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Why does a mismatch between left and right limits prevent continuity at a point?

Continuity at a point requires the two-sided limit to exist and equal the function value. The two-sided limit exists only if the left-hand limit and the right-hand limit are equal. If they mismatch, the two-sided limit does not exist, violating the second condition of continuity. This creates a 'jump' in the graph, meaning the function does not approach a single unique value from both sides.

Conditions

  • The point is an interior point of the domain.
  • The left-hand limit and right-hand limit are finite but unequal.

Reasoning, step by step

  1. Recall the definition of continuity: lim⁡x→af(x)=f(a)\lim_{x \to a} f(x) = f(a).
  2. Recognize that lim⁡x→af(x)\lim_{x \to a} f(x) exists only if lim⁡x→a−f(x)=lim⁡x→a+f(x)\lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x).
  3. Observe that a mismatch means the two-sided limit is undefined.
  4. Conclude that since the limit does not exist, it cannot equal f(a)f(a), so the function is discontinuous.

Example

At x=3x=3, the left limit is 7 and the right limit is 11. Their mismatch prevents a two-sided limit and produces a jump.

Common misconceptions

  • Thinking that the function value f(a)f(a) can compensate for the missing limit.
  • Believing that the average of the two limits is the two-sided limit.
  • Confusing the non-existence of the limit with the limit being zero.

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