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How do you compute the expected value of a three-digit lottery ticket with a $500 prize and a $1 cost under a uniform model?

The expected value is calculated as a long-run average by weighting each net outcome by its probability. First, determine the net profit for winning and losing. Then, multiply each net outcome by its respective probability and sum the results. For this specific lottery, the expectation is -$0.50 per ticket.

Conditions

  • The lottery has three positions with ten choices each, allowing repetition.
  • The model assumes all 1000 ordered tickets are equally likely.
  • The ticket costs $1.
  • The winning prize payment is $500, which includes the full prize amount.

Reasoning, step by step

  1. Calculate the total number of possible tickets: 10×10×10=100010 \times 10 \times 10 = 1000.
  2. Determine the probability of winning: 1/10001/1000.
  3. Determine the probability of losing: 999/1000999/1000.
  4. Calculate the net outcome for a win: 500−1=499500 - 1 = 499 dollars.
  5. Calculate the net outcome for a loss: 0−1=−10 - 1 = -1 dollar.
  6. Compute the expected value: (499×11000)+(−1×9991000)(499 \times \frac{1}{1000}) + (-1 \times \frac{999}{1000}).
  7. Simplify the expression: 4991000−9991000=−5001000=−0.50\frac{499}{1000} - \frac{999}{1000} = -\frac{500}{1000} = -0.50.
  8. Interpret the result as the long-run mean profit per ticket.

Example

The script states: 'If the 500-dollar payment includes the full prize, net outcomes are 499 on a win and −1 on a loss. The expectation is 499/1000−999/1000=−0.50499/1000-999/1000=-0.50 dollars per ticket.'

Common misconceptions

  • Confusing the gross prize ($500) with the net profit ($499).
  • Believing the expected value guarantees a loss of exactly $0.50 on a single play.
  • Assuming the probability of winning is different if the digits are not independent or if repetition is not allowed.

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