Arithmetic mean
The complete population has mean70 kilograms, from a total350 divided by5.
A complete population of five weights gives mean70kg, squared deviations720, variance144kg² and standard deviation12kg. Original bilingual notes distinguish population and sample denominators.
The five weights are67,79,55,61,88 kilograms, treated as the complete population. Find the mean70 kilograms, then calculate squared deviations from70 with sum720. Dividing by the population size5 gives population variance144 square kilograms; its nonnegative square root is the population standard deviation12 kilograms. This problem uses the population definition, not the sample-variance denominator.
Generated from the video's visuals and explanation; not verbatim speech.
Start with the object of the calculation: the question describes all five team members, so it uses population variance. Their weights are67,79,55,61,88 kilograms.
The weights sum to350. Divide by the population size5 to get the mean70 kilograms, the common reference for measuring deviations.
Subtract70 from each weight, square the deviations, add them and divide by5. Squaring prevents positive and negative deviations from canceling and gives larger deviations more weight.
The deviations are−3,9,−15,−9,18. Their squared sum is720, and their mean is the population variance144 square kilograms.
Take the nonnegative square root of the variance: the square root of144 is12. The unit returns to kilograms, giving a population standard deviation of12 kilograms.
The complete population has mean70 kilograms, from a total350 divided by5.
For this complete population, average the squared deviations from its own mean; the denominator is the population size5.
Subtract the population mean, square each deviation and take their mean. The result has squared units.
The deviations−3,9,−15,−9,18 give squared sum720. Divide by5 to obtain144 square kilograms.
The nonnegative square root of variance restores the original unit. Here the result is12 kilograms.
These five people are the entire population in the question. Use its size5; the sample variance formula is a different statistic, an editorial distinction.
Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.
The screen displays the arithmetic mean as μ = (67+79+55+61+88)/5 = 70
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
μ
Arithmetic mean (in this problem, the average weight of the five team members)
Real numbers
The screen displays the population variance as σ² = 1/5[(67-70)² + (79-70)² + (55-70)² + (61-70)² + (88-70)²]
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
σ²
Population variance
Non-negative real numbers
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The denominator in the formula is written as 5
n
Number of data points in the population (number of team members)
Positive integers
The screen displays "The arithmetic mean is μ = (67+79+55+61+88)/5 = 70".
The arithmetic mean of the dataset, i.e., the population mean
Real numbers; in this problem, the average weight of the data, unit is kilograms
The screen displays "The population variance is σ² = 1/5[(67-70)² + (79-70)² + (55-70)² + (61-70)² + (88-70)²]", subsequently simplified to 144.
Population variance, equal to the sum of squared deviations of each data point from the mean divided by the number of data points
Non-negative real numbers; the result for this problem is 144
The screen displays "The population standard deviation is σ = √144 = 12".
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Population standard deviation, equal to the non-negative square root of the population variance
Non-negative real numbers; the result for this problem is 12
The denominator in the mean and the coefficient in the variance both use 5.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
n
Number of data points / Population size
Positive integer; in this problem n=5
The formula substitutes 67, 79, 55, 61, 88 one by one, subtracts 70, and squares the result.
x_i
The i-th data value; in this problem, the weights of the five members
Real numbers; values in this problem are 67, 79, 55, 61, 88
μ = (67+79+55+61+88)/5 = 70
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The arithmetic mean μ is equal to the sum of all data values divided by the number of data points n. In this problem, the weights of the five team members are summed and divided by 5, resulting in an average weight of 70 kg.
Data consists of a finite number of numerical values
n > 0
σ² = 1/5[(67-70)² + (79-70)² + (55-70)² + (61-70)² + (88-70)²]
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The population variance σ² is defined as the sum of the squares of the differences between each data value and the population mean μ, divided by the number of data points n in the population. In this problem, μ=70 is found first, then the squared differences between each weight and 70 are calculated and averaged.
The population mean μ is known
The data represents the entire population rather than a sample
The screen introduces σ² = 1/5[(67-70)² + (79-70)² + (55-70)² + (61-70)² + (88-70)²] with the label "Population variance is".
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The video writes the population variance as the average of the squared deviations of the data from the mean: first subtract the mean μ from each data point x_i, then square it, and finally divide by the number of data points n. In this problem, n=5 and μ=70.
The data is treated as the entire population rather than a sample
μ is the mean of that population
n is the number of data points in the population
The screen displays "The population standard deviation is σ = √144 = 12".
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The video defines the population standard deviation as the square root of the population variance. Since the variance was calculated as 144, the standard deviation is √144=12.
σ² is the population variance
Take the non-negative square root
The screen displays μ=(67+79+55+61+88)/5=70.
The video first calculates the arithmetic mean of the five data points to serve as the baseline for subsequent deviation calculations.
n is the number of data points
In this problem n=5
Step-by-step display shows the numerator as 67+79+55+61+88, the denominator as 5, and the result as 70
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Substitute the weights of the five team members into the arithmetic mean formula
Definition of arithmetic mean
Calculate the sum of the numerator and divide by 5
Basic arithmetic operations
The average weight of the five team members is 70 kg.
The screen fully expands σ² = 1/5[(67-70)² + (79-70)² + (55-70)² + (61-70)² + (88-70)²]
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The0–60second interval sets up the formula; the full source later completes the results144 and12.
Substitute each weight and the previously calculated mean of 70 into the population variance formula
Definition of population variance
This sets up the population variance; the subsequent calculation of squared deviations gives the full-source result144 square kilograms.
The screen step-by-step shows σ² = 1/5[(67-70)²+(79-70)²+(55-70)²+(61-70)²+(88-70)²] = 1/5[(-3)²+9²+(-15)²+(-9)²+18²] = 1/5×720 = 144.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
First calculate the mean to serve as the baseline for each data point's deviation.
Definition of arithmetic mean.
Subtract the mean 70 from each of the five data points, square the results, add them up, and finally divide by 5.
Definition of population variance.
Calculate the differences inside the parentheses: 67-70=-3, 79-70=9, 55-70=-15, 61-70=-9, 88-70=18.
Algebraic simplification.
Sum the five squared terms to get 720.
Arithmetic summation; the video does not explicitly show the intermediate addition of 9, 81, 225, 81, 324, but the result can be verified.
Complete the division to obtain the population variance.
720÷5=144.
The population variance for this problem is 144.
The screen displays σ=√144=12.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Standard deviation is defined as the square root of the variance.
Definition of population standard deviation.
Substitute the variance 144 calculated in the previous step.
Substitution of equal quantities.
Calculate the square root.
12^2=144, and standard deviation takes the non-negative value.
The population standard deviation for this problem is 12.
Problem text: A cheerleading squad has 5 members whose weights (unit: kg) are 67, 79, 55, 61, and 88 respectively. The population variance of the weights is ______, and the population standard deviation is ______.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
These first two steps belong to0–60seconds; the complete answer is shown later in the full source.
Given the weights of 5 team members as 67, 79, 55, 61, and 88 kg, find the population variance and population standard deviation.
Dataset: {67, 79, 55, 61, 88}
Unit: kg
n = 5
Calculate population variance σ² and population standard deviation σ
First find the arithmetic mean as the baseline for variance calculation
Variance definition depends on the mean
Substitute into the population variance formula and expand the squared deviations from the mean
Definition of population variance
Full-source answer: population variance144 square kilograms and population standard deviation12 kilograms. This item retains the first two setup steps.
The correctness of the formula expansion can be verified by checking whether each squared deviation correctly corresponds to the original data and the mean of 70.
The problem text gives the weights of five members as 67, 79, 55, 61, 88, asking for the population variance and population standard deviation.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
A cheerleading squad has 5 members with weights (unit: kg) of 67, 79, 55, 61, and 88 respectively. Find the population variance and population standard deviation of the weights.
Data represents the entire population
n=5
x_1=67, x_2=79, x_3=55, x_4=61, x_5=88
Find σ² and σ.
First calculate the mean.
Definition of arithmetic mean.
Apply the population variance formula.
Definition of population variance.
Simplify differences, square, sum, and divide by 5.
Algebraic operations and arithmetic summation.
Take the square root of the variance to get the standard deviation.
Definition of population standard deviation.
The population variance is 144, and the population standard deviation is 12.
Reverse check: 12^2=144, and 144×5=720 matches the sum of the five squared deviations.
A white slide with a yellow frame displays the complete problem text and two blank lines for filling in answers
A yellow cursor sequentially points to the numbers and keywords in the problem
Problem text
Blank lines
Yellow cursor
Cursor moves from the title to each weight value
Cursor points to the blanks for 'population variance' and 'population standard deviation'
Problem text content remains unchanged
Background layout remains unchanged
Visual guidance via the cursor focuses the learner on key data and the solution goal.
After the circular icon with the character 'Solution' appears, the arithmetic mean formula emerges term by term
After the mean result 70 is displayed, the population variance formula is presented in its fully expanded form
'Solution' icon
Mean formula
Expanded variance formula
Formula goes from blank to fully displayed
Value 70 is filled into the variance formula
Formula structure and symbols remain consistent
The animation synchronizes with the instructor's speech rate to gradually reveal the calculation logic, reinforcing the derivation order from mean to variance.
A yellow cursor sequentially points to (67-70)², (79-70)², (55-70)², (61-70)², (88-70)² in the σ² formula.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
σ² formula
Five (x_i-70)² terms
Yellow cursor
Cursor moves from the first term to the fifth term
Each term is emphasized sequentially
Mean 70 remains unchanged
Number of data points 5 remains unchanged
Formula structure is sum of squared deviations divided by 5
Visually emphasizes that population variance is the average of the squared deviations of each data point relative to the mean.
The screen adds a line =1/5[(-3)²+9²+(-15)²+(-9)²+18²], then displays =1/5×720=144.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Original squared deviation expression
Simplified squared terms
720
144
Differences inside parentheses are calculated
Sum of squares is combined into 720
Dividing by 5 yields 144
Still the same σ² expression
Denominator remains 5
The animation transforms the abstract formula into concrete numerical calculation, explaining that the final value of variance comes from the average of the total squared deviations.
The blanks in the problem are first filled with 144, then a new line "Population standard deviation is σ=√144=12" appears below, and finally the second blank is filled with 12.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Two blanks in the problem
σ=√144=12 formula
Numbers 144 and 12
First blank changes from empty to 144
New standard deviation calculation line added
Second blank changes from empty to 12
The data itself remains unchanged
Variance result 144 remains unchanged
The visual sequence corresponds to the problem-solving flow: first find the variance, then derive the standard deviation from the variance, and finally fill the answers back into the problem blanks.
The problem explicitly states "population variance", and the formula on screen uses 1/5 instead of 1/(5-1).
The sample-population denominator contrast is editorial; the source explicitly uses the population formula.
Dividing all variances by n-1.
This problem involves population data, so the video adopts σ²=(1/n)Σ(x_i-μ)², meaning the denominator is n=5; if it were sample variance, the formula and denominator would be different.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The 70 in the variance formula comes directly from the previous step's mean result
Calculating population variance requires obtaining the population mean μ first. In this problem, μ=70 is a necessary input directly substituted into the variance formula.
First displays μ=70, then each term in the σ² formula subtracts 70.
Before calculating population variance, one must know the mean μ, because the deviation is x_i-μ.
The screen first obtains σ²=144, then writes σ=√144=12.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
Population standard deviation is directly obtained by taking the square root of the population variance.
The example fully applies the three formulas for mean, variance, and standard deviation.
The example is an application of these definitions to specific data.
μ = (67+79+55+61+88)/5 = 70
The formula uses 1/n instead of 1/(n-1)
The video does not explicitly contrast sample variance; this is a supplementary judgment by the analyst based on the formula form
The screen directly provides the population variance formula and calculation.
The formula uses 1/5, and the problem states there are 5 members.
The screen displays σ=√144=12.
The narration works through the population weights using the mean, the average squared deviation and the standard deviation in that order.
The blanks in the problem are filled with 144 and 12 sequentially.
Covered · Problem presentation and reading
Covered · Transition to solution steps
Covered · Arithmetic mean calculation
Covered · Connection to variance solution
Covered · Expansion of population variance formula
Covered · Screen presents the problem, mean, and original population variance formula; speaker reads out squared deviations term by term.
Covered · Displays simplified squared terms, 720, and 144, completing the population variance calculation.
Covered · Takes square root of σ²=144 to get σ=12, and fills both answers into the problem blanks.