three mutually independent rolls, multiply three one-half factors to obtain 1/8 for an even result on every roll. Editorial notes distinguish fairness from independence and clarify that pairwise independence alone does not justify a three-event product.

  • Independence ExplanationAt 1:03
    Why this connection?

    For two events, independence means one event does not change the other event probability. Repeated rolls in this example are assumed independent; a fair die alone does not imply this.