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Calculus / English

3 Step Continuity Test, Discontinuity, Piecewise Functions & Limits | Calculus

The Organic Chemistry Tutor · YouTube · 10:10

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Apply the continuity test to piecewise functions and distinguish jumps from removable discontinuities.

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Chapters

0:13Three conditions4:30A jump7:30A removable discontinuity

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At an interior point a, continuity requires that f(a)f(a) is defined, the two-sided limit exists, and that limit equals f(a)f(a). Check the correct branch on each side.

At x=3x=3 in the first example, the left limit is 7 and the right limit is 11. Their mismatch prevents a two-sided limit and produces a jump.

In the second example, both one-sided limits at x=−1x=-1 equal 3, but f(−1)=5f(-1)=5. The limit exists; redefining this single function value as 3 would restore continuity.

Knowledge cards

01

Three conditions

At an interior point a, continuity requires that f(a)f(a) is defined, the two-sided limit exists, and that limit equals f(a)f(a). Check the correct branch on each side.

02

A jump

At x=3x=3 in the first example, the left limit is 7 and the right limit is 11. Their mismatch prevents a two-sided limit and produces a jump.

03

A removable discontinuity

In the second example, both one-sided limits at x=−1x=-1 equal 3, but f(−1)=5f(-1)=5. The limit exists; redefining this single function value as 3 would restore continuity.

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  • Continuity ExplanationAt 0:13
    Why this connection?

    At an interior point a, continuity requires that f(a)f(a) is defined, the two-sided limit exists, and that limit equals f(a)f(a). Check the correct branch on each side. At x=3x=3 in the first example, the left limit is 7 and the right limit is 11. Their mismatch prevents a two-sided limit and produces a jump. In the second example, both one-sided limits at x=−1x=-1 equal 3, but f(−1)=5f(-1)=5. The limit exists; redefining this single function value as 3 would restore continuity.

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