Skip to content
Back to exploration
Calculus / English

limit of the multivariable function (KristaKingMath)

Krista King · YouTube · 6:43

Open original
READ & KEEP

The explanation, unpacked.

Reviewed learning material · Video analysis · English
Read the full overview

This 180-second chalkboard excerpt introduces a two-variable limit problem, lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}, and explains the strategy for deciding whether the limit exists. The speaker compares the situation to one-variable left and right limits, then draws the coordinate plane and marks the origin. Multiple yellow paths are added to illustrate approaching (0,0)(0,0) along the axes, the line y=xy=x, lines of the form y=mxy=mx, and the curve y=x2y=x^2. The key idea stated in the clip is that if two different paths give different limiting values, then the general multivariable limit does not exist. The speaker also warns that agreement along several tested paths is not enough to prove existence; for that, one must use the precise definition of the limit. No actual path substitutions or final numerical conclusion are completed within this excerpt. This 180-second whiteboard lesson solves the multivariable limit problem lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2} by testing two coordinate-axis paths. Along the y-axis, setting x=0x=0 gives −4y22y2=−2\frac{-4y^2}{2y^2}=-2. Along the x-axis, setting y=0y=0 gives x4x2=x2\frac{x^4}{x^2}=x^2, which tends to 0. Since -2\neq 0, the instructor concludes that the limit at the origin does not exist and boxes DNE. The clip ends with the caution that even equal results on two paths would not by itself prove existence. This video segment demonstrates how to evaluate the multivariable limit lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4 - 4y^2}{x^2 + 2y^2}. By applying the two-path test, the instructor calculates the limit along the y-axis, obtaining -2, and along the x-axis, obtaining 0. Since these values differ, the overall limit is concluded to not exist (DNE). The instructor also clarifies a common misconception: while testing different paths can disprove the existence of a limit, it cannot prove existence. If all tested paths yielded the same value, one would still need to use the precise epsilon-delta definition of a limit to rigorously prove it exists, as there are infinitely many possible paths of approach.

Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.

Chapters

0:00Problem statement: a limit at the origin0:20Analogy with one-sided limits0:50Sketching the plane and highlighting (0,0)1:05Approach paths: axes, y=xy=x, y=mx, y=x2y=x^21:40Directional limits versus the general limit2:10Search strategy and the need for the precise definition3:00Problem statement3:14Approach along the y-axis4:10Approach along the x-axis5:28Compare path limits and conclude DNE5:55Remark on further path testing6:00Introduction to the Two-Path Test6:15Conceptual Warning: Proving vs. Disproving Limits6:35Conclusion: Limit Does Not Exist

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

The clip opens on a chalkboard problem: find the limit of the two-variable rational function lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}, or state that it does not exist.

The instructor frames the method by analogy with single-variable calculus: instead of only comparing left and right limits, we must compare what happens when (x,y)(x,y) approaches the origin from many different directions in the plane.

A coordinate sketch is drawn, the origin is marked with a green dot, and the notation (0,0)(0,0) in the limit expression is highlighted to connect the algebraic target point with the geometric picture.

Yellow arrows are added one after another to represent candidate paths into the origin: the yy-axis, the xx-axis, the diagonal line y=xy=x, and later other straight-line directions such as y=mxy=mx.

The central logical point is stated explicitly: if two different paths produce two different limiting values, then the full two-variable limit cannot exist. This is the standard two-path test for nonexistence.

The explanation then distinguishes directional behavior from the general limit. A function may have a limit along a chosen path and still fail to have an overall limit at the point, because the general limit requires the same value for every possible approach.

A curved path corresponding to y=x2y=x^2 is also mentioned, broadening the idea beyond straight lines. The instructor emphasizes that to prove existence one would eventually need the precise definition of the limit, not just a list of successful path checks.

The practical workflow is laid out in order: first try the coordinate axes; if those agree, try y=xy=x or a general line y=mxy=mx; if those also agree, try still other lines; only after repeated agreement should one move to a rigorous epsilon-style proof of existence.

The excerpt ends before any substitution is carried out, so the board has established the strategy and geometry of the problem but has not yet computed a specific path limit or reached the final answer.

The clip opens on a blackboard problem asking for the limit of a two-variable function at the origin, or a statement that it does not exist. The displayed expression is lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)}\frac{x^4-4y^2}{x^2+2y^2}, and a small coordinate sketch with arrows toward the origin visually signals that different approach directions matter.

The instructor begins the first test path by moving along the y-axis. The key observation is that every point on that axis has x=0x=0, so the two-variable limit is rewritten as a restricted path limit lim⁡(0,y)→(0,0)\lim_{(0,y)\to(0,0)}. Substituting x=0x=0 into the function turns the numerator into −4y2-4y^2 and the denominator into 2y22y^2.

After substitution, the expression becomes −4y22y2\frac{-4y^2}{2y^2}. For y≠0y\neq 0, the common factor y2y^2 cancels, leaving the constant −2-2. Thus the function approaches −2-2 when the origin is reached along the y-axis.

The second test path is the x-axis. Here the defining condition is y=0y=0 everywhere on the path, so the limit is rewritten as lim⁡(x,0)→(0,0)\lim_{(x,0)\to(0,0)}. Substituting y=0y=0 removes the −4y2-4y^2 term in the numerator and the 2y22y^2 term in the denominator, leaving x4x2\frac{x^4}{x^2}.

The quotient x4x2\frac{x^4}{x^2} simplifies to x2x^2 for x≠0x\neq 0. Unlike the y-axis case, a variable expression remains, so the endpoint value is then substituted: as x→0x\to 0, x2→02=0x^2\to 0^2=0. Therefore the function approaches 00 along the x-axis.

With both path computations visible, the instructor compares the results: the y-axis gives −2-2, while the x-axis gives 00. Since −2≠0-2\neq 0, the two-variable limit cannot exist at (0,0)(0,0). The board records the inequality and then boxes the final answer DNE.

The closing remark adds an important methodological caution: if both tested paths had produced the same number, that agreement alone would not prove existence. One would still need to test additional paths before drawing any positive conclusion about the limit.

We are evaluating the limit of the function f(x,y)=x4−4y2x2+2y2f(x,y) = \frac{x^4 - 4y^2}{x^2 + 2y^2} as (x,y)(x,y) approaches (0,0)(0,0). The strategy is to approach the origin along different paths to check if the function yields different limiting values.

It is important to note that if every path we tested resulted in the same value, say -2, this would not be a proof that the limit exists. Because there are infinitely many ways to approach a point in a multivariable space, testing a finite number of paths is insufficient for a general proof. To rigorously prove existence, one must transition to the precise epsilon-delta definition of a limit.

However, in this specific case, we have already found two paths that give contradictory results. Approaching along the y-axis (x=0x=0) gives a limit of -2, while approaching along the x-axis (y=0y=0) gives a limit of 0. Since −2≠0-2 \neq 0, the two-path test successfully proves that the overall limit does not exist (DNE).

Knowledge cards

01

Two-variable limit problem at the origin

The featured problem asks for the behavior of a rational function of two variables as (x,y)(x,y) approaches (0,0)(0,0). Because the denominator vanishes at the origin, the question is not answered by direct substitution alone; one must analyze limiting behavior from the plane.

lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
02

Path-testing method for multivariable limits

For functions of two variables, the clip presents the method of approaching the target point along different paths. If two paths give different limiting values, the general limit does not exist. This extends the familiar one-variable idea of comparing left and right limits.

03

Two-path criterion for nonexistence

If a function has two distinct approach paths ending at the same point and the corresponding path-limits are unequal, then the unrestricted multivariable limit at that point fails to exist. This is a sufficient test for DNE, though not a test for existence.

04

Directional limits are not the general limit

The video stresses that a function can have well-defined limits along particular directions or curves while still lacking a general limit at the point. The general limit requires the same value no matter how the point is approached.

05

Common paths to try first

The suggested search order is to begin with the coordinate axes, then try simple slanted lines such as y=xy=x or y=mxy=mx, and then consider other paths if needed. Curves such as y=x2y=x^2 are also part of the broader space of possible approaches.

06

Why the precise definition is needed to prove existence

Agreement along several tested paths does not prove that a multivariable limit exists. To establish existence rigorously, one must use the precise definition of the limit and control the function's behavior for all sufficiently close points, not just a few sample paths.

07

Problem: limit of a two-variable rational function at the origin

The lesson asks whether lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)}\frac{x^4-4y^2}{x^2+2y^2} exists. Because this is a multivariable limit, the value must be the same no matter how (x,y)(x,y) approaches (0,0)(0,0). The instructor tests this by checking separate paths.

lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
08

Path test along the y-axis

Along the y-axis, x=0x=0 for every point. Substituting x=0x=0 into the function gives −4y22y2\frac{-4y^2}{2y^2}, which simplifies to −2-2 after canceling y2y^2 for y≠0y\neq 0. So the path limit along the y-axis is −2-2.

lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}=-2
09

Path test along the x-axis

Along the x-axis, y=0y=0 for every point. Substituting y=0y=0 gives x4x2=x2\frac{x^4}{x^2}=x^2 for x≠0x\neq 0. Then letting x→0x\to 0 yields 02=00^2=0. So the path limit along the x-axis is 00.

lim⁡(x,0)→(0,0)x4x2=lim⁡(x,0)→(0,0)x2=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}=\lim_{(x,0)\to(0,0)}x^2=0
10

Why different path limits imply DNE

If a function of two variables approaches different values along two different paths to the same point, the overall limit at that point cannot exist. Here the y-axis path gives −2-2 and the x-axis path gives 00, so the board concludes −2≠0-2\neq 0 and therefore the limit is DNE.

−2≠0⇒DNE-2\neq 0 \Rightarrow \text{DNE}
11

Caution: equal path values do not prove existence

The ending comment warns that getting the same value on two paths would not be enough to conclude that the multivariable limit exists. Additional paths may still need to be checked before claiming existence.

12

Two-Path Test for Non-Existence

A method to prove that a multivariable limit does not exist by finding two different paths of approach to the target point that yield different limiting values. If lim⁡path 1f≠lim⁡path 2f\lim_{\text{path 1}} f \neq \lim_{\text{path 2}} f, then the overall limit DNE.

If lim⁡path 1f(x,y)≠lim⁡path 2f(x,y), then lim⁡f(x,y) DNE.\text{If } \lim_{\text{path 1}} f(x,y) \neq \lim_{\text{path 2}} f(x,y), \text{ then } \lim f(x,y) \text{ DNE.}
13

Limit Along the Y-Axis

By substituting x=0x=0 into the function, we evaluate the limit as yy approaches 0. The y2y^2 terms cancel out, leaving a constant value.

lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2} = -2
14

Limit Along the X-Axis

By substituting y=0y=0 into the function, we evaluate the limit as xx approaches 0. Simplifying the expression yields x2x^2, which evaluates to 0 at the origin.

lim⁡(x,0)→(0,0)x4x2=lim⁡(x,0)→(0,0)x2=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2} = \lim_{(x,0)\to(0,0)} x^2 = 0
15

Misconception: Finite Paths Prove Existence

Testing multiple paths and getting the same result does not prove a limit exists. There are infinitely many curves and lines one could use to approach a point. To prove existence, the precise epsilon-delta definition must be used.

Detailed learning notes

Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.

Symbols · 18

(x,y)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows (x,y)→(0,0)(x,y)\to(0,0) in the limit expression.

  2. Audio
    Observation

    The speaker says the problem asks for the limit as x,yx,y approaches zero zero.

Symbol

(x,y)

Meaning

An ordered pair of real variables representing a point in the plane from which the function is evaluated.

Domain

Points in R2\mathbb{R}^2, especially near (0,0)(0,0).

(0,0)

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The limit notation contains (0,0)(0,0).

  2. Diagram
    Observation

    A green dot marks the origin on the coordinate sketch.

Symbol

(0,0)

Meaning

The target point in the plane toward which (x,y)(x,y) is taken to approach.

Domain

A specific point in R2\mathbb{R}^2.

x4−4y2x^4-4y^2

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The numerator written on the board is x4−4y2x^4-4y^2.

  2. Audio
    Observation

    The speaker reads it as x to the fourth minus four y squared.

Symbol

x4−4y2x^4-4y^2

Meaning

The numerator of the rational two-variable function whose limit is being studied.

Domain

Defined for all real xx and yy.

x2+2y2x^2+2y^2

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The denominator written on the board is x2+2y2x^2+2y^2.

  2. Audio
    Observation

    The speaker reads it as quantity x squared plus two y squared.

Symbol

x2+2y2x^2+2y^2

Meaning

The denominator of the rational two-variable function whose limit is being studied.

Domain

Defined for all real xx and yy; it equals 00 only at (0,0)(0,0).

f(x,y)=x4−4y2x2+2y2f(x,y)=\frac{x^4-4y^2}{x^2+2y^2}

Approximate timing
Derived from the video
Evidence
  1. Formula
    Observation

    The displayed expression is lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}.

Uncertainties
  1. The video does not explicitly introduce a separate name such as f(x,y)f(x,y); this label is an analyst convenience.

Symbol

f(x,y)=x4−4y2x2+2y2f(x,y)=\frac{x^4-4y^2}{x^2+2y^2}

Meaning

The multivariable rational function under consideration in the limit problem.

Domain

All (x,y)∈R2(x,y)\in\mathbb{R}^2 with (x,y)≠(0,0)(x,y)\neq(0,0).

x=0x=0

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker mentions approaching along the y-axis.

  2. Animation
    Observation

    A yellow arrow is drawn down the vertical axis toward the origin.

Symbol

x=0x=0

Meaning

The vertical-axis path used as one possible way to approach (0,0)(0,0).

Domain

Points of the form (0,y)(0,y) with y→0y\to 0.

y=0y=0

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker mentions approaching along the x-axis.

  2. Animation
    Observation

    A yellow arrow is drawn along the horizontal axis toward the origin.

Symbol

y=0y=0

Meaning

The horizontal-axis path used as one possible way to approach (0,0)(0,0).

Domain

Points of the form (x,0)(x,0) with x→0x\to 0.

y=xy=x

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says we could look at the value as we approach along the line y equals x.

  2. Animation
    Observation

    A diagonal yellow arrow is drawn toward the origin.

Symbol

y=xy=x

Meaning

A diagonal straight-line path through the origin used to test directional behavior.

Domain

Points of the form (t,t)(t,t) with t→0t\to 0.

y=mx

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says we can try some different lines too, or just along some line y equals mx like this one that we drew here.

  2. Animation
    Observation

    Additional yellow arrows are drawn from other directions toward the origin.

Uncertainties
  1. The symbol mm is spoken but not written on the board.

Symbol

y=mx

Meaning

A family of straight-line paths through the origin with slope mm, used to search for different limiting values.

Domain

Points of the form (t,mt)(t,mt) with t→0t\to 0 and fixed real slope mm.

y=x2y=x^2

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says we really have to show that as we come in here on the line y equals x squared.

  2. Animation
    Observation

    A curved yellow path is drawn into the origin, visually distinct from the straight arrows.

Uncertainties
  1. The equation y=x2y=x^2 is spoken rather than written on the board.

Symbol

y=x2y=x^2

Meaning

A curved path through the origin mentioned as another possible approach direction.

Domain

Points of the form (t,t2)(t,t^2) with t→0t\to 0.

x

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The variable x appears in the displayed function and in the path notation (x,0).

Symbol

x

Meaning

First coordinate variable of the two-variable function.

Domain

Real values; in the worked paths it is either fixed at 0 or allowed to approach 0.

y

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The variable y appears in the displayed function and in the path notation (0,y).

Symbol

y

Meaning

Second coordinate variable of the two-variable function.

Domain

Real values; in the worked paths it is either fixed at 0 or allowed to approach 0.

Knowledge points · 10

Problem statement for a two-variable limit

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board displays: Find the limit of the multivariable function, or state that it DNE. lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}.

  2. Audio
    Observation

    The speaker introduces the task as finding the limit of a multivariable function or stating that it does not exist.

Definition
Explanation

The clip sets up a concrete limit question for a rational function of two variables at the origin. The mathematical object under study is the behavior of x4−4y2x2+2y2\frac{x^4-4y^2}{x^2+2y^2} as (x,y)(x,y) approaches (0,0)(0,0) from the plane.

Formula
lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
Conditions
  1. The limit point is (0,0)(0,0).

  2. The function is a quotient of polynomial expressions in xx and yy.

  3. The denominator vanishes at (0,0)(0,0), so direct substitution is not immediately informative.

Path-based method for testing multivariable limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that because we have a multivariable function, we have to look at the limit as we approach the point zero zero from different directions.

  2. Animation
    Observation

    Multiple yellow arrows are drawn from different directions into the origin on a coordinate sketch.

Method
Explanation

The video explains a standard strategy for two-variable limits: compare the values obtained when approaching the target point along different paths. If two paths give different limiting values, then the overall limit cannot exist. This mirrors the one-variable idea of checking left-hand and right-hand limits, but in two dimensions there are infinitely many possible directions and curves of approach.

Formula
Conditions
  1. Applies to limits of functions of two or more variables.

  2. Finding equal values along several paths does not by itself prove existence of the full limit.

  3. Finding unequal values along two paths is enough to conclude the full limit does not exist.

Prerequisites
  1. Problem statement for a two-variable limit

Directional limits versus the general limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says we can have limits in specific directions, but the general limit doesn't exist.

  2. Audio
    Observation

    The speaker adds that the general limit can only exist if the function approaches the same value no matter which direction we approach from.

Definition
Explanation

The clip distinguishes between limits taken along particular paths and the full two-variable limit. A function may have well-defined behavior along chosen lines or curves while still failing to have a single overall limit at the point, because the general limit requires agreement across all approaches.

Formula
Conditions
  1. The general limit requires the same limiting value for every approach to the point.

  2. Specific directional or pathwise limits may exist even when the general limit does not.

Prerequisites
  1. Path-based method for testing multivariable limits

Role of the precise epsilon-delta style definition

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says the only way we can really do that is by using the precise definition of the limit to show it.

  2. Audio
    Observation

    The speaker also says that if many paths keep giving the same answer, then we can go to the precise definition of the limit, which is more complicated, to really prove that it approaches the same value no matter where we approach from.

Method
Explanation

The video states that path testing is useful for disproving existence, but proving existence of a multivariable limit requires the precise definition of the limit. In other words, checking finitely many paths is not enough to establish the full limit; one must control the function's behavior for all sufficiently close points.

Formula
Conditions
  1. Used when path tests do not produce a contradiction.

  2. Required to prove the general limit exists rather than merely to disprove it.

Prerequisites
  1. Path-based method for testing multivariable limits
  2. Directional limits versus the general limit

Problem statement: limit of a two-variable rational function at the origin

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    Top text reads: Find the limit of the multivariable function, or state that it DNE.

  2. Formula
    Observation

    Displayed limit: lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}.

Definition
Explanation

The clip presents a standard multivariable calculus problem: determine whether the limit of f(x,y)=x4−4y2x2+2y2f(x,y)=\frac{x^4-4y^2}{x^2+2y^2} exists as (x,y) approaches (0,0), or conclude that it does not exist.

Formula
lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
Conditions
  1. The target point is the origin (0,0).

  2. The function is a quotient of polynomial expressions in x and y.

Path restriction to the y-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that approaching along the y-axis means x=0x=0 everywhere on that line.

  2. Formula
    Observation

    Board writes lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}=-2.

Method
Explanation

To test the two-variable limit, the instructor first restricts the approach to the y-axis by setting x=0x=0. This converts the original function into a one-variable expression in y, which can then be simplified and evaluated as y approaches 0.

Formula
lim⁡(0,y)→(0,0)04−4y202+2y2=lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{0^4-4y^2}{0^2+2y^2}=\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}=-2
Conditions
  1. Along the chosen path, x is fixed at 0.

  2. The simplification uses cancellation of y2y^2 for y≠0y\neq 0 before taking the limit.

Prerequisites
  1. Problem statement: limit of a two-variable rational function at the origin

Path restriction to the x-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker asks what happens if we approach along the x-axis and states that y=0y=0 everywhere on that axis.

  2. Formula
    Observation

    Board writes lim⁡(x,0)→(0,0)x4x2=x2=02=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}=x^2=0^2=0.

Method
Explanation

The second test path is the x-axis, obtained by setting y=0y=0. The function reduces to a one-variable expression in x, which simplifies to x2x^2 and then evaluates to 0 as x approaches 0.

Formula
lim⁡(x,0)→(0,0)x4−4(0)2x2+2(0)2=lim⁡(x,0)→(0,0)x4x2=lim⁡(x,0)→(0,0)x2=0\lim_{(x,0)\to(0,0)} \frac{x^4-4(0)^2}{x^2+2(0)^2}=\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}=\lim_{(x,0)\to(0,0)} x^2=0
Conditions
  1. Along the chosen path, y is fixed at 0.

  2. After simplification, the remaining expression still depends on x, so the endpoint value x=0x=0 is substituted.

Prerequisites
  1. Problem statement: limit of a two-variable rational function at the origin

Conclusion from two different path limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker summarizes that the y-axis gives -2 and the x-axis gives 0, so because these are different values, the limit at (0,0) does not exist.

  2. Formula
    Observation

    Board writes -2 ≠0\neq 0 and boxes DNE.

Method
Explanation

The clip uses the two-path test: if a multivariable function approaches different values along two different paths to the same point, then the overall limit at that point cannot exist. Here the two computed path limits are -2 and 0, so the final answer is DNE.

Formula
−2≠0⇒lim⁡(x,y)→(0,0)x4−4y2x2+2y2 DNE-2\neq 0 \quad\Rightarrow\quad \lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}\text{ DNE}
Conditions
  1. Both paths must approach the same point (0,0).

  2. The two path limits must be unequal.

Prerequisites
  1. Path restriction to the y-axis
  2. Path restriction to the x-axis

Two-Path Test for Non-Existence of a Limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains approaching the origin along different lines to see if the value is different.

  2. Formula
    Observation

    Two different limits are calculated: one equals -2 and the other equals 0.

Method
Explanation

To show that a multivariable limit does not exist, one can approach the target point along two different paths. If the function yields different limiting values along these paths, the overall limit does not exist.

Formula
If lim⁡path 1f(x,y)≠lim⁡path 2f(x,y), then lim⁡f(x,y) DNE.\text{If } \lim_{\text{path 1}} f(x,y) \neq \lim_{\text{path 2}} f(x,y), \text{ then } \lim f(x,y) \text{ DNE.}
Conditions
  1. The paths must both approach the same target point.

  2. The limits along the chosen paths must exist.

Precise Definition of a Limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker states that if all paths yielded the same value, one would need to use the precise definition of the limit to prove it exists because there are an infinite number of paths.

Definition
Explanation

The formal epsilon-delta definition required to rigorously prove that a limit exists, as testing a finite number of paths is insufficient for a general proof.

Formula
Conditions
  1. Used when attempting to prove a limit exists, not to disprove it.

Claims and conditions · 5

Two-path disagreement criterion for nonexistence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that if the value along the y-axis is different from the value along the line y equals x, then we know that we can approach this point zero zero from two directions and get two different values, which tells us that the general limit does not exist.

Proposition
Statement

If a two-variable function approaches two different limiting values along two different paths ending at the same point, then the general limit at that point does not exist.

Hypotheses
  1. There are two distinct paths approaching the same point.

  2. The function has a limiting value along each path.

  3. Those two limiting values are different.

Quantifiers

For a function of two variables and a fixed target point, existence of two paths with unequal path-limits implies nonexistence of the full limit.

All-directions requirement for a general limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says the general limit can only exist if the function approaches the same value no matter which direction we approach from.

Proposition
Statement

A general multivariable limit at a point can exist only if the function approaches the same value along every possible approach to that point.

Hypotheses
  1. The function is being considered near a point in the plane.

  2. One is asking about the full two-variable limit rather than a single path limit.

Quantifiers

For all approaches to the point, the limiting value must be the same.

Path agreement does not replace the precise proof of existence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that if we keep getting the same answer every time, then we can go to the precise definition of the limit ... to really prove that it approaches the same value no matter where we approach from.

Proposition
Statement

Obtaining the same limiting value along several tested paths does not by itself prove that the full multivariable limit exists; the precise definition is needed for a rigorous existence proof.

Hypotheses
  1. Several paths have been tested and produced the same limiting value.

  2. The goal is to prove existence of the general limit, not merely to search for a counterexample.

Quantifiers

For any finite collection of tested paths, matching path-limits do not imply the unrestricted limit exists.

Two-path criterion for nonexistence of a multivariable limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker states that because the function approaches two different values at (0,0), the limit does not exist.

  2. Formula
    Observation

    The board records -2 ≠0\neq 0 and then DNE as the final conclusion.

Proposition
Statement

If a function of two variables approaches different limiting values along two different paths to the same point, then the limit at that point does not exist.

Hypotheses
  1. The function is evaluated near a common point, here (0,0).

  2. At least two distinct approach paths are considered.

  3. The pathwise limits exist and are unequal.

Quantifiers

For a given point and two paths approaching that point.

Conclusion of Non-Existence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker concludes 'we know that this particular limit does not exist.'

  2. Formula
    Observation

    The board shows '-2 ≠0\neq 0' and a boxed 'DNE'.

Proposition
Statement

The limit lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4 - 4y^2}{x^2 + 2y^2} does not exist.

Hypotheses
  1. The function approaches -2 along the y-axis.

  2. The function approaches 0 along the x-axis.

  3. -2 is not equal to 0.

Quantifiers

N/AN/A

Derivations and proofs · 7

From one-sided limits to path limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says finding the limit here is going to be similar to the process we used to find the limit when we were dealing with a two-dimensional function, and recalls checking the left-hand limit and the right-hand limit.

  2. Audio
    Observation

    The speaker then says that for a multivariable function we have to look at the limit as we approach the point from different directions.

Uncertainties
  1. The phrase 'two-dimensional function' in the audio appears to refer to the earlier one-variable setting being contrasted with the present multivariable setting; the exact wording is preserved from the source.

Intuitive argument
Steps
  1. Expression
    Explanation

    In the simpler single-variable setting, the speaker recalls checking the left-hand limit and the right-hand limit.

    Justification

    Stated directly in the audio as prior knowledge being reviewed.

    Shown in the video
  2. Expression
    Explanation

    If those one-sided limits both existed and were equal, then the general limit existed.

    Justification

    This is the familiar criterion for ordinary one-variable limits.

    Shown in the video
  3. Expression
    Explanation

    For a function of two variables, the analogous idea is to compare approaches from different directions in the plane.

    Justification

    The speaker explicitly says we follow the same process except that now we approach from different directions.

    Shown in the video
Conclusion

The clip motivates the path-testing method by analogy with one-sided limits in single-variable calculus.

Ordered strategy for testing paths

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says typically we start by approaching along the y-axis and along the x-axis.

  2. Audio
    Observation

    The speaker continues that if we still get the same answers there, then we'll try approaching along the line y equals x or just along some line y equals mx.

  3. Audio
    Observation

    The speaker adds that if those also give the same answers, we can try some different lines too, and if we keep getting the same answer every time, then we can go to the precise definition of the limit.

Intuitive argument
Steps
  1. Expression
    Explanation

    First test the coordinate-axis paths, namely the xx-axis and yy-axis.

    Justification

    These are the simplest paths through the origin and are explicitly named first by the speaker.

    Shown in the video
  2. Expression
    Explanation

    If those agree, test a diagonal line such as y=xy=x or a more general line y=mxy=mx.

    Justification

    The speaker says this is the next step when the axes give the same answer.

    Shown in the video
  3. Expression
    Explanation

    If those also agree, continue trying other lines.

    Justification

    The speaker says we can try some different lines too.

    Shown in the video
  4. Expression
    Explanation

    Only if repeated path tests keep producing the same value should one switch to the precise definition to attempt a proof of existence.

    Justification

    This is stated directly in the audio.

    Shown in the video
Conclusion

The practical workflow in the clip is to search for a counterexample path first, escalating from axes to slanted lines and then to other curves before considering a rigorous existence proof.

Derivation of the limit along the y-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains that along the y-axis x=0x=0, then substitutes 0 for x in the function.

  2. Formula
    Observation

    The board shows the substitution and simplification to -2.

Proof
Steps
  1. Expression
    lim⁡(0,y)→(0,0)x4−4y2x2+2y2\lim_{(0,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
    Explanation

    Start from the original limit and restrict the approach to points of the form (0,y).

    Justification

    This is the chosen test path: the y-axis.

    Shown in the video
  2. Expression
    lim⁡(0,y)→(0,0)04−4y202+2y2\lim_{(0,y)\to(0,0)} \frac{0^4-4y^2}{0^2+2y^2}
    Explanation

    Substitute x=0x=0 everywhere in the numerator and denominator.

    Justification

    Every point on the y-axis has x-coordinate 0.

    Shown in the video
  3. Expression
    lim⁡(0,y)→(0,0)−4y22y2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}
    Explanation

    Simplify 040^4 and 020^2 to 0, leaving only the y2y^2 terms.

    Justification

    Arithmetic simplification of constants.

    Shown in the video
  4. Expression
    −2-2
    Explanation

    Cancel the common factor y2y^2 and divide -4 by 2.

    Justification

    For y≠0y\neq 0 the quotient equals -2, so the path limit is -2.

    Shown in the video
Conclusion

Along the y-axis, the function approaches -2.

Derivation of the limit along the x-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that along the x-axis y=0y=0, then substitutes 0 for y and simplifies.

  2. Formula
    Observation

    The board shows x4x2=x2=02=0\frac{x^4}{x^2}=x^2=0^2=0.

Proof
Steps
  1. Expression
    lim⁡(x,0)→(0,0)x4−4y2x2+2y2\lim_{(x,0)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}
    Explanation

    Start from the original limit and restrict the approach to points of the form (x,0).

    Justification

    This is the chosen test path: the x-axis.

    Shown in the video
  2. Expression
    lim⁡(x,0)→(0,0)x4−4(0)2x2+2(0)2\lim_{(x,0)\to(0,0)} \frac{x^4-4(0)^2}{x^2+2(0)^2}
    Explanation

    Substitute y=0y=0 everywhere in the numerator and denominator.

    Justification

    Every point on the x-axis has y-coordinate 0.

    Shown in the video
  3. Expression
    lim⁡(x,0)→(0,0)x4x2\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}
    Explanation

    The terms containing y vanish, leaving x4x^4 over x2x^2.

    Justification

    Arithmetic simplification after substitution.

    Shown in the video
  4. Expression
    lim⁡(x,0)→(0,0)x2\lim_{(x,0)\to(0,0)} x^2
    Explanation

    Reduce the quotient by canceling x2x^2.

    Justification

    For x≠0x\neq 0, x4x2=x2\frac{x^4}{x^2}=x^2.

    Shown in the video
  5. Expression
    02=00^2=0
    Explanation

    Now let x approach 0 and evaluate the remaining expression.

    Justification

    Direct substitution into the simplified one-variable expression.

    Shown in the video
Conclusion

Along the x-axis, the function approaches 0.

Final derivation that the two-variable limit does not exist

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explicitly compares the two results and concludes the limit does not exist.

  2. Formula
    Observation

    The board writes -2 ≠0\neq 0 and boxes DNE.

Proof
Steps
  1. Expression
    −2-2
    Explanation

    Recall the limit value found along the y-axis.

    Justification

    Previously derived path result.

    Shown in the video
  2. Expression
    00
    Explanation

    Recall the limit value found along the x-axis.

    Justification

    Previously derived path result.

    Shown in the video
  3. Expression
    −2≠0-2\neq 0
    Explanation

    Compare the two path limits.

    Justification

    They are unequal numbers.

    Shown in the video
  4. Expression
    DNE\text{DNE}
    Explanation

    Conclude that the full limit at (0,0) does not exist.

    Justification

    By the two-path criterion for nonexistence of multivariable limits.

    Shown in the video
Conclusion

Because two different approach paths give different limiting values, the overall limit at (0,0) does not exist.

Limit along the y-axis

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The calculation lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2} = -2 is shown on the board.

Numerical verification
Steps
  1. Expression
    lim⁡(0,y)→(0,0)x4−4y2x2+2y2\lim_{(0,y)\to(0,0)} \frac{x^4 - 4y^2}{x^2 + 2y^2}
    Explanation

    Start with the original limit expression.

    Justification

    Problem statement.

    Shown in the video
  2. Expression
    lim⁡(0,y)→(0,0)04−4y202+2y2\lim_{(0,y)\to(0,0)} \frac{0^4 - 4y^2}{0^2 + 2y^2}
    Explanation

    Substitute x=0x = 0 to approach along the y-axis.

    Justification

    Definition of approaching along the y-axis.

    Derived from the video
  3. Expression
    lim⁡(0,y)→(0,0)−4y22y2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}
    Explanation

    Simplify the numerator and denominator.

    Justification

    Arithmetic simplification.

    Shown in the video
  4. Expression
    −2-2
    Explanation

    Cancel the y2y^2 terms (for y≠0y \neq 0) and evaluate the constant limit.

    Justification

    Algebraic cancellation and limit of a constant.

    Shown in the video
Conclusion

The limit along the y-axis is -2.

Limit along the x-axis

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The calculation lim⁡(x,0)→(0,0)x4x2=x2=02=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2} = x^2 = 0^2 = 0 is shown on the board.

Numerical verification
Steps
  1. Expression
    lim⁡(x,0)→(0,0)x4−4y2x2+2y2\lim_{(x,0)\to(0,0)} \frac{x^4 - 4y^2}{x^2 + 2y^2}
    Explanation

    Start with the original limit expression.

    Justification

    Problem statement.

    Shown in the video
  2. Expression
    lim⁡(x,0)→(0,0)x4−4(0)2x2+2(0)2\lim_{(x,0)\to(0,0)} \frac{x^4 - 4(0)^2}{x^2 + 2(0)^2}
    Explanation

    Substitute y=0y = 0 to approach along the x-axis.

    Justification

    Definition of approaching along the x-axis.

    Derived from the video
  3. Expression
    lim⁡(x,0)→(0,0)x4x2\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}
    Explanation

    Simplify the expression.

    Justification

    Arithmetic simplification.

    Shown in the video
  4. Expression
    lim⁡(x,0)→(0,0)x2\lim_{(x,0)\to(0,0)} x^2
    Explanation

    Cancel x2x^2 from the numerator and denominator (for x≠0x \neq 0).

    Justification

    Algebraic cancellation.

    Shown in the video
  5. Expression
    02=00^2 = 0
    Explanation

    Evaluate the limit as x approaches 0.

    Justification

    Direct substitution.

    Shown in the video
Conclusion

The limit along the x-axis is 0.

Worked examples · 3

Main worked example introduced but not yet computed

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2} under the instruction to find the limit or state that it DNE.

  2. Audio
    Observation

    The speaker describes this as the particular problem and reads the expression aloud.

Uncertainties
  1. No numerical path evaluations are completed within this 180-second excerpt.

Problem

Find lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}, or state that the limit does not exist.

Given
  1. The function is x4−4y2x2+2y2\frac{x^4-4y^2}{x^2+2y^2}.

  2. The approach point is (0,0)(0,0).

  3. The task allows either computing the limit or concluding that it does not exist.

Goal

Determine whether the two-variable limit exists at the origin, and if not, justify that it does not exist.

Steps
  1. Expression
    Explanation

    Set up the problem as a multivariable limit at the origin.

    Justification

    Directly shown on the board and read aloud.

    Shown in the video
  2. Expression
    Explanation

    Explain that the method will be to compare values obtained by approaching (0,0)(0,0) along different paths.

    Justification

    Stated in the audio during the conceptual introduction.

    Shown in the video
  3. Expression
    Explanation

    Sketch the coordinate plane and mark the origin, then indicate candidate paths such as the axes, y=xy=x, y=mxy=mx, and y=x2y=x^2.

    Justification

    Shown through the drawing animation and described in the audio.

    Shown in the video
  4. Expression
    Explanation

    State the plan to look for two paths that yield different values, which would prove nonexistence.

    Justification

    Explicitly stated by the speaker.

    Shown in the video
Answer

Within this excerpt, the final numerical answer is not reached; the clip only establishes the setup and strategy.

Verification

The absence of a completed computation is evident from the audio ending mid-explanation and from the board never showing substituted path results.

Worked example: show that the limit at the origin does not exist

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The entire clip works the displayed example lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}.

  2. Audio
    Observation

    The speaker narrates each path computation and the final conclusion.

Problem

Find lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}, or state that it does not exist.

Given
  1. The function is f(x,y)=x4−4y2x2+2y2f(x,y)=\frac{x^4-4y^2}{x^2+2y^2}.

  2. The target point is (0,0).

  3. Two test paths are used: the y-axis and the x-axis.

Goal

Determine whether the two-variable limit exists at (0,0).

Steps
  1. Expression
    lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2}=-2
    Explanation

    Approach along the y-axis by setting x=0x=0 and simplify.

    Justification

    Path restriction plus algebraic cancellation.

    Shown in the video
  2. Expression
    lim⁡(x,0)→(0,0)x4x2=lim⁡(x,0)→(0,0)x2=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2}=\lim_{(x,0)\to(0,0)} x^2=0
    Explanation

    Approach along the x-axis by setting y=0y=0 and simplify.

    Justification

    Path restriction, cancellation, then substitution x=0x=0.

    Shown in the video
  3. Expression
    −2≠0-2\neq 0
    Explanation

    Compare the two path limits.

    Justification

    Different numerical results along two valid paths to the same point.

    Shown in the video
  4. Expression
    DNE\text{DNE}
    Explanation

    State the final conclusion for the original two-variable limit.

    Justification

    Two-path test for nonexistence.

    Shown in the video
Answer

The limit does not exist (DNE).

Verification

The conclusion is verified by exhibiting two explicit paths to (0,0) that yield different limiting values, -2 and 0.

Evaluating a Multivariable Limit

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The entire problem and solution are written on the board.

  2. Audio
    Observation

    The speaker narrates the process of finding the limit or stating it DNE.

Problem

Find the limit of the multivariable function lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4 - 4y^2}{x^2 + 2y^2}, or state that it DNE.

Given
  1. The function f(x,y)=x4−4y2x2+2y2f(x,y) = \frac{x^4 - 4y^2}{x^2 + 2y^2}

  2. The target point (0,0)(0,0)

Goal

Determine if the limit exists and find its value, or prove it does not exist.

Steps
  1. Expression
    lim⁡(0,y)→(0,0)−4y22y2=−2\lim_{(0,y)\to(0,0)} \frac{-4y^2}{2y^2} = -2
    Explanation

    Approach the origin along the y-axis (set x=0x=0) and evaluate the limit.

    Justification

    Two-path test method.

    Shown in the video
  2. Expression
    lim⁡(x,0)→(0,0)x4x2=0\lim_{(x,0)\to(0,0)} \frac{x^4}{x^2} = 0
    Explanation

    Approach the origin along the x-axis (set y=0y=0) and evaluate the limit.

    Justification

    Two-path test method.

    Shown in the video
  3. Expression
    −2≠0-2 \neq 0
    Explanation

    Compare the results from the two different paths.

    Justification

    Logical comparison.

    Shown in the video
  4. Expression
    DNE\text{DNE}
    Explanation

    Conclude that the overall limit does not exist.

    Justification

    Two-path test theorem.

    Shown in the video
Answer

The limit does not exist (DNE).

Verification

The two chosen paths yield different limiting values (-2 and 0), which is sufficient to prove non-existence.

Visual events · 9

Static presentation of the problem statement

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A black chalkboard fills the frame with white handwritten text at the top and the limit expression centered below it.

  2. Formula
    Observation

    The visible formula is lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}.

Objects
  1. White handwritten instruction line

  2. Limit expression

  3. Blackboard background

Changes
  1. No new writing appears during most of this interval.

  2. The cursor or pointer moves around the formula while the speaker reads and explains it.

Invariants
  1. The problem statement remains unchanged on screen.

  2. The target point (0,0)(0,0) and the rational expression stay visible throughout.

Interpretation

This visual phase anchors the mathematical task before any geometric explanation begins.

Drawing the plane and marking the origin

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    A vertical double-headed arrow is drawn first, then a horizontal double-headed arrow crossing it, forming coordinate axes.

  2. Animation
    Observation

    A green dot is placed at the intersection of the axes.

Objects
  1. Vertical axis

  2. Horizontal axis

  3. Green dot at the intersection

Changes
  1. The blank lower-left portion of the board becomes a simple coordinate sketch.

  2. The origin is highlighted with a colored point.

Invariants
  1. The original limit expression remains at the top of the board.

  2. The axes represent the standard xx-yy plane around (0,0)(0,0).

Interpretation

The sketch converts the abstract limit point (0,0)(0,0) into a geometric location that can be approached from many directions.

Emphasizing the limit point in the formula

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    A yellow rectangular highlight appears around (0,0)(0,0) in the limit expression.

Objects
  1. Yellow box around (0,0)(0,0)

  2. Limit expression

Changes
  1. The target point in the formula is visually singled out.

Invariants
  1. The rest of the formula is unchanged.

  2. The coordinate sketch remains visible below.

Interpretation

This links the algebraic notation (x,y)→(0,0)(x,y)\to(0,0) to the geometric origin just drawn.

Illustrating multiple approach paths

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    Yellow arrows are drawn sequentially toward the origin along the vertical axis, horizontal axis, and a diagonal direction.

  2. Animation
    Observation

    Later, additional yellow arrows and a curved yellow path are added, indicating more ways to approach the origin.

  3. Audio
    Observation

    The speaker names the y-axis, x-axis, the line y=xy=x, lines of the form y=mxy=mx, and the curve y=x2y=x^2 while these marks are being made.

Uncertainties
  1. Some later arrows are generic illustrations of other directions rather than labeled equations written on the board.

Objects
  1. Yellow arrow down the y-axis

  2. Yellow arrow along the x-axis

  3. Yellow diagonal arrow for y=xy=x

  4. Additional yellow arrows for other lines

  5. Curved yellow path associated with y=x2y=x^2

Changes
  1. The number of indicated approach directions increases over time.

  2. The sketch evolves from two axes into a multi-path diagram around the origin.

Invariants
  1. All drawn paths terminate at the same green origin point.

  2. The underlying function and limit statement do not change.

Interpretation

The animation visualizes the central idea that a two-variable limit depends on behavior under many possible approaches, not just one.

Blackboard layout and coordinate sketch

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    A blackboard shows the problem text at top, the limit expression near the upper middle, and a coordinate sketch on the left with arrows pointing toward the origin.

Objects
  1. Top instruction text

  2. Limit expression lim⁡(x,y)→(0,0)x4−4y2x2+2y2\lim_{(x,y)\to(0,0)} \frac{x^4-4y^2}{x^2+2y^2}

  3. Left-side coordinate axes sketch

  4. Multiple arrows directed toward the origin

Changes
  1. New handwritten work is added below the original problem as the solution progresses.

  2. The final boxed DNE is written near the end.

Invariants
  1. The original problem statement remains visible throughout.

  2. The coordinate sketch continues to represent approach toward the origin.

Interpretation

The visual organization separates the problem statement from the step-by-step path calculations, while the arrow diagram reinforces that the issue is the behavior of the function as (x,y) approaches (0,0) from different directions.

Writing of the y-axis path calculation

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The board adds lim⁡(0,y)→(0,0)\lim_{(0,y)\to(0,0)} and then the simplified fraction leading to -2.

Objects
  1. Expression lim⁡(0,y)→(0,0)\lim_{(0,y)\to(0,0)}

  2. Fraction −4y22y2\frac{-4y^2}{2y^2}

  3. Result -2

Changes
  1. The path notation (0,y) is introduced.

  2. The substituted fraction is written and simplified to -2.

Invariants
  1. The original function at the top remains unchanged.

Interpretation

This visual step encodes the restriction x=0x=0 and shows the resulting one-variable limit along the y-axis.

Writing of the x-axis path calculation

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The board adds lim⁡(x,0)→(0,0)\lim_{(x,0)\to(0,0)} and the chain x4x2=x2=02=0\frac{x^4}{x^2}=x^2=0^2=0.

Objects
  1. Expression lim⁡(x,0)→(0,0)\lim_{(x,0)\to(0,0)}

  2. Fraction x4x2\frac{x^4}{x^2}

  3. Simplified expression x2x^2

  4. Result 0

Changes
  1. The path notation (x,0) is introduced.

  2. The substituted fraction is simplified to x2x^2 and then evaluated at 0.

Invariants
  1. The earlier y-axis result -2 remains visible above.

Interpretation

This visual step encodes the restriction y=0y=0 and shows the resulting one-variable limit along the x-axis.

Final comparison and boxed conclusion

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The board writes -2 ≠0\neq 0 and then boxes DNE.

Objects
  1. Inequality -2 ≠0\neq 0

  2. Boxed label DNE

Changes
  1. The inequality comparing the two path limits is written.

  2. The final answer DNE is boxed.

Invariants
  1. Both prior path results remain visible.

Interpretation

The visual emphasis on the boxed DNE marks the logical endpoint of the two-path argument.

Blackboard Layout and Annotations

Clear evidence
Shown in the video
Evidence
  1. Diagram
    Observation

    The blackboard displays the problem statement at the top, a coordinate system with colored arrows indicating paths on the left, and the step-by-step calculations below.

Objects
  1. Coordinate axes

  2. Colored arrows representing paths

  3. Mathematical expressions

  4. Boxed 'DNE' conclusion

Changes
  1. The speaker points to different parts of the board while explaining the concepts.

Invariants
  1. The written mathematical content remains static throughout the clip.

Interpretation

The visual layout organizes the problem, the geometric intuition (paths), and the algebraic execution of the two-path test.

Misconceptions · 4

Mistaking repeated path agreement for a proof of existence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that if we keep getting the same answer every time, then we can go to the precise definition of the limit ... to really prove that it approaches the same value no matter where we approach from.

Misconception

One might think that if several tested paths all give the same limiting value, then the full multivariable limit must exist.

Clarification

The video explicitly warns against this: path testing can help find nonexistence, but proving existence requires the precise definition of the limit because all approaches must be controlled.

Confusing a directional limit with the general limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says we can have limits in specific directions, but the general limit doesn't exist.

Misconception

One might assume that a limit along a particular direction is enough to define the overall limit at the point.

Clarification

The clip distinguishes pathwise or directional behavior from the general two-variable limit, which requires the same value for every approach to the point.

Matching path values do not prove the limit exists

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that if both paths had given -2, then one might have wanted to try a couple other values as well.

Misconception

Getting the same limit along two chosen paths is enough to conclude that the full multivariable limit exists.

Clarification

The video indicates that equal results on two paths would still leave room for testing additional paths; agreement on finitely many paths does not establish existence.

Assuming finite path testing proves existence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explicitly warns that even if many paths gave the same value, it wouldn't prove the limit exists without the precise definition, because there are an infinite number of paths.

Misconception

Believing that if a function approaches the same value along several tested paths, the multivariable limit must exist.

Clarification

Testing a finite number of paths can only disprove the existence of a limit. To prove it exists, one must use the precise epsilon-delta definition to account for all infinite possible paths.

Concept relations · 10

Path-based method for testing multivariable limits → Problem statement for a two-variable limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker compares the present multivariable problem to the earlier process of checking left-hand and right-hand limits.

Application
Explanation

The method of comparing approaches is presented as an extension of the familiar one-variable idea of matching one-sided limits to the two-variable setting.

Path-based method for testing multivariable limits → Two-path disagreement criterion for nonexistence

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains that two different path values imply the general limit does not exist.

Proof dependency
Explanation

The path-testing method relies on the proposition that disagreement between two path-limits is sufficient to conclude nonexistence of the full limit.

Directional limits versus the general limit → All-directions requirement for a general limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker contrasts limits in specific directions with the general limit.

Contrast
Explanation

The clip uses the distinction between directional behavior and the unrestricted limit to explain why the all-directions condition matters.

Role of the precise epsilon-delta style definition → Path-based method for testing multivariable limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that after repeated path tests give the same answer, one must use the precise definition of the limit to prove existence.

Generalizes
Explanation

The precise-definition approach is presented as the stronger, fully rigorous method that supersedes finite path checking when one wants to prove the limit exists.

Problem statement: limit of a two-variable rational function at the origin → Path restriction to the y-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker moves from the general limit problem to the specific y-axis path.

  2. Formula
    Observation

    The board rewrites the original limit using (0,y) -> (0,0).

Application
Explanation

The general two-variable limit problem is investigated by applying a path restriction to the y-axis.

Problem statement: limit of a two-variable rational function at the origin → Path restriction to the x-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker then asks what happens along the x-axis.

  2. Formula
    Observation

    The board rewrites the original limit using (x,0) -> (0,0).

Application
Explanation

The same original limit is tested again using a second path restriction, now to the x-axis.

Path restriction to the y-axis → Conclusion from two different path limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker compares the two results and concludes DNE.

  2. Formula
    Observation

    The board writes -2 ≠0\neq 0 and boxes DNE.

Proof dependency
Explanation

The final nonexistence conclusion depends on the previously computed y-axis path limit.

Path restriction to the x-axis → Conclusion from two different path limits

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker compares the two results and concludes DNE.

  2. Formula
    Observation

    The board writes -2 ≠0\neq 0 and boxes DNE.

Proof dependency
Explanation

The final nonexistence conclusion also depends on the previously computed x-axis path limit.

Path restriction to the y-axis → Path restriction to the x-axis

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explicitly contrasts the y-axis result with the x-axis result.

  2. Formula
    Observation

    The board displays -2 from one path and 0 from the other, then -2 ≠0\neq 0.

Contrast
Explanation

The two methods are contrasted because they use different coordinate restrictions and produce different limiting values.

Two-Path Test for Non-Existence of a Limit → Precise Definition of a Limit

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker transitions from discussing the results of the path tests to mentioning the need for the precise definition if the values had matched.

Contrast
Explanation

The two-path test is used to disprove the existence of a limit by finding contradictory evidence, whereas the precise definition is required to prove the existence of a limit across all possible paths.

Find an answer · 13

How do you show that a multivariable limit does not exist by using different paths?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains that two different path values imply the general limit does not exist.

Knowledge points
  1. Path-based method for testing multivariable limits
  2. Two-path disagreement criterion for nonexistence

Why is checking several paths with the same limit not enough to prove a two-variable limit exists?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says that if many paths give the same answer, one still needs the precise definition of the limit to prove existence.

Knowledge points
  1. Role of the precise epsilon-delta style definition
  2. Path agreement does not replace the precise proof of existence
  3. Mistaking repeated path agreement for a proof of existence

What is the difference between a directional limit and the general limit of a function of two variables?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker distinguishes limits in specific directions from the general limit.

Knowledge points
  1. Directional limits versus the general limit
  2. All-directions requirement for a general limit
  3. Confusing a directional limit with the general limit

Which paths should be tried first when testing a limit at the origin for a two-variable function?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker lists a typical order: y-axis, x-axis, then y=xy=x or y=mx, then other lines.

Knowledge points
  1. Path-based method for testing multivariable limits
  2. Ordered strategy for testing paths

What multivariable limit problem is being solved in this clip?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The opening board text and displayed limit define the task.

Knowledge points
  1. Problem statement: limit of a two-variable rational function at the origin

Why does approaching along the y-axis mean substituting x=0x=0?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains that along the y-axis, x=0x=0 everywhere.

Knowledge points
  1. Path restriction to the y-axis

Why does approaching along the x-axis mean substituting y=0y=0?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains that along the x-axis, y=0y=0 everywhere.

Knowledge points
  1. Path restriction to the x-axis

How is the value -2 obtained from the y-axis path?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows −4y22y2=−2\frac{-4y^2}{2y^2}=-2.

Knowledge points
  1. Path restriction to the y-axis
  2. Derivation of the limit along the y-axis

How is the value 0 obtained from the x-axis path?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The board shows x4x2=x2=02=0\frac{x^4}{x^2}=x^2=0^2=0.

Knowledge points
  1. Path restriction to the x-axis
  2. Derivation of the limit along the x-axis

Why does the video conclude that the limit at (0,0) does not exist?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker says the limit does not exist because the two paths give different values.

  2. Formula
    Observation

    The board writes -2 ≠0\neq 0 and DNE.

Knowledge points
  1. Conclusion from two different path limits
  2. Two-path criterion for nonexistence of a multivariable limit
  3. Final derivation that the two-variable limit does not exist

Does getting the same answer along two paths prove that a multivariable limit exists?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker notes that if both paths gave -2, more values might still need to be tried.

Knowledge points
  1. Matching path values do not prove the limit exists

How do I use the two-path test to show a multivariable limit does not exist?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The speaker explains the process of approaching along different lines to see if values are different.

  2. Formula
    Observation

    The board shows the calculation of two different path limits leading to a DNE conclusion.

Knowledge points
  1. Two-Path Test for Non-Existence of a Limit
  2. Evaluating a Multivariable Limit
Coverage and review notes

Covered · The board shows the problem statement and the speaker reads the limit expression.

Covered · The speaker explains that the multivariable case is handled by comparing approaches from different directions, by analogy with one-sided limits.

Covered · A coordinate sketch is drawn, the origin is marked, and (0,0)(0,0) in the formula is highlighted.

Covered · Several approach paths are illustrated and the speaker states that two different path values imply the general limit does not exist.

Covered · The speaker contrasts directional limits with the general limit and states the all-directions requirement.

Covered · The speaker gives the practical order of path tests and explains that proving existence ultimately requires the precise definition of the limit.

Covered · Opening statement of the multivariable limit problem and displayed function.

Covered · Computation of the limit along the y-axis by setting x=0x=0.

Covered · Brief transition after finishing the y-axis result and before introducing the x-axis path.

Covered · Computation of the limit along the x-axis by setting y=0y=0.

Covered · Explanation of why substitution at the endpoint was needed in the x-axis case and setup for comparing the two path results.

Covered · Comparison of -2 and 0 and final boxed conclusion DNE.

Covered · Closing remark that matching path values would still call for testing more paths.

Covered · The entire clip covers the explanation and execution of the two-path test for a specific multivariable limit, including the conceptual warning about proving existence.

Explore the knowledge in this video

Reviewed subject paths