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Limits are...weird...for multi-variable functions | Limits along paths

Dr. Trefor Bazett · YouTube · 5:38

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The explanation, unpacked.

Reviewed learning material · Video analysis · English
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This 150-second introductory calculus lecture explains how to think about limits of multivariable functions by first reviewing one-variable limit behavior. The main example is f(x,y)f(x,y)=xy/(x2+y2x^2+y^2), which is undefined at (0,0) because the denominator vanishes there. The presenter warns that a computer-generated surface plot near such a singular point is only an interpolation and should not be treated as exact evidence. Two one-dimensional examples then clarify the logic: a piecewise jump function has no limit at x=1x=1 because the left and right limits differ, while a constant function with a hole at x=1x=1 still has limit 1 because both sides agree. Returning to the multivariable problem, the video introduces path restriction as a method, chooses the line y=xy=x, substitutes it into the function, simplifies to x2/(2x2)x^2/(2x^2), and computes the one-variable limit along that path as 1/21/2. The excerpt stops after this single-path calculation and does not state the final conclusion for the full two-variable limit. This 150-second lecture segment analyzes the multivariable function f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} near (0,0)(0,0) by restricting it to two straight-line paths. Along y=xy=x the displayed computation gives lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12; along y=−xy=-x it gives lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12. A 3D surface plot visually contrasts the two diagonals through the origin. From these unequal path-limits, the lecturer concludes that the full limit at (0,0)(0,0) does not exist and names the general criterion the two-path test for nonexistence. The segment ends by raising two unanswered questions: how to define existence of a multivariable limit, and whether agreement along every straight line is sufficient. This 38-second clip contains a short multivariable-calculus reflection followed by an outro. From 0 to 18 seconds, the lecturer displays a boxed proposition stating that if f(x,y)f(x,y) has two different limits along two different paths approaching (x0,y0)(x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to (x_0,y_0)} f(x,y) does not exist. Beneath it are two open questions: how to define existence of a limit at a point, and whether agreement along every straight line is enough to guarantee the limit exists. The audio emphasizes the contrast between straight-line paths and a possible curvy path, suggesting that straight-line agreement alone is not treated as conclusive. From 18 to 38 seconds, the scene changes to a studio-like room with a monitor reading 'SUBSCRIBE'; the speaker asks viewers to comment, like the video, and watch more videos in a multivariable calculus playlist. No worked example, proof, or final resolution of the open questions appears within this excerpt.

Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.

Chapters

0:00Title card: Limits of Multivariable Functions0:03Main example f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) and the question at (0,0)0:36Caution about interpolated graphs near the singularity0:59One-variable example with unequal one-sided limits1:33One-variable example with a hole but an existing limit1:48Return to the multivariable problem2:07Restrict to the path y=xy=x and compute the pathwise limit2:30Restrict to the line y=xy=x and compute the path limit2:53Change the restriction to y=−xy=-x and get a different limit3:55Conclude nonexistence at (0,0) from unequal path limits4:10State the two-path test for nonexistence4:51Pose two follow-up questions about existence and straight lines5:00Two-path nonexistence rule and open questions5:18Outro and channel promotion

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

The clip opens with a chalkboard-style title, “LIMITS OF MULTIVARIABLE FUNCTIONS,” signaling that the topic is limiting behavior for functions of more than one variable.

The first mathematical object shown is the two-variable function f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}, displayed beside a colored 3D surface plot. The lecturer’s goal is not to evaluate f(0,0)f(0,0) directly, but to ask what happens as (x,y)(x,y) approaches (0,0)(0,0).

He immediately identifies the obstruction: at (0,0)(0,0) the denominator x2+y2x^2+y^2 becomes zero, so the function is undefined there. This motivates a separate question about the limit, because limits concern nearby behavior rather than the value at the point itself.

Using the surface plot, he points to the origin as a visually “pinched” region where two parts of the graph seem to meet. He then adds an important caution: the plotted image is only an approximation, since graphing software interpolates between sampled nearby points and never actually evaluates the undefined point (0,0)(0,0).

To build intuition, the lecture temporarily leaves the multivariable setting and reviews a one-variable piecewise function: f(x)=1f(x)=1 for x<1x<1 and f(x)=2f(x)=2 for x≥1x\ge 1. The graph shows a jump at x=1x=1.

From the definition, the left-hand limit is lim⁡x→1−f(x)=1\lim_{x\to1^-}f(x)=1, while the right-hand limit is lim⁡x→1+f(x)=2\lim_{x\to1^+}f(x)=2. Because these one-sided limits disagree, the two-sided limit lim⁡x→1f(x)\lim_{x\to1}f(x) does not exist. This example establishes the rule that matching approach from both sides is required for a limit to exist.

The next one-variable example changes only the nature of the defect at the point. Now f(x)=1f(x)=1 for all x≠1x\ne1, so the function is undefined at x=1x=1, but the graph is otherwise a flat line at height 1.

Here both one-sided limits equal 1: lim⁡x→1−f(x)=1=lim⁡x→1+f(x)\lim_{x\to1^-}f(x)=1=\lim_{x\to1^+}f(x). Therefore lim⁡x→1f(x)=1\lim_{x\to1}f(x)=1 even though f(1)f(1) itself is missing. The contrast with the previous example makes clear that “undefined at the point” and “limit does not exist” are not the same statement.

With that groundwork laid, the lecture returns to the original multivariable function and the problematic point (0,0)(0,0). The speaker proposes a concrete strategy: restrict attention to a particular path through the point, thereby turning the multivariable question into a familiar one-variable limit problem.

He chooses the line y=xy=x, shown in red on the surface plot. Substituting y=xy=x into f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} gives x⋅xx2+x2=x22x2\frac{x\cdot x}{x^2+x^2}=\frac{x^2}{2x^2} for x≠0x\ne0 along that path.

The displayed conclusion is lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12. This is the limit along the single path y=xy=x; within this excerpt, the video stops after computing that pathwise value and does not yet state whether the full two-variable limit exists.

The segment opens on the worked example f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} with the restriction y=xy=x already displayed. The board shows the reduced one-variable expression x22x2\frac{x^2}{2x^2} and its limit 12\frac12 as x→0x\to 0. The lecturer emphasizes that this trick avoids inventing a new definition: once a path is chosen, the problem becomes an ordinary single-variable limit.

He then changes the restriction to y=−xy=-x. Algebraically, the substitution inserts minus signs, producing −x22x2\frac{-x^2}{2x^2}, whose limit is −12-\frac12. Visually, the highlighted diagonal on the surface plot switches to the opposite line through the origin, and the lecturer points out that the heights along this new path are much lower, matching the negative limiting value.

Comparing the two results, the lecture draws the key conclusion: because one approach to (0,0)(0,0) gives 12\frac12 and another gives −12-\frac12, the full multivariable limit of f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} at (0,0)(0,0) does not exist. The undefined central spot on the surface plot is used as the geometric picture of this path dependence.

A boxed theorem then formalizes the reasoning as the two-path test for nonexistence: if f(x,y)f(x,y) has two different limits along two different paths approaching (x0,y0)(x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to(x_0,y_0)} f(x,y) does not exist. The lecturer immediately stresses the limitation of this criterion: it proves nonexistence, not existence.

The clip closes by posing two future questions. First, how should one define what it means for a multivariable limit to exist at a point? Second, if approaching along every straight line gives the same value, does the limit necessarily exist? These questions are shown on screen and left unanswered within this segment.

The clip opens on a static lecture frame with a white-bordered theorem box and two numbered questions beneath it. The displayed mathematical statement is: If f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to (x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to (x_0,y_0)} f(x,y) does not exist. This is a one-way nonexistence test: unequal path-limits are enough to rule out the full multivariable limit.

While that theorem remains on screen, the speaker shifts attention to Question 2: suppose every straight-line approach gives the same value. The spoken line asks whether a curvy path could change the limit, making clear that the set of all paths is broader than the set of straight lines.

The mathematical point of this segment is contrast. The first displayed fact gives a valid way to prove nonexistence by finding two conflicting paths. The second displayed question asks about the opposite-looking situation, where many paths agree. Agreement along selected families of paths is not presented as a substitute for the full definition of limit existence.

At the cut to the outro, the mathematics stops. The speaker moves into channel promotion, asking viewers to leave questions in the comments, like the video, and continue with a larger multivariable calculus playlist. No answer to either open question is supplied inside this excerpt.

Knowledge cards

01

Main multivariable example and its singular point

The clip centers on f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} and asks about lim⁡(x,y)→(0,0)f(x,y)\lim_{(x,y)\to(0,0)} f(x,y). The function is not defined at (0,0)(0,0) because the denominator x2+y2x^2+y^2 vanishes there, so the lecture separates the issue of the function value from the issue of the limiting behavior.

f(x,y)=xyx2+y2,lim⁡(x,y)→(0,0)f(x,y)=???f(x,y)=\frac{xy}{x^2+y^2},\qquad \lim_{(x,y)\to(0,0)} f(x,y)=???
02

Why the plotted surface can mislead at the singularity

The presenter warns that the 3D graph near (0,0)(0,0) is only an approximation. Plotting software interpolates between nearby sampled points and never evaluates the undefined point itself, so the visual “pinch” should motivate analysis rather than replace it.

03

One-variable rule: unequal one-sided limits mean no limit

For the piecewise function f(x)=1f(x)=1 when x<1x<1 and f(x)=2f(x)=2 when x≥1x\ge1, the left-hand limit at x=1x=1 is 1 and the right-hand limit is 2. Since these do not match, lim⁡x→1f(x)\lim_{x\to1} f(x) does not exist.

lim⁡x→1−f(x)=1≠2=lim⁡x→1+f(x),lim⁡x→1f(x) DNE\lim_{x\to1^-}f(x)=1\ne 2=\lim_{x\to1^+}f(x),\qquad \lim_{x\to1}f(x)\text{ DNE}
04

A missing function value does not prevent a limit from existing

The second one-variable example, f(x)=1f(x)=1 for x≠1x\ne1, is undefined at x=1x=1 but approaches 1 from both sides. Hence the two-sided limit exists and equals 1, illustrating the difference between a removable hole and a genuine failure of the limit.

f(x)=1, x≠1,lim⁡x→1f(x)=1f(x)=1,\ x\ne1,\qquad \lim_{x\to1}f(x)=1
05

Path-restriction method for multivariable limits

To investigate the multivariable problem, the lecturer restricts the input to a chosen path through the target point. Selecting the line y=xy=x turns f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} into a single-variable expression, making it possible to use ordinary one-variable limit techniques.

Restrict to y=x\text{Restrict to }y=x
06

Computation along the path y=xy=x

Substituting y=xy=x gives x2x2+x2=x22x2\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2}, and for x≠0x\ne0 this simplifies to 12\frac12. Therefore the limit along that particular path is 12\frac12. The excerpt stops here and does not state the final conclusion for the full two-variable limit.

lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12
07

Example function and point of interest

The lecture studies f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} near the origin. The formula is undefined at (0,0)(0,0), and the whole segment investigates whether a limit exists as (x,y)→(0,0)(x,y)\to(0,0) by comparing different approaches to that point.

f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
08

Restricting to a path reduces the problem to one variable

The method shown is to impose a relation between xx and yy, such as y=xy=x or y=−xy=-x, and substitute it into the function. This turns the multivariable question into an ordinary one-variable limit problem, which the lecturer describes as reusing the old one-dimensional concept of a limit.

Substitute y=x or y=−x into f(x,y).\text{Substitute } y=x \text{ or } y=-x \text{ into } f(x,y).
09

Limit along y=xy=x is 1/21/2

With y=xy=x, the function becomes x2x2+x2=x22x2\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2}. For x≠0x\neq 0 this simplifies to 12\frac12, so the displayed path-limit is lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12.

lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12
10

Limit along y=−xy=-x is -1/2

With y=−xy=-x, the numerator becomes −x2-x^2 while the denominator remains 2x22x^2. Thus the restricted expression is −x22x2\frac{-x^2}{2x^2}, and the displayed path-limit is −12-\frac12.

lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12
11

Unequal path limits imply nonexistence at (0,0)

Because the same function approaches 12\frac12 along one line through the origin and −12-\frac12 along another, the lecturer concludes that the full multivariable limit at (0,0)(0,0) does not exist. The visual contrast between the two diagonals on the surface plot supports this path-dependence argument.

12≠−12⇒lim⁡(x,y)→(0,0)xyx2+y2 does not exist\frac12\neq -\frac12 \Rightarrow \lim_{(x,y)\to(0,0)}\frac{xy}{x^2+y^2}\text{ does not exist}
12

Two-path test for nonexistence

The general rule stated on screen is: if f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to(x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to(x_0,y_0)} f(x,y) does not exist. The lecturer names this the two-path test for a limit not existing.

If two path-limits differ, then the multivariable limit does not exist.\text{If two path-limits differ, then the multivariable limit does not exist.}
13

The test proves only nonexistence

A key caution in the clip is that the two-path test is one-sided in logical force: it can certify that a limit does not exist, but it cannot certify that a limit does exist. Matching values along some paths do not settle the existence question.

14

Future Question 1: what does existence mean?

After establishing nonexistence by counterexample, the lecture asks how to define what it means for a multivariable limit to exist at a point. This is presented as the next conceptual task, not answered here.

15

Future Question 2: are straight lines enough?

The final prompt asks whether agreement along every straight line through the point would guarantee existence of the full multivariable limit. The clip raises this issue explicitly but leaves the answer for later.

16

Two-path test for nonexistence of a multivariable limit

The video explicitly states a sufficient criterion for showing that a two-variable limit fails to exist: if f(x,y)f(x,y) approaches different values along two different paths ending at (x0,y0)(x_0,y_0), then the full limit lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to (x_0,y_0)} f(x,y) does not exist. This is a method for disproving existence only; the clip does not claim that matching path-limits prove existence.

If f(x,y) has two different limits along two different paths (x,y)→(x0,y0), then lim⁡(x,y)→(x0,y0)f(x,y) does not exist.\text{If } f(x,y) \text{ has two different limits along two different paths } (x,y)\to (x_0,y_0), \text{ then } \lim_{(x,y)\to (x_0,y_0)} f(x,y) \text{ does not exist.}
17

Open question: what does it mean for a multivariable limit to exist?

Question 1 on the board asks how one defines a limit existing at a point. In this clip it is posed as a conceptual prompt rather than answered, and it sets up the later doubt about whether checking only certain paths is enough.

18

Open question: do all straight lines suffice?

Question 2 asks whether agreement along every straight-line path forces the limit to exist. The speaker immediately contrasts straight lines with a curvy path, indicating that the full path space matters and that straight-line agreement alone is not treated as settled evidence in this excerpt.

19

Straight-line agreement versus curvy-path behavior

The audio emphasizes a key distinction: even if every straight-line path gives the same result, one can still ask what happens along a nonlinear route. This highlights why multivariable limits are subtler than single-variable limits and why path choice matters.

20

Clip ends before resolving the conceptual questions

After 18 seconds the video switches to an outro asking for comments, likes, and playlist viewing. No proof, counterexample, or final answer to the two displayed questions appears within this excerpt.

Detailed learning notes

Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.

Symbols · 24

f(x,y)f(x,y)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Top-left formula reads f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

  2. Audio
    Observation

    Speaker says “for a multivariable function like f of x y equal to x y over x squared plus y squared.”

Symbol

f(x,y)f(x,y)

Meaning

Two-variable function used as the main example in the clip.

Domain

Defined for (x,y) with x2+y2≠0x^2+y^2 \neq 0; not defined at (0,0).

x, y

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Formula uses variables x and y in xy/(x2+y2x^2+y^2).

  2. Audio
    Observation

    Speaker refers to approaching the point “zero zero” in the x-y plane.

Symbol

x, y

Meaning

Independent real variables of the multivariable function.

Domain

Real numbers, subject to the denominator restriction x2+y2≠0x^2+y^2 \neq 0 for f.

lim⁡(x,y)→(0,0)f(x,y)\lim_{(x,y)\to(0,0)} f(x,y)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text shows lim_{(x,y)->(0,0)} f(x,y)f(x,y) = ???.

  2. Audio
    Observation

    Speaker asks what the limit is as x,y gets closer and closer to 0,0.

Symbol

lim⁡(x,y)→(0,0)f(x,y)\lim_{(x,y)\to(0,0)} f(x,y)

Meaning

Limit of the two-variable function as the input approaches the origin.

Domain

Questioned value; the clip does not state the final answer.

f(x)={1,x<12,x≥1f(x)=\begin{cases}1,&x<1\\2,&x\ge 1\end{cases}

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen piecewise definition: f(x)=1f(x)=1 if x<1x<1, and f(x)=2f(x)=2 if x>=1.

  2. Audio
    Observation

    Speaker describes the same one-dimensional piecewise function.

Symbol

f(x)={1,x<12,x≥1f(x)=\begin{cases}1,&x<1\\2,&x\ge 1\end{cases}

Meaning

One-variable piecewise example used to explain nonexistence of a limit at x=1x=1.

Domain

All real x; discontinuity at x=1x=1.

lim⁡x→1−f(x)\lim_{x\to1^-} f(x),\ lim⁡x→1+f(x)\lim_{x\to1^+} f(x)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text shows lim_{x->1^-} f(x)=1f(x)=1 != 2=lim⁡2 = \lim _{x->1^+} f(x)f(x), followed by “so lim_{x->1} f(x)f(x) DNE”.

  2. Audio
    Observation

    Speaker says the left-hand limit is 1, the right-hand limit is 2, and therefore the limit did not exist.

Symbol

lim⁡x→1−f(x)\lim_{x\to1^-} f(x),\ lim⁡x→1+f(x)\lim_{x\to1^+} f(x)

Meaning

Left-hand and right-hand limits of the one-variable piecewise function at x=1x=1.

Domain

Approach to x=1x=1 from below and above.

f(x)=1f(x)=1,\ x≠1x\ne 1

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text reads f(x)=1f(x)=1, x != 1.

  2. Audio
    Observation

    Speaker says the function is not defined at one point but equals 1 on both sides.

Symbol

f(x)=1f(x)=1,\ x≠1x\ne 1

Meaning

One-variable constant function with a single missing point at x=1x=1.

Domain

All real x except x=1x=1.

lim⁡x→1f(x)=1\lim_{x\to1} f(x)=1

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text shows lim_{x->1^-} f(x)=1=1=lim⁡f(x)=1=1=\lim _{x->1^+} f(x)f(x), then so lim_{x->1} f(x)=1f(x)=1.

  2. Audio
    Observation

    Speaker concludes the limit exists and equals 1.

Symbol

lim⁡x→1f(x)=1\lim_{x\to1} f(x)=1

Meaning

Two-sided limit of the punctured constant function at x=1x=1.

Domain

Limit statement about approach to x=1x=1, not the value f(1)f(1).

y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Red text says “Restrict to line y=xy=x”.

  2. Audio
    Observation

    Speaker says “let me demand that y is equal to x” and calls it a restriction.

Symbol

y=xy=x

Meaning

Chosen path through the origin used to reduce the multivariable problem to one variable.

Domain

Line in the xy-plane passing through (0,0).

f(x)=x2x2+x2=x22x2f(x)=\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2}

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen derivation writes f(x)=x2/(x2+x2)=x2/(2x2)f(x)=x^2/(x^2+x^2)=x^2/(2x^2).

  2. Audio
    Observation

    Speaker says after substituting y=xy=x, one is left with x squared over x squared plus x squared, which is x squared over 2x squared.

Symbol

f(x)=x2x2+x2=x22x2f(x)=\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2}

Meaning

Single-variable expression obtained by restricting the original multivariable function to the path y=xy=x.

Domain

Valid for x≠0x \neq 0 along the chosen path.

lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text shows lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

  2. Audio
    Observation

    Speaker states the resulting one-variable limit equals one half.

Symbol

lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12

Meaning

Limit of the restricted function along the path y=xy=x as x approaches 0.

Domain

Pathwise limit only; the clip does not claim this is the full two-variable limit.

f(x,y)f(x,y)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The displayed function is f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}.

  2. Audio
    Observation

    The lecturer refers to this as the function under study throughout the clip.

Symbol

f(x,y)f(x,y)

Meaning

A two-variable real-valued function used as the main example for testing multivariable limits.

Domain

The displayed formula is defined when x2+y2≠0x^2+y^2\neq 0, so (x,y)≠(0,0)(x,y)\neq(0,0); the video explicitly discusses behavior near (0,0)(0,0).

x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    xx appears in f(x,y)f(x,y), in the restricted expressions, and in lim⁡x→0\lim_{x\to 0}.

  2. Audio
    Observation

    The lecturer says the restriction changes yy equal to xx or yy equal to minus xx.

Symbol

x

Meaning

One independent variable of the two-variable function; after restriction it also serves as the single parameter along the chosen line.

Knowledge points · 15

Central question: limit of a multivariable function at an undefined point

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Formula f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) appears with a 3D surface plot.

  2. Audio
    Observation

    Speaker introduces the topic as the limit of a function as it approaches a point for a multivariable function.

  3. Formula
    Observation

    At 28s the screen adds lim_{(x,y)->(0,0)} f(x,y)f(x,y) = ???.

Definition
Explanation

The clip frames the main problem as determining the behavior of f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) as (x,y) approaches (0,0), even though the function itself is not defined there. The speaker explicitly connects the issue to the denominator becoming zero at that point.

Formula
f(x,y)=xyx2+y2,lim⁡(x,y)→(0,0)f(x,y)=???f(x,y)=\frac{xy}{x^2+y^2},\qquad \lim_{(x,y)\to(0,0)} f(x,y)=???
Conditions
  1. The function is considered near (0,0).

  2. At (0,0) the denominator is zero, so f(0,0)f(0,0) is undefined.

Graphical caution about plotting the singular point

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A 3D surface plot remains on screen while the speaker discusses the pinch at (0,0).

  2. Audio
    Observation

    Speaker says the graph is only an approximation because the computer interpolates between nearby points but never exactly at (0,0).

Method
Explanation

The speaker warns that the displayed surface should not be trusted literally at the singular point because plotting software fills in values by interpolation from nearby sampled points rather than evaluating the undefined point itself.

Formula
Conditions
  1. Applies when visualizing functions with a point of undefined value.

  2. The picture is a computational approximation, not a proof of the limiting value.

Prerequisites
  1. Central question: limit of a multivariable function at an undefined point

One-variable reminder: unequal one-sided limits imply no limit

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Piecewise definition f(x)=1f(x)=1 for x<1x<1 and f(x)=2f(x)=2 for x>=1 is shown.

  2. Formula
    Observation

    On-screen text gives lim_{x->1^-} f(x)=1f(x)=1 != 2=lim⁡2 = \lim _{x->1^+} f(x)f(x), then “so lim_{x->1} f(x)f(x) DNE”.

  3. Diagram
    Observation

    A step graph shows a jump at x=1x=1.

Method
Explanation

To prepare for the multivariable case, the video revisits a one-dimensional piecewise function and uses mismatched left and right limits at x=1x=1 to explain why the two-sided limit does not exist.

Formula
f(x)={1,x<12,x≥1,lim⁡x→1−f(x)=1≠2=lim⁡x→1+f(x),lim⁡x→1f(x) DNEf(x)=\begin{cases}1,&x<1\\2,&x\ge 1\end{cases},\qquad \lim_{x\to1^-}f(x)=1\ne 2=\lim_{x\to1^+}f(x),\qquad \lim_{x\to1}f(x)\text{ DNE}
Conditions
  1. The comparison point is x=1x=1.

  2. The left-hand and right-hand limits are different.

One-variable reminder: a missing point does not prevent a limit from existing

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen text reads f(x)=1f(x)=1, x != 1.

  2. Formula
    Observation

    Then lim_{x->1^-} f(x)=1=1=lim⁡f(x)=1=1=\lim _{x->1^+} f(x)f(x), so lim_{x->1} f(x)=1f(x)=1.

  3. Diagram
    Observation

    A horizontal line at height 1 is shown with a missing point at x=1x=1.

Method
Explanation

The second one-dimensional example contrasts with the first: although the function is undefined at x=1x=1, the values on both sides approach the same number, so the limit exists and equals 1.

Formula
f(x)=1, x≠1,lim⁡x→1−f(x)=1=1=lim⁡x→1+f(x),lim⁡x→1f(x)=1f(x)=1,\ x\ne 1,\qquad \lim_{x\to1^-}f(x)=1=1=\lim_{x\to1^+}f(x),\qquad \lim_{x\to1}f(x)=1
Conditions
  1. The function is undefined only at x=1x=1.

  2. Approach from both sides yields the same value.

Prerequisites
  1. One-variable reminder: unequal one-sided limits imply no limit

Pathwise restriction method for multivariable limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says one way to grapple with the problem is to restrict to a particular direction, a particular line.

  2. Formula
    Observation

    Red text says “Restrict to line y=xy=x”.

  3. Formula
    Observation

    Derivation on screen substitutes y=xy=x into f(x,y)f(x,y) and simplifies to x2/(2x2)x^2/(2x^2).

  4. Formula
    Observation

    Final displayed line gives lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

Method
Explanation

The video introduces a standard strategy for investigating a multivariable limit: choose a path through the target point, substitute the path equation into the function, and study the resulting one-variable limit. Here the chosen path is y=xy=x, producing a restricted expression whose limit as x->0 is 1/21/2.

Formula
Restrict to y=x:xyx2+y2↦x2x2+x2=x22x2,lim⁡x→0x22x2=12\text{Restrict to }y=x:\quad \frac{xy}{x^2+y^2}\mapsto \frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2},\qquad \lim_{x\to0}\frac{x^2}{2x^2}=\frac12
Conditions
  1. The path must pass through the point being approached, here (0,0).

  2. Substitution reduces the multivariable expression to one variable.

  3. The computed value is a pathwise limit, not automatically the full two-variable limit.

Prerequisites
  1. Central question: limit of a multivariable function at an undefined point
  2. One-variable reminder: unequal one-sided limits imply no limit
  3. One-variable reminder: a missing point does not prevent a limit from existing

Main example function for multivariable limit behavior

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}.

  2. Diagram
    Observation

    A 3D surface plot of this function is shown with a highlighted path through the origin.

Definition
Explanation

The clip uses the rational two-variable function f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} as the central example. The lecturer studies its behavior near the origin by restricting the function to different paths and comparing the resulting one-variable limits.

Formula
f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
Conditions
  1. The displayed formula is considered away from (0,0)(0,0) because the denominator vanishes there.

  2. The clip focuses on behavior as (x,y)→(0,0)(x,y)\to(0,0).

Restricting a multivariable function to a path

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer says he did not need a new definition for the limit in a higher-dimensional context; he put a restriction on and it became the old one-dimensional concept of a limit.

  2. Formula
    Observation

    The board substitutes y=xy=x into f(x,y)f(x,y) to obtain a one-variable expression.

Method
Explanation

The method demonstrated is to replace one variable by an expression in the other variable, thereby reducing the two-variable problem to a one-variable limit problem. In this clip the chosen restrictions are the straight lines y=xy=x and y=−xy=-x.

Formula
Substitute a path relation such as y=x or y=−x into f(x,y).\text{Substitute a path relation such as } y=x \text{ or } y=-x \text{ into } f(x,y).
Conditions
  1. The chosen path must pass through the point where the limit is being tested.

  2. The substitution produces a single-variable expression whose limit can be computed by ordinary one-variable methods.

Prerequisites
  1. Main example function for multivariable limit behavior

Limit along the line y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The displayed computation is f(x)=x2x2+x2=x22x2f(x)=\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2} and lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12.

  2. Audio
    Observation

    The lecturer says the result is one half.

Formula
Explanation

When the function is restricted to the line y=xy=x, the numerator becomes x2x^2 and the denominator becomes 2x22x^2, so the restricted expression simplifies to 12\frac12 for x≠0x\neq 0. Therefore the one-variable limit as x→0x\to 0 along this path is 12\frac12.

Formula
lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12
Conditions
  1. This is the limit along the specific path y=xy=x.

  2. The simplification is valid for x≠0x\neq 0 before taking the limit.

Prerequisites
  1. Main example function for multivariable limit behavior
  2. Restricting a multivariable function to a path

Limit along the line y=−xy=-x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The displayed computation is f(x)=−x2x2+x2=−x22x2f(x)=\frac{-x^2}{x^2+x^2}=\frac{-x^2}{2x^2} and lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12.

  2. Audio
    Observation

    The lecturer says the result is minus one half and contrasts it with plus one half on the previous line.

Formula
Explanation

When the function is restricted to the line y=−xy=-x, the numerator becomes −x2-x^2 while the denominator remains 2x22x^2. The restricted expression simplifies to −12-\frac12 for x≠0x\neq 0, so the one-variable limit as x→0x\to 0 along this path is −12-\frac12.

Formula
lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12
Conditions
  1. This is the limit along the specific path y=−xy=-x.

  2. The simplification is valid for x≠0x\neq 0 before taking the limit.

Prerequisites
  1. Main example function for multivariable limit behavior
  2. Restricting a multivariable function to a path

Name and purpose of the two-path test

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer explicitly calls the criterion "the two path test for a limit not existing."

  2. Formula
    Observation

    A boxed theorem statement appears on screen.

Definition
Explanation

The clip names the criterion the two-path test for a limit not existing. Its purpose is to prove nonexistence of a multivariable limit by exhibiting two approaches to the same point that give different limiting values.

Formula
Conditions
  1. It is used to conclude that a multivariable limit does not exist.

  2. It does not establish existence of the limit.

Prerequisites
  1. Limit along the line y=xy=x
  2. Limit along the line y=−xy=-x

Open question about defining existence of a multivariable limit

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    On-screen text reads "Question 1: How do we define a limit existing at a point?"

  2. Audio
    Observation

    The lecturer asks what exactly a limit existing in the multivariable context means.

Definition
Explanation

After showing that different paths can produce different limits, the lecturer raises the next conceptual issue: how to define what it means for a multivariable limit to exist at a point. This is presented as a future topic rather than answered in the clip.

Formula
Conditions
  1. This is a forward-looking question introduced at the end of the segment.

  2. No formal definition is given within this clip.

Prerequisites
  1. Name and purpose of the two-path test

Open question about whether all straight-line paths suffice

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    On-screen text reads "Question 2: Suppose that approaching along any STRAIGHT line gives the same value. Does the limit necessarily exist?"

  2. Audio
    Observation

    The lecturer begins introducing the second question after noting that he has been focusing on straight lines.

Definition
Explanation

The second forward-looking question asks whether agreement of the limiting value along every straight line through the point is enough to guarantee existence of the full multivariable limit. The clip poses the question but does not resolve it.

Formula
Conditions
  1. This is a forward-looking question introduced at the end of the segment.

  2. The clip does not provide the answer within the available duration.

Prerequisites
  1. Name and purpose of the two-path test
Claims and conditions · 9

The example function is undefined at the origin

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says the function is not defined at x=0x=0, y=0y=0 because there becomes a zero in the denominator.

  2. Formula
    Observation

    The displayed formula has denominator x2+y2x^2+y^2.

Proposition
Statement

For f(x,y)f(x,y)=xy/(x2+y2x^2+y^2), the function is not defined at (0,0) because the denominator x2+y2x^2+y^2 equals 0 there.

Hypotheses
  1. f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

  2. Evaluate at (x,y)=(0,0).

Quantifiers

At the specific point (0,0).

Unequal one-sided limits imply the two-sided limit does not exist

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows lim_{x->1^-} f(x)=1f(x)=1 != 2=lim⁡2 = \lim _{x->1^+} f(x)f(x).

  2. Formula
    Observation

    Screen then states so lim_{x->1} f(x)f(x) DNE.

  3. Audio
    Observation

    Speaker says the left and right do not match, so the limit did not exist.

Proposition
Statement

If the left-hand limit and right-hand limit at a point are different, then the two-sided limit at that point does not exist.

Hypotheses
  1. The one-sided limits at the point exist or are being compared.

  2. They have different values.

Quantifiers

Applied to x=1x=1 in the displayed example.

A function can have a limit at a point where it is undefined

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows f(x)=1f(x)=1, x != 1.

  2. Formula
    Observation

    Then lim_{x->1^-} f(x)=1=1=lim⁡f(x)=1=1=\lim _{x->1^+} f(x)f(x), so lim_{x->1} f(x)=1f(x)=1.

  3. Audio
    Observation

    Speaker says that in this case the limit did exist and was equal to 1.

Proposition
Statement

For f(x)=1f(x)=1 with x != 1, the limit as x approaches 1 exists and equals 1 even though f(1)f(1) is not defined.

Hypotheses
  1. f(x)=1f(x)=1 for all x != 1.

  2. Approach x=1x=1 from both sides.

Quantifiers

At the point x=1x=1.

Along the path y=xy=x, the restricted limit equals 1/21/2

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    On-screen derivation shows f(x)=x2/(x2+x2)=x2/(2x2)f(x)=x^2/(x^2+x^2)=x^2/(2x^2).

  2. Formula
    Observation

    Final line shows lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

  3. Audio
    Observation

    Speaker says the restricted expression is x squared over 2x squared and the limit is one half.

Uncertainties
  1. The clip does not state whether this pathwise result determines the full multivariable limit.

Proposition
Statement

After restricting f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) to the line y=xy=x, the resulting one-variable limit as x approaches 0 is 1/21/2.

Hypotheses
  1. Use the path y=xy=x.

  2. Take x -> 0 along that path.

Quantifiers

For approach to (0,0) constrained to the line y=xy=x.

Two-path test for nonexistence of a multivariable limit

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The boxed statement reads: "If f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to(x_0,y_0) then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to(x_0,y_0)} f(x,y) does not exist."

  2. Audio
    Observation

    The lecturer paraphrases this as: if one path gives some limit and another path gives a different limit, then for sure the limit does not exist.

Theorem
Statement

If f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to(x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to(x_0,y_0)} f(x,y) does not exist.

Hypotheses
  1. There are two distinct paths approaching (x0,y0)(x_0,y_0).

  2. The limit of f(x,y)f(x,y) along each path exists.

  3. The two path-limits are different.

Quantifiers

For a function of two variables and a point (x0,y0)(x_0,y_0), existence of two unequal path-limits implies nonexistence of the full multivariable limit.

Conclusion for the example function at the origin

Clear evidence
Derived from the video
Evidence
  1. Audio
    Observation

    The lecturer concludes there is no limit for this function as (x,y)(x,y) goes to (0,0)(0,0).

  2. Formula
    Observation

    Earlier displayed path computations give 12\frac12 along y=xy=x and −12-\frac12 along y=−xy=-x.

Proposition
Statement

For f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}, the limit as (x,y)→(0,0)(x,y)\to(0,0) does not exist.

Hypotheses
  1. Along y=xy=x, the restricted limit is 12\frac12.

  2. Along y=−xy=-x, the restricted limit is −12-\frac12.

  3. These two path-limits are different.

Quantifiers

At the specific point (0,0)(0,0) for this specific function.

Scope limitation of the two-path test

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer says, "Now this test only tells us when a limit does not exist."

  2. Caption evidence
    Observation

    The subsequent on-screen questions ask what existence means and whether straight-line agreement suffices.

Proposition
Statement

The two-path test only establishes nonexistence of a multivariable limit; it does not establish existence.

Hypotheses
  1. The criterion being discussed is the two-path test for nonexistence.

Quantifiers

For the test named in the clip.

Different path limits imply nonexistence of the multivariable limit

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The boxed theorem-like statement directly asserts that two different path-limits imply nonexistence of the overall limit.

Proposition
Statement

If f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to (x_0,y_0), then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to (x_0,y_0)} f(x,y) does not exist.

Hypotheses
  1. ff is a function of two variables.

  2. There are two different paths approaching (x0,y0)(x_0,y_0).

  3. The limits of f(x,y)f(x,y) along those two paths are different.

Quantifiers

For a given f(x,y)f(x,y) and point (x0,y0)(x_0,y_0), existence of two distinct paths with unequal limiting values is sufficient to conclude nonexistence of the full limit.

Whether agreement along all straight lines guarantees limit existence is left open in this clip

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    On-screen Question 2 asks whether agreement along any straight line forces the limit to exist.

  2. Audio
    Observation

    The speaker asks whether a curvy path could change the limit or whether only straight lines matter.

Uncertainties
  1. The clip does not provide the final answer or counterexample within this excerpt.

Conjecture
Statement

Suppose that approaching along any straight line gives the same value. Does the limit necessarily exist?

Hypotheses
  1. All straight-line approaches to (x0,y0)(x_0,y_0) yield the same limiting value.

Quantifiers

Universal over straight-line paths; the status of the implication to full limit existence is posed as a question rather than settled here.

Derivations and proofs · 6

Derivation that the piecewise one-variable limit does not exist

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen displays lim_{x->1^-} f(x)=1f(x)=1 != 2=lim⁡2 = \lim _{x->1^+} f(x)f(x).

  2. Formula
    Observation

    Screen then displays so lim_{x->1} f(x)f(x) DNE.

  3. Audio
    Observation

    Speaker explains the left side is 1 and the right side is 2, so they do not match.

Proof
Steps
  1. Expression
    f(x)={1,x<12,x≥1f(x)=\begin{cases}1,&x<1\\2,&x\ge 1\end{cases}
    Explanation

    Start from the given piecewise definition.

    Justification

    Observed on-screen formula and spoken description.

    Shown in the video
  2. Expression
    lim⁡x→1−f(x)=1\lim_{x\to1^-} f(x)=1
    Explanation

    As x approaches 1 from the left, x<1x<1, so the function uses the branch equal to 1.

    Justification

    Direct reading of the piecewise definition.

    Shown in the video
  3. Expression
    lim⁡x→1+f(x)=2\lim_{x\to1^+} f(x)=2
    Explanation

    As x approaches 1 from the right, x>1x>1, so the function uses the branch equal to 2.

    Justification

    Direct reading of the piecewise definition.

    Shown in the video
  4. Expression
    1≠21\ne 2
    Explanation

    The two one-sided limits are different numbers.

    Justification

    Comparison of the previous two results.

    Shown in the video
  5. Expression
    lim⁡x→1f(x) DNE\lim_{x\to1} f(x)\text{ DNE}
    Explanation

    Therefore the two-sided limit at x=1x=1 does not exist.

    Justification

    Standard criterion: unequal one-sided limits imply nonexistence of the two-sided limit.

    Shown in the video
Conclusion

The one-variable piecewise example has no limit at x=1x=1 because its left and right limits differ.

Derivation that the punctured constant function has limit 1

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen displays f(x)=1f(x)=1, x != 1.

  2. Formula
    Observation

    Screen displays lim_{x->1^-} f(x)=1=1=lim⁡f(x)=1=1=\lim _{x->1^+} f(x)f(x), then so lim_{x->1} f(x)=1f(x)=1.

  3. Audio
    Observation

    Speaker says the function is equal to 1 on both sides and the limit exists and equals 1.

Proof
Steps
  1. Expression
    f(x)=1, x≠1f(x)=1,\ x\ne 1
    Explanation

    Start from the function that equals 1 everywhere except at the missing point x=1x=1.

    Justification

    Observed on-screen formula and spoken explanation.

    Shown in the video
  2. Expression
    lim⁡x→1−f(x)=1\lim_{x\to1^-} f(x)=1
    Explanation

    From the left of 1, the function value is constantly 1, so the left-hand limit is 1.

    Justification

    Constant behavior on the punctured domain.

    Shown in the video
  3. Expression
    lim⁡x→1+f(x)=1\lim_{x\to1^+} f(x)=1
    Explanation

    From the right of 1, the function value is also constantly 1, so the right-hand limit is 1.

    Justification

    Constant behavior on the punctured domain.

    Shown in the video
  4. Expression
    lim⁡x→1f(x)=1\lim_{x\to1} f(x)=1
    Explanation

    Since both one-sided limits agree, the two-sided limit exists and equals 1.

    Justification

    Matching one-sided limits criterion.

    Shown in the video
Conclusion

Even though f(1)f(1) is undefined, the limit as x approaches 1 exists and equals 1.

Derivation of the limit along the path y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Red text says Restrict to line y=xy=x.

  2. Formula
    Observation

    Screen shows f(x)=x2/(x2+x2)=x2/(2x2)f(x)=x^2/(x^2+x^2)=x^2/(2x^2).

  3. Formula
    Observation

    Screen shows lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

  4. Audio
    Observation

    Speaker says to plug the x value wherever there is a y, leaving x squared over x squared plus x squared, then x squared over 2x squared.

Uncertainties
  1. The clip does not continue to compare other paths or state the final conclusion about the full multivariable limit.

Proof
Steps
  1. Expression
    f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
    Explanation

    Begin with the original multivariable function.

    Justification

    Observed on-screen formula.

    Shown in the video
  2. Expression
    y=xy=x
    Explanation

    Choose the line y=xy=x as a path through the origin.

    Justification

    Explicitly stated restriction in audio and red on-screen text.

    Shown in the video
  3. Expression
    x⋅xx2+x2\frac{x\cdot x}{x^2+x^2}
    Explanation

    Substitute y=xy=x into numerator and denominator.

    Justification

    Algebraic substitution along the chosen path.

    Shown in the video
  4. Expression
    x22x2\frac{x^2}{2x^2}
    Explanation

    Simplify x⋅x=x2x\cdot x=x^2 and x2+x2=2x2x^2+x^2=2x^2.

    Justification

    Elementary algebra.

    Shown in the video
  5. Expression
    lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12
    Explanation

    For x≠0x\ne 0 along the path, the ratio simplifies to 1/21/2, so the pathwise limit is 1/21/2.

    Justification

    Cancellation of the common factor x2x^2 away from x=0x=0, then taking the limit.

    Shown in the video
Conclusion

Along the specific path y=xy=x, the restricted one-variable limit is 1/21/2.

Derivation of the limit along y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows f(x)=x2x2+x2=x22x2f(x)=\frac{x^2}{x^2+x^2}=\frac{x^2}{2x^2} and then lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12.

  2. Audio
    Observation

    The lecturer explains that imposing the restriction turns the problem into an old one-dimensional limit computation.

Proof
Steps
  1. Expression
    f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
    Explanation

    Start from the given two-variable function.

    Justification

    Displayed on the board.

    Shown in the video
  2. Expression
    y=xy=x
    Explanation

    Restrict to the line y=xy=x.

    Justification

    Stated by the red label "Restrict to line y=xy=x".

    Shown in the video
  3. Expression
    f(x)=x⋅xx2+x2=x22x2f(x)=\frac{x\cdot x}{x^2+x^2}=\frac{x^2}{2x^2}
    Explanation

    Substitute y=xy=x into the function and simplify the denominator.

    Justification

    Direct algebraic substitution shown on the board.

    Shown in the video
  4. Expression
    lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12
    Explanation

    Cancel the common factor x2x^2 for x≠0x\neq 0 and take the one-variable limit.

    Justification

    Displayed computation and spoken conclusion "which is one half."

    Shown in the video
Conclusion

Along the path y=xy=x, the limiting value is 12\frac12.

Derivation of the limit along y=−xy=-x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board updates to f(x)=−x2x2+x2=−x22x2f(x)=\frac{-x^2}{x^2+x^2}=\frac{-x^2}{2x^2} and then lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12.

  2. Audio
    Observation

    The lecturer says the new restriction introduces minus signs and yields minus one half.

Proof
Steps
  1. Expression
    f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
    Explanation

    Start again from the same two-variable function.

    Justification

    The original formula remains on the board.

    Shown in the video
  2. Expression
    y=−xy=-x
    Explanation

    Change the restriction to the line y=−xy=-x.

    Justification

    Stated by the updated red label "Restrict to line y=−xy=-x".

    Shown in the video
  3. Expression
    f(x)=x(−x)x2+(−x)2=−x22x2f(x)=\frac{x(-x)}{x^2+(-x)^2}=\frac{-x^2}{2x^2}
    Explanation

    Substitute y=−xy=-x and simplify.

    Justification

    Direct algebraic substitution shown on the board.

    Shown in the video
  4. Expression
    lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12
    Explanation

    Cancel x2x^2 for x≠0x\neq 0 and evaluate the one-variable limit.

    Justification

    Displayed computation and spoken conclusion "minus one half."

    Shown in the video
Conclusion

Along the path y=−xy=-x, the limiting value is −12-\frac12.

Using two different path-limits to conclude nonexistence

Clear evidence
Derived from the video
Evidence
  1. Audio
    Observation

    The lecturer compares the two results and concludes there is no limit at (0,0)(0,0).

  2. Formula
    Observation

    The boxed theorem states that two different path-limits imply nonexistence of the multivariable limit.

Proof
Steps
  1. Expression
    lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12
    Explanation

    One path gives limiting value 12\frac12.

    Justification

    Previously derived along y=xy=x.

    Shown in the video
  2. Expression
    lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12
    Explanation

    Another path gives limiting value −12-\frac12.

    Justification

    Previously derived along y=−xy=-x.

    Shown in the video
  3. Expression
    12≠−12\frac12\neq -\frac12
    Explanation

    The two path-limits are different.

    Justification

    Immediate comparison of the computed values.

    Derived from the video
  4. Expression
    lim⁡(x,y)→(0,0)xyx2+y2 does not exist\lim_{(x,y)\to(0,0)}\frac{xy}{x^2+y^2}\text{ does not exist}
    Explanation

    Therefore the full multivariable limit at the origin does not exist.

    Justification

    By the two-path test stated on screen.

    Shown in the video
Conclusion

Because two different approaches to (0,0)(0,0) yield different limits, the multivariable limit of f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} at (0,0)(0,0) does not exist.

Worked examples · 4

Main example: investigate lim_{(x,y)->(0,0)} xy/(x2+y2x^2+y^2)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Main displayed function is f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

  2. Diagram
    Observation

    A 3D surface plot accompanies the formula throughout the opening and closing sections.

  3. Formula
    Observation

    Later the screen asks lim_{(x,y)->(0,0)} f(x,y)f(x,y)=??? and then computes the restriction to y=xy=x.

Uncertainties
  1. The clip stops after one path computation and does not present the final verdict for the full two-variable limit.

Problem

Determine how to analyze the limit of f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) as (x,y) approaches (0,0), where the function is undefined.

Given
  1. f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

  2. The point of interest is (0,0).

  3. The denominator vanishes at (0,0).

Goal

Understand what the limit means and begin evaluating it by path restriction.

Steps
  1. Expression
    f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}
    Explanation

    Identify the function under investigation.

    Justification

    Displayed formula and spoken introduction.

    Shown in the video
  2. Expression
    (x,y)→(0,0)(x,y)\to(0,0)
    Explanation

    Focus on approach to the origin, not the value at the origin.

    Justification

    Speaker explicitly asks what happens as x,y get closer and closer to 0,0.

    Shown in the video
  3. Expression
    Restrict to y=x\text{Restrict to }y=x
    Explanation

    Choose a particular path through the origin to reduce the problem to one variable.

    Justification

    Speaker introduces path restriction as a way to grapple with the problem.

    Shown in the video
  4. Expression
    lim⁡x→0x22x2=12\lim_{x\to0}\frac{x^2}{2x^2}=\frac12
    Explanation

    Compute the resulting one-variable limit along that path.

    Justification

    Shown algebraically on screen and stated aloud.

    Shown in the video
Answer

The clip obtains the pathwise value 1/21/2 along y=xy=x, but it does not state the final answer for the full two-variable limit within this excerpt.

Verification

Verification would require comparing multiple paths or applying a rigorous definition of the multivariable limit; that comparison is not shown in this clip.

Supporting example: one-variable piecewise jump

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Piecewise function and one-sided limit statements are shown on screen.

  2. Diagram
    Observation

    Step graph illustrates the jump at x=1x=1.

Problem

Use a one-dimensional example to explain when a limit fails to exist.

Given
  1. f(x)=1f(x)=1 for x<1x<1.

  2. f(x)=2f(x)=2 for x>=1.

Goal

Decide whether lim_{x->1} f(x)f(x) exists.

Steps
  1. Expression
    lim⁡x→1−f(x)=1\lim_{x\to1^-} f(x)=1
    Explanation

    Left branch gives value 1.

    Justification

    Piecewise definition.

    Shown in the video
  2. Expression
    lim⁡x→1+f(x)=2\lim_{x\to1^+} f(x)=2
    Explanation

    Right branch gives value 2.

    Justification

    Piecewise definition.

    Shown in the video
  3. Expression
    lim⁡x→1f(x) DNE\lim_{x\to1} f(x)\text{ DNE}
    Explanation

    Because the one-sided limits differ, the two-sided limit does not exist.

    Justification

    Standard limit criterion.

    Shown in the video
Answer

The limit does not exist at x=1x=1.

Verification

The mismatch 1 != 2 directly verifies nonexistence.

Supporting example: one-variable removable hole

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows f(x)=1f(x)=1, x != 1 and the matching one-sided limits.

  2. Diagram
    Observation

    Horizontal line with a missing point at x=1x=1.

Problem

Show that a function can have a limit at a point where it is not defined.

Given
  1. f(x)=1f(x)=1 for all x != 1.

Goal

Evaluate lim_{x->1} f(x)f(x).

Steps
  1. Expression
    lim⁡x→1−f(x)=1\lim_{x\to1^-} f(x)=1
    Explanation

    Approach from the left stays on the constant branch 1.

    Justification

    Definition of the punctured constant function.

    Shown in the video
  2. Expression
    lim⁡x→1+f(x)=1\lim_{x\to1^+} f(x)=1
    Explanation

    Approach from the right also stays on the constant branch 1.

    Justification

    Definition of the punctured constant function.

    Shown in the video
  3. Expression
    lim⁡x→1f(x)=1\lim_{x\to1} f(x)=1
    Explanation

    Matching one-sided limits imply the two-sided limit exists and equals 1.

    Justification

    Standard limit criterion.

    Shown in the video
Answer

The limit exists and equals 1, despite f(1)f(1) being undefined.

Verification

Equality of the two one-sided limits verifies existence.

Worked example: testing the limit of xy/(x2+y2x^2+y^2) at (0,0)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The entire clip works with f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} and computes path limits at the origin.

  2. Audio
    Observation

    The lecturer uses this example to motivate the two-path test.

Problem

Determine whether lim⁡(x,y)→(0,0)xyx2+y2\lim_{(x,y)\to(0,0)}\frac{xy}{x^2+y^2} exists by comparing limits along different paths.

Given
  1. f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}

  2. Path 1: y=xy=x

  3. Path 2: y=−xy=-x

  4. Target point: (0,0)(0,0)

Goal

Decide whether the full multivariable limit at (0,0)(0,0) exists.

Steps
  1. Expression
    Restrict to y=x\text{Restrict to } y=x
    Explanation

    Replace yy by xx to obtain a one-variable function along the first path.

    Justification

    Demonstrated method in the lecture.

    Shown in the video
  2. Expression
    lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12
    Explanation

    The limit along y=xy=x equals 12\frac12.

    Justification

    Shown algebraically on the board and stated aloud.

    Shown in the video
  3. Expression
    Restrict to y=−x\text{Restrict to } y=-x
    Explanation

    Replace yy by −x-x to obtain a one-variable function along the second path.

    Justification

    Demonstrated method in the lecture.

    Shown in the video
  4. Expression
    lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12
    Explanation

    The limit along y=−xy=-x equals −12-\frac12.

    Justification

    Shown algebraically on the board and stated aloud.

    Shown in the video
  5. Expression
    12≠−12\frac12\neq -\frac12
    Explanation

    The two path-limits disagree.

    Justification

    Direct comparison of the computed values.

    Derived from the video
  6. Expression
    lim⁡(x,y)→(0,0)xyx2+y2 does not exist\lim_{(x,y)\to(0,0)}\frac{xy}{x^2+y^2}\text{ does not exist}
    Explanation

    Therefore the multivariable limit at the origin does not exist.

    Justification

    By the two-path test for nonexistence.

    Shown in the video
Answer

The limit does not exist at (0,0)(0,0).

Verification

Verification is internal to the method: two explicit paths approaching the same point produce different limiting values, which triggers the stated two-path test.

Visual events · 11

Opening title animation

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    Black chalkboard background with animated handwritten title text appearing in sequence.

  2. Caption evidence
    Observation

    Title reads LIMITS OF MULTIVARIABLE FUNCTIONS.

Objects
  1. Chalkboard background

  2. Handwritten title text

Changes
  1. Words appear sequentially until the full title is visible.

Invariants
  1. No mathematical formula is shown yet.

  2. No speaker is visible.

Interpretation

This segment serves as a title card introducing the topic before the lecture content begins.

Multivariable surface plot with singularity highlighted

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    Left side shows a 3D surface plot with axes labeled roughly from -2 to 2 in x and y and about -1 to 1 vertically.

  2. Formula
    Observation

    Top-left formula f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) is visible.

  3. Formula
    Observation

    Pink annotation Problematic at (0,0)! points toward the origin region.

  4. Formula
    Observation

    At 28s the line lim_{(x,y)->(0,0)} f(x,y)f(x,y) = ??? appears.

Uncertainties
  1. Exact axis tick labels are small; the broad ranges are clear but fine readings are approximate.

Objects
  1. 3D surface plot

  2. Formula f(x,y)f(x,y)=xy/(x2+y2x^2+y^2)

  3. Pink arrow annotation

  4. Limit question text

  5. Presenter on the right

Changes
  1. The limit question appears after the initial setup.

  2. The presenter gestures toward the pinch region of the surface.

Invariants
  1. The surface remains the same example function throughout this interval.

  2. The highlighted problematic location is (0,0).

Interpretation

The visualization supports the verbal point that the origin is a singular pinch point and that the plotted surface is only an interpolation-based approximation near that point.

One-variable jump graph

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    2D graph shows a horizontal red segment at y=1y=1 for x<1x<1 and another at y=2y=2 for x>=1.

  2. Formula
    Observation

    Piecewise definition and one-sided limit statements are displayed above the graph.

Objects
  1. Coordinate grid

  2. Two horizontal red segments

  3. Piecewise formula

  4. One-sided limit formulas

Changes
  1. The graph replaces the earlier 3D surface.

  2. Text builds from the function definition to the mismatched one-sided limits and DNE conclusion.

Invariants
  1. The discontinuity is located at x=1x=1.

  2. The left level is 1 and the right level is 2.

Interpretation

The picture concretizes the abstract rule that unequal left and right limits produce nonexistence of the two-sided limit.

One-variable removable-hole graph

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A horizontal red line at y=1y=1 is shown with a missing point at x=1x=1.

  2. Formula
    Observation

    Text reads f(x)=1f(x)=1, x != 1 and then the matching one-sided limits leading to limit = 1.

Objects
  1. Coordinate grid

  2. Horizontal red line at y=1y=1

  3. Gap at x=1x=1

  4. Limit formulas

Changes
  1. The previous jump graph is replaced by a single-level graph with a puncture.

  2. The text changes from DNE to an existing limit equal to 1.

Invariants
  1. The function value is 1 everywhere it is defined in the displayed window.

  2. The only exceptional point is x=1x=1.

Interpretation

The visual contrast with the previous example shows that missing the value at a point is different from having incompatible approaches from the two sides.

Path restriction visualized on the multivariable surface

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The 3D surface plot returns on the left.

  2. Formula
    Observation

    Red text says Restrict to line y=xy=x.

  3. Animation
    Observation

    A red line is drawn across the surface corresponding to the path y=xy=x.

  4. Formula
    Observation

    Derivation text appears stepwise: f(x)=x2/(x2+x2)=x2/(2x2)f(x)=x^2/(x^2+x^2)=x^2/(2x^2), then lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

Uncertainties
  1. The exact geometric thickness and endpoints of the red path line are visual approximations, but the intended path y=xy=x is explicit.

Objects
  1. 3D surface plot

  2. Red path line

  3. Restriction label

  4. Algebraic derivation text

  5. Presenter

Changes
  1. The scene returns from 1D examples to the original 2D function.

  2. A red line is overlaid to indicate the chosen path.

  3. The algebraic reduction and final pathwise limit appear in sequence.

Invariants
  1. The underlying function remains f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

  2. The chosen path remains y=xy=x once introduced.

Interpretation

The animation links the abstract substitution y=xy=x to a concrete curve on the surface, showing how a multivariable problem is reduced to a one-variable limit along that path.

Surface plot with highlighted path y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A 3D surface plot of f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2} is shown with a red line marking the path y=xy=x through the origin.

  2. Formula
    Observation

    The red label reads "Restrict to line y=xy=x".

Uncertainties
  1. The exact axis orientation is visible but not fully labeled in every frame; the mathematical meaning is clear from the formulas and narration.

Objects
  1. 3D surface of f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}

  2. red line on the surface

  3. coordinate axes

  4. formula panel

Changes
  1. The red highlighted path corresponds to y=xy=x.

  2. The displayed algebra updates from the general function to the restricted one-variable expression.

Invariants
  1. The underlying function remains f(x,y)=xyx2+y2f(x,y)=\frac{xy}{x^2+y^2}.

  2. The point of interest is the origin.

Interpretation

The visual emphasizes that approaching the origin along the line y=xy=x produces a definite height trend corresponding to the computed limit 12\frac12.

Surface plot switches to the path y=−xy=-x

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The red highlighted line changes to the opposite diagonal, matching the label "Restrict to line y=−xy=-x".

  2. Formula
    Observation

    The algebra changes to −x22x2\frac{-x^2}{2x^2} and the limit to −12-\frac12.

Objects
  1. same 3D surface

  2. new red line on the opposite diagonal

  3. updated formula panel

Changes
  1. The highlighted path changes from y=xy=x to y=−xy=-x.

  2. The displayed restricted expression changes sign in the numerator.

  3. The computed limit changes from 12\frac12 to −12-\frac12.

Invariants
  1. The surface itself does not change.

  2. The target point remains the origin.

Interpretation

The visual contrast shows that a different straight-line approach to the same point can lead to a different limiting height, supporting path dependence.

On-screen theorem box for the two-path test

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    A boxed statement appears: "If f(x,y)f(x,y) has two different limits along two different paths (x,y)→(x0,y0)(x,y)\to(x_0,y_0) then lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to(x_0,y_0)} f(x,y) does not exist."

  2. Audio
    Observation

    The lecturer names this the two-path test for a limit not existing.

Objects
  1. boxed theorem text

  2. lecturer speaking beside it

Changes
  1. The clip shifts from the worked example to a general criterion.

Invariants
  1. The example function has already established unequal path-limits.

Interpretation

The box formalizes the reasoning used in the example: unequal path-limits imply nonexistence of the full multivariable limit.

Closing question prompts on screen

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    Text appears reading "Question 1: How do we define a limit existing at a point?" and then "Question 2: Suppose that approaching along any STRAIGHT line gives the same value. Does the limit necessarily exist?"

  2. Audio
    Observation

    The lecturer introduces these as two future questions.

Objects
  1. two on-screen question statements

  2. lecturer

Changes
  1. The presentation moves from the nonexistence test to open conceptual questions.

Invariants
  1. The discussion remains about multivariable limits and path-based reasoning.

Interpretation

The visuals signal that the current clip proves nonexistence by counterexample paths, but does not yet define existence or settle whether straight-line agreement is sufficient.

Static theorem-and-questions board during the conceptual discussion

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A lecturer stands before a dark chalkboard-style background with a white-bordered box at upper left containing the two-path theorem text, plus two numbered questions below.

  2. Animation
    Observation

    The speaker gestures while talking; no mathematical diagram changes occur during this interval.

Objects
  1. Lecturer

  2. White-bordered theorem box

  3. Question 1 text

  4. Question 2 text

  5. Chalkboard-style background

Changes
  1. Only the speaker's hand gestures change.

  2. The displayed mathematical text remains fixed throughout this interval.

Invariants
  1. The theorem statement about two different path limits stays visible.

  2. Question 1 and Question 2 remain on screen unchanged.

Interpretation

The visual layout separates a known sufficient criterion for nonexistence from two unresolved conceptual questions about how to define limit existence and whether straight-line agreement is enough.

Scene change to outro setting

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    At 18 seconds the scene cuts to a different room with acoustic foam panels, a desk microphone, a laptop, and a monitor displaying 'SUBSCRIBE'.

  2. Animation
    Observation

    The speaker points downward and later gives a thumbs-up while delivering the outro.

Objects
  1. Lecturer in different shirt

  2. Monitor with 'SUBSCRIBE'

  3. Desk microphone

  4. Laptop

  5. Acoustic foam wall panels

Changes
  1. Background changes completely from chalkboard-style lecture frame to office/studio setup.

  2. Speaker gestures shift from explanatory hand motions to pointing and thumbs-up.

Invariants
  1. No new mathematical content appears after the cut.

Interpretation

This visual transition marks the end of the mathematical discussion and the start of channel promotion.

Misconceptions · 7

Do not treat the plotted surface as exact at the undefined point

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says when he tries to graph something like this, it is only an approximation because the computer is interpolating between nearby points but never equal to 0,0.

Misconception

One may think the computer-generated graph shows the true value or limiting behavior at (0,0) because the surface appears continuous there.

Clarification

The speaker explicitly warns that the plot is interpolated from nearby sampled points and does not evaluate the undefined point itself, so the picture alone should not settle the limit question.

Undefined at a point does not automatically mean the limit fails

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows f(x)=1f(x)=1, x != 1 and then lim_{x->1} f(x)=1f(x)=1.

  2. Audio
    Observation

    Speaker contrasts a function not defined at one point with the existence of its limit there.

Misconception

Students may conflate “the function is not defined here” with “the limit does not exist here.”

Clarification

The clip’s second one-variable example shows that even when f(1)f(1) is missing, the limit can still exist if both sides approach the same value.

A single path computation is not by itself the full multivariable limit

Approximate timing
Supplementary explanation
Evidence
  1. Formula
    Observation

    The clip computes only one path, y=xy=x, and obtains 1/21/2.

  2. Audio
    Observation

    Speaker introduces path restriction as one way to start grappling with the problem, not as a completed proof of the full limit.

Uncertainties
  1. This caution is an analyst-added clarification; the excerpt itself does not explicitly warn against overinterpreting a single path.

Misconception

One might infer from the displayed value 1/21/2 that the full limit lim_{(x,y)->(0,0)} f(x,y)f(x,y) has already been determined.

Clarification

Editorial clarification: the excerpt only evaluates the function along the chosen path y=xy=x. To decide the full two-variable limit, one would need additional argument or comparison with other paths, which is not shown in this clip.

Mistaking the two-path test for an existence criterion

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer explicitly says the test only tells us when a limit does not exist.

  2. Caption evidence
    Observation

    The follow-up questions ask what existence means and whether straight-line agreement suffices.

Misconception

One might think that checking paths and getting matching values proves the multivariable limit exists.

Clarification

The clip states that the two-path test only proves nonexistence when two paths give different limits. It does not establish existence, and the lecturer raises the separate question of what existence really means.

Assuming all straight-line paths are sufficient to decide the limit

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    Question 2 asks whether agreement along any STRAIGHT line guarantees existence.

  2. Audio
    Observation

    The lecturer notes that he has been focusing on straight lines and introduces this as a remaining issue.

Uncertainties
  1. The clip poses the question but does not answer it within the available duration.

Misconception

One might assume that if every straight line through the point gives the same limiting value, then the full multivariable limit must exist.

Clarification

The video explicitly raises this as an open question rather than asserting it as true. Within this clip, straight-line agreement is not shown to be sufficient.

Mistaking agreement on all straight-line paths for proof of full limit existence

Clear evidence
Shown in the video
Evidence
  1. Caption evidence
    Observation

    Question 2 explicitly asks whether agreement along any straight line implies the limit exists.

  2. Audio
    Observation

    The speaker follows by asking what happens if one approaches along a curvy path and whether that could change the limit.

Misconception

One might think that if every straight-line approach gives the same value, then the multivariable limit must exist.

Clarification

The video treats this as an open question and immediately contrasts straight lines with curvy paths, signaling that straight-line agreement alone is not presented as sufficient evidence for the full limit.

Confusing a nonexistence test with an existence test

Clear evidence
Derived from the video
Evidence
  1. Formula
    Observation

    The displayed statement only concludes nonexistence from two different path limits.

  2. Audio
    Observation

    From the wording of the theorem, the implication runs from unequal path limits to nonexistence, not the reverse.

Misconception

One might incorrectly read the two-path rule as saying that matching path limits prove the limit exists.

Clarification

The displayed proposition is one-directional: different path limits imply nonexistence. It does not state that equal path limits imply existence.

Concept relations · 12

Pathwise restriction method for multivariable limits → One-variable reminder: unequal one-sided limits imply no limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says, “To help me understand this, let’s go back to the one-dimensional case.”

  2. Formula
    Observation

    The video switches from the 2D function to two 1D examples before returning to the 2D problem.

Prerequisite
Explanation

The clip uses one-variable limit reasoning as preparation for understanding pathwise restriction in the multivariable example.

One-variable reminder: unequal one-sided limits imply no limit → One-variable reminder: a missing point does not prevent a limit from existing

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    First 1D example ends with DNE because one-sided limits differ.

  2. Formula
    Observation

    Second 1D example ends with limit = 1 despite the function being undefined at the point.

Contrast
Explanation

The two one-variable examples are deliberately contrasted: mismatched sides destroy the limit, while a lone missing point does not.

Pathwise restriction method for multivariable limits → Central question: limit of a multivariable function at an undefined point

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker returns to the multivariable case and says one way to grapple with it is to restrict to a particular line.

  2. Formula
    Observation

    The restriction y=xy=x is applied directly to f(x,y)f(x,y)=xy/(x2+y2x^2+y^2).

Application
Explanation

The path-restriction method is introduced specifically as a tool for investigating the central multivariable limit question.

One-variable reminder: unequal one-sided limits imply no limit → Pathwise restriction method for multivariable limits

Clear evidence
Derived from the video
Evidence
  1. Formula
    Observation

    After substituting y=xy=x, the problem becomes lim_{x->0} x2/(2x2)x^2/(2x^2).

  2. Audio
    Observation

    Speaker says the restriction makes the multivariable function into a single-variable function that we know how to do.

Proof dependency
Explanation

Once a path is chosen, the multivariable question is handled using ordinary one-variable limit techniques, which the preceding examples review.

Restricting a multivariable function to a path → Limit along the line y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer says putting a restriction made it the old one-dimensional concept of a limit.

  2. Formula
    Observation

    The board converts f(x,y)f(x,y) into a one-variable expression after substituting y=xy=x.

Application
Explanation

The method of restricting to a path is applied to compute the one-variable limit along y=xy=x.

Worked example: testing the limit of xy/(x2+y2x^2+y^2) at (0,0) → Two-path test for nonexistence of a multivariable limit

Clear evidence
Derived from the video
Evidence
  1. Audio
    Observation

    The lecturer moves from the two computed path-limits to the named criterion.

  2. Formula
    Observation

    The boxed theorem generalizes the example's reasoning.

Proof dependency
Explanation

The worked example supplies the concrete unequal path-limits that motivate and instantiate the general two-path test.

Two-path test for nonexistence of a multivariable limit → Conclusion for the example function at the origin

Clear evidence
Derived from the video
Evidence
  1. Audio
    Observation

    The lecturer concludes there is no limit at (0,0)(0,0) after comparing the two path results.

  2. Formula
    Observation

    The theorem box states that different path-limits imply nonexistence.

Application
Explanation

The general two-path test is applied to the specific function to conclude that its limit at the origin does not exist.

Scope limitation of the two-path test → Open question about defining existence of a multivariable limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    After saying the test only proves nonexistence, the lecturer asks what existence means.

  2. Caption evidence
    Observation

    Question 1 appears on screen.

Contrast
Explanation

The limitation of the test motivates the separate question of how to define existence of a multivariable limit.

Restricting a multivariable function to a path → Open question about whether all straight-line paths suffice

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The lecturer notes he has been focusing on straight lines and introduces the second question.

  2. Caption evidence
    Observation

    Question 2 asks whether agreement along any straight line suffices.

Contrast
Explanation

The clip's method uses straight-line restrictions, and the final question contrasts that with the unresolved issue of whether straight lines alone are enough to decide existence.

Two-path test for nonexistence of a multivariable limit → Open question 2: agreement on all straight lines versus full limit existence

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The boxed theorem concerns two different paths and nonexistence.

  2. Caption evidence
    Observation

    Question 2 asks about all straight lines giving the same value and whether the limit then exists.

Contrast
Explanation

The first item gives a valid way to disprove existence by finding unequal path limits, while the second item asks about the converse-style situation where many paths agree; the contrast highlights that agreement along selected paths is not treated like the proven nonexistence criterion.

Open question 1: definition of a limit existing at a point → Open question 2: agreement on all straight lines versus full limit existence

Clear evidence
Derived from the video
Evidence
  1. Caption evidence
    Observation

    Question 1 asks how to define a limit existing at a point.

  2. Caption evidence
    Observation

    Question 2 asks whether straight-line agreement forces existence.

Prerequisite
Explanation

Answering whether straight-line agreement suffices depends on having a precise definition of what it means for a multivariable limit to exist.

Two-path test for nonexistence of a multivariable limit → lim⁡(x,y)→(x0,y0)\lim_{(x,y)\to (x_0,y_0)}

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The theorem is stated for lim⁡(x,y)→(x0,y0)f(x,y)\lim_{(x,y)\to (x_0,y_0)} f(x,y).

Application
Explanation

The two-path nonexistence method is applied specifically to the multivariable limit notation shown on screen.

Find an answer · 19

What is the main limit problem introduced at the start of the clip?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) and later lim_{(x,y)->(0,0)} f(x,y)f(x,y)=???.

  2. Audio
    Observation

    Speaker introduces the limit of a multivariable function as it approaches a point.

Knowledge points
  1. Central question: limit of a multivariable function at an undefined point

Why is f(x,y)f(x,y)=xy/(x2+y2x^2+y^2) not defined at (0,0)?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says there becomes a zero in the denominator at x=0x=0, y=0y=0.

  2. Formula
    Observation

    Denominator is x2+y2x^2+y^2.

Knowledge points
  1. Central question: limit of a multivariable function at an undefined point
  2. The example function is undefined at the origin

Why does the presenter say the plotted surface is only an approximation near the singular point?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says the graph is only an approximation because the computer interpolates between nearby points.

Knowledge points
  1. Graphical caution about plotting the singular point
  2. Do not treat the plotted surface as exact at the undefined point

Why does the one-variable piecewise example have no limit at x=1x=1?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows lim_{x->1^-} f(x)=1f(x)=1 != 2=lim⁡2 = \lim _{x->1^+} f(x)f(x), so lim_{x->1} f(x)f(x) DNE.

Knowledge points
  1. One-variable reminder: unequal one-sided limits imply no limit
  2. Unequal one-sided limits imply the two-sided limit does not exist
  3. Derivation that the piecewise one-variable limit does not exist

Can a limit exist when the function is undefined at the point being approached?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen shows f(x)=1f(x)=1, x != 1 and then lim_{x->1} f(x)=1f(x)=1.

Knowledge points
  1. One-variable reminder: a missing point does not prevent a limit from existing
  2. A function can have a limit at a point where it is undefined
  3. Derivation that the punctured constant function has limit 1

What method does the video introduce for beginning to analyze a multivariable limit?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    Speaker says one way to grapple with the problem is to restrict to a particular direction, a particular line.

  2. Formula
    Observation

    Red text says Restrict to line y=xy=x.

Knowledge points
  1. Pathwise restriction method for multivariable limits

How is the value 1/21/2 obtained after restricting to the line y=xy=x?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Screen derives f(x)=x2/(x2+x2)=x2/(2x2)f(x)=x^2/(x^2+x^2)=x^2/(2x^2) and then lim_{x->0} x2/(2x2)=1/2x^2/(2x^2)=1/2.

Knowledge points
  1. Pathwise restriction method for multivariable limits
  2. Along the path y=xy=x, the restricted limit equals 1/21/2
  3. Derivation of the limit along the path y=xy=x

Does computing the limit along just one path determine the full multivariable limit?

Approximate timing
Supplementary explanation
Evidence
  1. Formula
    Observation

    Only one path, y=xy=x, is evaluated in the excerpt.

  2. Audio
    Observation

    Speaker presents path restriction as a way to start grappling with the problem.

Uncertainties
  1. The excerpt does not explicitly discuss the logical insufficiency of a single path for proving existence.

Knowledge points
  1. Pathwise restriction method for multivariable limits
  2. A single path computation is not by itself the full multivariable limit

What is the two-path test for showing a multivariable limit does not exist?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The boxed theorem statement is visible.

  2. Audio
    Observation

    The lecturer names the two-path test.

Knowledge points
  1. Name and purpose of the two-path test
  2. Two-path test for nonexistence of a multivariable limit

Why do different path limits imply the full limit does not exist?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The two displayed path-limits are 12\frac12 and −12-\frac12.

  2. Audio
    Observation

    The lecturer contrasts the previous line with the new line.

Knowledge points
  1. Two-path test for nonexistence of a multivariable limit
  2. Using two different path-limits to conclude nonexistence

What is the limit of xyx2+y2\frac{xy}{x^2+y^2} along the line y=xy=x?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows lim⁡x→0x22x2=12\lim_{x\to 0}\frac{x^2}{2x^2}=\frac12.

Knowledge points
  1. Limit along the line y=xy=x
  2. Derivation of the limit along y=xy=x

What is the limit of xyx2+y2\frac{xy}{x^2+y^2} along the line y=−xy=-x?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows lim⁡x→0−x22x2=−12\lim_{x\to 0}\frac{-x^2}{2x^2}=-\frac12.

Knowledge points
  1. Limit along the line y=−xy=-x
  2. Derivation of the limit along y=−xy=-x
Coverage and review notes

Covered · Title card only; no mathematical content beyond topic identification.

Covered · Introduction of f(x,y)f(x,y)=xy/(x2+y2x^2+y^2), the question of its limit at (0,0), and the warning that the plotted surface is interpolated near the singularity.

Covered · One-variable piecewise example showing unequal one-sided limits and nonexistence of the two-sided limit.

Covered · One-variable punctured constant example showing that a limit can exist even when the function is undefined at the point.

Covered · Return to the multivariable example and computation of the restricted limit along the path y=xy=x, yielding 1/21/2.

Covered · Final fraction of a second contains no new mathematical event beyond the already displayed pathwise result.

Covered · Opening computation of the limit along y=xy=x with surface plot and algebra.

Covered · Switch to the path y=−xy=-x, computation of the second limit, and visual contrast between the two paths.

Covered · General statement of the two-path test, conclusion of nonexistence for the example, and the two closing conceptual questions.

Covered · Mathematical content consists of the displayed two-path nonexistence rule and two open conceptual questions about multivariable limits.

Covered · No mathematical content is introduced in this interval; it is an outro asking for comments, likes, and playlist viewing.

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