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What is the probability of winning the three-digit lottery under the lesson's uniform model?

The probability of winning is 1/10001/1000. This is derived from the fact that there are 1000 equally likely ordered tickets, and only one of them is the winning ticket.

Conditions

  • The lottery consists of three positions.
  • Each position has ten possible choices (digits 0-9).
  • Repetition of digits is allowed.
  • The model assumes a uniform distribution over all possible tickets.

Reasoning, step by step

  1. Calculate the number of choices for the first position: 10.
  2. Calculate the number of choices for the second position: 10.
  3. Calculate the number of choices for the third position: 10.
  4. Multiply the choices to find the total number of ordered tickets: 10×10×10=100010 \times 10 \times 10 = 1000.
  5. Identify that there is exactly one winning ticket.
  6. Calculate the probability as the ratio of winning tickets to total tickets: 1/10001/1000.

Example

The script states: 'With ten choices in each of three positions and repetition allowed, there are 1000 ordered tickets. Under the lesson’s uniform model, one winning ticket has probability 1/10001/1000.'

Common misconceptions

  • Assuming the probability is 1/101/10 because there are 10 digits.
  • Believing that repetition is not allowed, which would reduce the total number of tickets to 10×9×8=72010 \times 9 \times 8 = 720.
  • Confusing the probability of matching a specific digit with the probability of matching the entire sequence.

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