Variance
This problem uses corrected sample variance: average the squared deviations with denominator n−1. For a sample of 6, the denominator is 5.
Six sampled pulse counts give mean 74, squared-deviation sum 180, corrected sample variance 36 and sample standard deviation 6. Bilingual notes explain the sample denominator and scope.
A class of 40 supplies a random sample of 6 students with pulse counts per minute 71, 83, 67, 74, 70, 79. The sample mean is 74 and the squared deviations sum to 180. Under the corrected sample-variance definition used here, divide by 6−1=5 to get sample variance 36; its nonnegative square root gives sample standard deviation 6. The class size 40 describes the sampling background, not the variance denominator. These sample statistics do not determine the whole class population parameters.
Generated from the video's visuals and explanation; not verbatim speech.
The class has 40 students, but the question gives pulse data for a random sample of 6: 71, 83, 67, 74, 70, 79. Establish that sample before choosing the formula.
The six observations total 444. Divide by the sample size 6 to obtain the mean 74, the reference for every deviation in this sample.
The corrected sample variance used in this problem has denominator 6 minus 1, which is 5. Neither the whole class size 40 nor the sample size 6 replaces that denominator.
Subtracting 74 gives deviations −3, 9, −7, 0, −4, 5. Squaring and adding gives 180; divide by 5 to get sample variance 36.
The nonnegative square root of 36 is the sample standard deviation 6, in the original pulse-count-per-minute unit. These are sample statistics, not a known population standard deviation for the entire class.
This problem uses corrected sample variance: average the squared deviations with denominator n−1. For a sample of 6, the denominator is 5.
The sum 444 divided by sample size 6 gives mean 74; all deviations use that same reference.
The class size is 40, but only 6 sampled values enter this statistic. The corrected sample variance denominator is 6−1=5.
The definition of sample variance demonstrated in the video is: first find the mean, then subtract the mean from each data point, square the result, sum them up, and finally divide by n-1. In this problem n=6, so the denominator is 5, not 6.
The data are 71, 83, 67, 74, 70, 79. First calculate the mean x̄=74, then calculate the sum of squared deviations 180, so the sample variance S²=180/5=36.
The sample standard deviation is the non-negative square root of the sample variance. In this problem, from S²=36, we get S=√36=6.
The corrected sample variance used here has denominator n−1: divide squared sum180 by5, not by6. Changing the denominator changes both the variance and standard deviation.
Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.
The screen displays "Arithmetic mean is x̄ = (71+83+67+74+70+79)/6 = 74"
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Sample arithmetic mean
Real numbers
The screen displays "S² = 1/(6-1) [(71-74)² + ... + (79-74)²]"
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
S^2
Sample variance
Non-negative real numbers
The screen displays "The arithmetic mean is x̄ = (71+83+67+74+70+79)/6 = 74".
Arithmetic mean of the sample data
Real numbers
The screen displays "S² = 1/(6-1)[(71-74)^2 + ... + (79-74)^2]", and finally calculates 36.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
S^2
Sample variance
Non-negative real numbers
The screen displays "The sample standard deviation is S = √36 = 6".
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
S
Sample standard deviation
Non-negative real numbers
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The denominator is written as 6-1, corresponding to sample size n=6.
n
Sample size
Positive integers
The screen provides the specific expansion of S² = 1/(n-1) Σ(x_i - x̄)², with the denominator explicitly written as 6-1
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The source uses the corrected sample-variance definition: sum squared deviations from the sample mean and divide by n−1. This problem computes sample statistics; it does not determine the exact class population variance or establish an unbiased standard deviation.
Use the corrected sample-variance convention in this source
Sample size n is greater than 1
Use the mean of this same sample
The screen displays x̄ = (71+83+67+74+70+79)/6 = 74
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Sum all sample observations and divide by the sample size n to obtain the center of the sample. This step is a necessary prerequisite for calculating variance.
All sample observations must be known
The screen gives S² = 1/(6-1)[(71-74)^2+(83-74)^2+(67-74)^2+(74-74)^2+(70-74)^2+(79-74)^2].
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The video demonstrates sample variance with specific data: first subtract the mean from each observation, then square the result, and finally sum these squared differences and divide by n-1. Here n=6, so the denominator is 6-1=5.
Sample data x_1,x_2,…,x_n must be known
The sample mean x̄ must be calculated first
The denominator uses n-1 instead of n
The screen displays "The sample standard deviation is S = √36 = 6".
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The video directly defines the sample standard deviation as the square root of the sample variance. Since S²=36 was calculated earlier, S=√36=6.
S² has been calculated first
Take the non-negative square root
The screen displays x̄=(71+83+67+74+70+79)/6=74.
The video first calculates the arithmetic mean of the six data points as the baseline for subsequent calculations of deviations from the mean.
Data consists of a finite number of values x_1,…,x_n
The screen step-by-step shows the summation of the numerator and division by 6, with the final result being 74
Substitute the six pulse rate data points
Definition of arithmetic mean
Calculate the sum 444 divided by 6
Basic arithmetic operation
The sample mean is 74
The screen displays S² = 1/(6-1) [(71-74)² + (83-74)² + (67-74)² + (74-74)² + (70-74)² + (79-74)²]
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The current 0–71-second interval sets up the formula; the full source later gives 36 and 6.
Substitute n=6 and x̄=74 into the sample variance formula
Definition of sample variance
Expand the squared deviation of each observation from the mean
Expansion of summation notation
This sets up sample variance with denominator 5; the full source then completes the squared sum and obtains 36.
The screen writes the expansion and simplification of S² step by step, giving final value36.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
First calculate the mean of the six data points.
Definition of arithmetic mean.
Subtract the mean from each data point, square the result, sum them up, and divide by 6-1.
Formula for sample variance.
Calculate each deviation from the mean: 71-74=-3, 83-74=9, 67-74=-7, 74-74=0, 70-74=-4, 79-74=5.
Algebraic simplification.
The sum of squares is 9+81+49+0+16+25=180, then multiply by 1/5.
Arithmetic calculation.
Sample variance S²=36.
The screen displays S=√36=6.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Sample standard deviation is defined as the square root of sample variance.
Relationship between standard deviation and variance.
Substitute S²=36 obtained in the previous step.
Arithmetic calculation.
Sample standard deviation S=6.
Problem text: The commerce class has 40 students. A random sample of 6 students' pulse rates per minute are 71, 83, 67, 74, 70, 79.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The first two steps are retained from 0–71 seconds; the full numerical results appear later in the complete source.
A class has40 students. A random sample of6 students provides pulse data; find the sample variance and sample standard deviation.
Population size N=40 (used only to describe the sampling context, does not participate in sample statistic calculation)
Sample data x_i ∈ {71, 83, 67, 74, 70, 79}
Sample size n=6
Calculate sample variance S² and sample standard deviation S
First calculate the sample mean as the center for the variance formula
Definition of arithmetic mean
Substitute into the sample variance formula, noting the denominator is n-1=5
Definition of sample variance
Full-source answer: sample variance 36 and sample standard deviation 6. This item retains the first two formula-setup steps.
Independent calculation gives squared-deviation sum 180, divided by 5 to get 36; its nonnegative square root is 6, matching the complete source result.
Problem text: "The commerce class has 40 students. A random sample of 6 students' pulse rates per minute are 71, 83, 67, 74, 70, 79. Then the sample variance of the pulse rate is ______, and the sample standard deviation is ______."
The solution area step-by-step calculates the mean 74, variance 36, and standard deviation 6.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Given a sample of 6 students' pulse rates per minute as 71, 83, 67, 74, 70, 79, find the sample variance and sample standard deviation.
Sample data: 71, 83, 67, 74, 70, 79
Sample size n=6
Total population size 40 is background information only and does not participate in the calculation
Find S² and S.
First calculate the mean.
Definition of arithmetic mean.
Apply the formula for sample variance.
Definition of sample variance.
Calculate the sum of squares and simplify.
Arithmetic operations.
Take the square root of the variance.
Definition of standard deviation.
The sample variance is 36, and the sample standard deviation is 6.
The screen finally fills the answers back into the blanks in the problem: fill 36 in the variance blank and 6 in the standard deviation blank.
In the white writing area, the mean formula and variance expansion appear sequentially; key numbers 74 and denominator 6-1 are clearly visible
Mean formula
Variance expansion
Yellow circular 'Solution' label
From blank writing area to displaying complete mean calculation
From mean result to displaying variance formula structure
Problem statement text remains fixed at the top of the screen
Publisher watermark position unchanged
Visually presents the logical sequence from raw data to statistical formulas, emphasizing the structural feature of the n-1 denominator
The yellow cursor first stays on the denominator 6-1.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Denominator 6-1
Yellow cursor
Cursor stops at the denominator position, indicating that the denominator here is not 6 but 6-1
The numerator structure remains the sum of squared deviations from the mean
Visually highlights the difference in the denominator between sample variance and population variance: n-1 is used here.
The cursor moves to the mean 74, then to the first parenthesis (71-74)^2.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Mean 74
(71-74)^2
Yellow cursor
Cursor points to 74 first, then to 71-74
All parentheses adopt the form 'data minus mean'
Explains that each term in the variance is the difference between a single data point and the mean.
The cursor sequentially scans (83-74)^2, (67-74)^2, (74-74)^2, (70-74)^2, (79-74)^2.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Six squared difference terms
Yellow cursor
Cursor points to each term sequentially according to the order of the data in the problem
Each term is (x_i-74)^2
There are six terms in total, corresponding to n=6
Maps the abstract formula to concrete data, showing that variance sums the squared deviations of all samples.
A new line =1/5[(-3)^2+9^2+(-7)^2+0^2+(-4)^2+5^2] appears on the screen, and the cursor pauses on each term again.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Newly appeared simplified line
Values -3, 9, -7, 0, -4, 5
Transforms from the form (x_i-74)^2 to the specific squared difference form
Number of terms remains six
Denominator remains 5
Visually displays the result of algebraic simplification, making the subsequent sum of squares calculation clearer.
First "The sample standard deviation is S=√36=6" appears, then the blanks in the problem are filled with red text 36 and 6.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
New standard deviation line at the bottom
Two blanks in the problem
Red answers 36, 6
Final standard deviation equation added to the solution area
Blanks in the problem change from empty to 36 and 6
Variance calculation result remains 36
Standard deviation calculation result remains 6
Maps the derived results back to the original problem, completing the fill-in-the-blank solution.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The variance denominator on the screen is written as 6-1 instead of 6
Believing that sample variance should also be divided by the sample size n
This problem explicitly uses corrected sample variance with denominator n−1. To describe a complete finite population, its variance instead divides squared deviations by the population size. This distinction does not assert that a standard-deviation estimator is unbiased or that the sample values determine the whole class population parameters.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The cursor stops on the denominator 6-1.
It is easy to mistakenly write the denominator of sample variance as the sample size n.
The video clearly states that this is sample variance, and the denominator should be n-1; in this problem n=6, so the denominator is 6-1=5.
The term (x_i - 74)² appears repeatedly in the variance expansion, where 74 is exactly the x̄ calculated in the previous step
The calculation of sample variance relies on the previously obtained sample mean as the baseline for deviations
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Defines the denominator rule and scope of application for sample variance by contrasting it with population variance
First x̄=74 is given; then S² repeatedly uses terms subtracting74.
The calculation of sample variance depends on first finding the mean, and then subtracting that mean from each data point.
The screen transitions from S²=36 to S=√36=6.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The sample standard deviation is directly obtained by taking the square root of the sample variance.
The denominator of the S² formula is explicitly written as 6-1
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
The narration distinguishes sample and population, then calculates the pulse data through the sample mean, corrected sample variance and sample standard deviation.
Fully displays the calculation from the mean to the sum of squares and then to 36.
S=√36=6.
Covered · Reading the problem and presenting conditions
Covered · Conceptual distinction between sample and population variance
Covered · Calculation of the mean
Covered · Currently establishing the sample variance formula from 62–71 seconds; the complete numerical result of the original video is in the subsequent part, which is not a missing item in the current input.
Covered · Presentation of the problem, calculation of the mean, expansion and simplification of the sample variance formula to 36.
Covered · Taking the square root of the variance to get the standard deviation 6, and filling 36 and 6 back into the problem blanks.
Reviewed current material begins with a random sample of six students from a class of forty and carefully separates sample size from population size while computing sample statistics.
This problem uses corrected sample variance: average the squared deviations with denominator n−1. For a sample of 6, the denominator is 5.