What is the general criterion for equality of two fractions and in a localization?
Conditions
- is a commutative ring.
- is multiplicatively closed.
- and .
Reasoning, step by step
- Start with two arbitrary fractions and .
- Compute the cross-product difference .
- Check if there exists an element that annihilates this difference, i.e., .
- Conclude that the fractions are equivalent if and only if such a exists.
Example
The board writes , then , then . The speaker explains that equality holds not only when the cross product itself vanishes, but when there exists some such that .
Common misconceptions
- Thinking two fractions in are equal exactly when .
- Assuming the naive cross-multiplication rule is sufficient in the general localization setting.
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The naive condition is insufficient because in a general commutative ring, elements can be annihilated by nonzero elements of . The refined condition requires the existence of some such that , which accounts for zero-divisor phenomena and ensures the equivalence relation is well-defined.
Conditions: is a general commutative ring (not necessarily an integral domain).; is multiplicatively closed.
Two fractions and in the localization are defined to be equivalent if there exists an element in the multiplicatively closed set such that . This relation ensures that the fractions represent the same element in the localization.
Conditions: is a commutative ring.; is a multiplicatively closed subset.; and .
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