How do you check if a differential equation is exact?
Conditions
- The equation must be in the form .
- M and N must have continuous first-order partial derivatives.
Reasoning, step by step
- Identify as the coefficient of dx and as the coefficient of dy.
- Calculate the partial derivative of M with respect to y, treating x as a constant.
- Calculate the partial derivative of N with respect to x, treating y as a constant.
- Compare the two resulting expressions.
- Conclude the equation is exact if the partial derivatives are equal.
Example
For the equation (-3x^2 - y), and . The partial derivative of M with respect to y is -1, and the partial derivative of N with respect to x is -1. Since -1 = -1, the equation is exact.
Common misconceptions
- Assuming the equation is exact without checking the partial derivatives.
- Confusing the partial derivative of M with respect to y with the partial derivative of M with respect to x.
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Related questions
The final implicit solution for the example equation (-3x^2 - y) is -x^ - xy = C.
Conditions: The equation is exact.; The terms are combined correctly without double-counting.
The term -xy appears in both the integration of M with respect to x and the integration of N with respect to y. When combining the results to form the potential function, shared terms should only be included once to avoid double-counting.
Conditions: The term -xy is present in both antiderivatives.
When integrating a multivariable function with respect to one variable, the other variables are treated as constants. Therefore, the 'constant' of integration can be any function that depends only on the other variables, which in this case is y.
Conditions: The integration is with respect to x.; The function M depends on both x and y.
The presenter leaves the answer in implicit form because the equation contains multiple powers and products of y, making it cumbersome to solve explicitly for y.
Conditions: The solution contains multiple y terms.; An explicit solution for y is not attempted.
The steps involve finding the potential function by integrating M with respect to x and N with respect to y, then combining the results to form the implicit solution .
Conditions: The differential equation has been verified as exact.
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