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What is the missing middle column if the shown method is carried to completion?

The missing middle column is [0−169]\begin{bmatrix} 0 \\ -16 \\ 9 \end{bmatrix}. This is obtained by applying the transformation A to the middle column of B, which is [023]\begin{bmatrix} 0 \\ 2 \\ 3 \end{bmatrix}. The calculation involves taking the linear combination of the columns of A with coefficients 0, 2, and 3.

Conditions

  • A and B are the specific 3x3 matrices shown in the video.
  • The method of column-wise composition is used.

Reasoning, step by step

  1. Identify the middle column of B: [023]\begin{bmatrix} 0 \\ 2 \\ 3 \end{bmatrix}.
  2. Express this as 0⋅e1+2⋅e2+3⋅e30 \cdot e_1 + 2 \cdot e_2 + 3 \cdot e_3.
  3. Apply A: 0⋅A(e1)+2⋅A(e2)+3⋅A(e3)0 \cdot A(e_1) + 2 \cdot A(e_2) + 3 \cdot A(e_3).
  4. Substitute the columns of A: 0⋅[−3−33]+2⋅[0−23]+3⋅[0−41]0 \cdot \begin{bmatrix} -3 \\ -3 \\ 3 \end{bmatrix} + 2 \cdot \begin{bmatrix} 0 \\ -2 \\ 3 \end{bmatrix} + 3 \cdot \begin{bmatrix} 0 \\ -4 \\ 1 \end{bmatrix}.
  5. Compute the sum: [0−46]+[0−123]=[0−169]\begin{bmatrix} 0 \\ -4 \\ 6 \end{bmatrix} + \begin{bmatrix} 0 \\ -12 \\ 3 \end{bmatrix} = \begin{bmatrix} 0 \\ -16 \\ 9 \end{bmatrix}.

Example

The video explicitly calculates this: '0 times the first column of A, plus 2 times the second column of A, plus 3 times the third column of A... Finally, we add these two vectors component-wise: [0, -4, 6] + [0, -12, 3] = [0, -16, 9].'

Common misconceptions

  • Arithmetic errors in scalar multiplication or vector addition.
  • Using the wrong coefficients from the middle column of B.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.