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How do you check if a differential equation is exact?

To check if a differential equation is exact, you must verify that the partial derivative of the coefficient of dx with respect to y is equal to the partial derivative of the coefficient of dy with respect to x. If these mixed partial derivatives are equal, the equation is exact.

Conditions

  • The equation must be in the form M(x,y)dx+N(x,y)dy=0M(x,y)dx + N(x,y)dy = 0.
  • M and N must have continuous first-order partial derivatives.

Reasoning, step by step

  1. Identify M(x,y)M(x,y) as the coefficient of dx and N(x,y)N(x,y) as the coefficient of dy.
  2. Calculate the partial derivative of M with respect to y, treating x as a constant.
  3. Calculate the partial derivative of N with respect to x, treating y as a constant.
  4. Compare the two resulting expressions.
  5. Conclude the equation is exact if the partial derivatives are equal.

Example

For the equation (-3x^2 - y)dx+(3y2−x)dy=0dx + (3y^2 - x)dy = 0, M=−3x2−yM = -3x^2 - y and N=3y2−xN = 3y^2 - x. The partial derivative of M with respect to y is -1, and the partial derivative of N with respect to x is -1. Since -1 = -1, the equation is exact.

Common misconceptions

  • Assuming the equation is exact without checking the partial derivatives.
  • Confusing the partial derivative of M with respect to y with the partial derivative of M with respect to x.

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