A prism element
Approximate each prism volume by base area times height at a sample point.
Charles队长 · Bilibili · 0:32
This video segment provides a geometric visualization of calculating the volume under a curved surface using double integrals. It begins by showing a 3D coordinate system with a smooth upward-curving surface over a rectangular base region. The region is then subdivided into small grid cells, and vertical rectangular prisms are constructed on each cell to approximate the volume of the solid cylinder-like shape. Finally, one individual prism is isolated and magnified on the right side, labeled with its infinitesimal base area Δσ and height . The formal definition of the double integral for volume appears at the bottom: _{||T||→0} .
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Generated from the video's visuals and explanation; not verbatim speech.
This segment aims to intuitively demonstrate how to calculate the volume of a solid bounded above by a curved surface through the limit of Riemann sums. The scene first plots a smooth, upward-bulging surface in a 3D Cartesian coordinate system, along with its rectangular projection forming a closed planar region D on the horizontal plane. To compute the volume of the space between this surface and region D, we uniformly partition the base region D into numerous tiny rectangular grids. Next, upon each micro-grid, we extrude upwards to generate a series of slender rectangular prisms, using the corresponding surface height as their altitude. The sum of the volumes of these prisms forms a rough approximation of the true volume of the curved-top solid. As the grid partitions become increasingly dense, this stepped approximation model converges infinitely close to the actual smooth surface.
Isolate one prism: its base area is Δσᵢ and its height is f(ξᵢ,ηᵢ). Add their products and let the maximum mesh size tend to zero to obtain the exact volume. A continuous nonnegative height function justifies this example.
Approximate each prism volume by base area times height at a sample point.
For an integrable function, prism sums approach the double integral as the partition mesh tends to zero. Increasing the number alone is insufficient.
Treating the function as height above the base requires . Between two surfaces, integrate upper height minus lower height.
The reviewed prism and Riemann-sum cards explain a double integral through sums of sample heights times cell areas. For an integrable nonnegative height function, partitions with mesh tending to zero make these sums converge to the geometric volume. Increasing the number of cells alone is insufficient; a solid between two surfaces uses the upper-minus-lower height.
The convergence occurs when the partition of the base region becomes arbitrarily fine, specifically when the maximum mesh size (norm of the partition, denoted or ) approaches zero. Additionally, the function must be integrable over ; in the context of the video's geometric visualization, continuity and non-negativity are cited as justifying factors for the specific example shown.
Conditions: The maximum diameter of any sub-region in the partition tends to zero ().; The function is defined on the region .; For the specific geometric intuition presented, is assumed to be continuous and non-negative.
The definition is justified when the height function is continuous and nonnegative over the base region D. This ensures that the surface is smooth enough and lies above the base, allowing the Riemann sum limit to represent a physical volume.
Conditions: The function is continuous.; The function is nonnegative ().; The base region D is a closed planar region.
The volume is approximated by uniformly partitioning the base region into small rectangular grids and constructing vertical rectangular prisms on each cell. The height of each prism corresponds to the surface value at a sample point, and the sum of these prism volumes forms a rough approximation of the true volume.
Conditions: The base region is a closed planar region D.; The surface is smooth and upward-bulging.; The grid partitions are uniform.
The volume is approximated by partitioning the base region into small rectangular grids. On each grid cell, a vertical rectangular prism is constructed with height equal to the function value at a sample point within that cell.
Conditions: The solid is bounded above by a smooth surface and below by a planar region .; The base region is uniformly partitioned into tiny rectangular grids.; represents the area of the -th sub-region.; is a sample point chosen within the -th sub-region.
The infinitesimal base area represents the area of a small grid cell on the base region D, while represents the height of the curved surface above that specific sample point. Their product approximates the volume of a single rectangular prism.
Conditions: The base region is subdivided into small grid cells.; A sample point is chosen within each cell.; The surface height is evaluated at the sample point.
The formal definition is given by the limit of the sum of the products of the function height and the infinitesimal base area, as the maximum mesh size of the partition approaches zero. Mathematically, it is expressed as , where is the height at a sample point and is the area element.
Conditions: The function represents the height of the surface above the region .; The limit is taken as the norm of the partition (maximum diameter of sub-regions) goes to zero.; The sum extends over all sub-regions of the partition.
The stepped approximation converges because as the grid partitions become increasingly dense, the maximum mesh size tends to zero. This causes the discrete sum of prism volumes to approach the continuous integral, infinitely close to the actual smooth surface volume.
Conditions: The grid partitions become increasingly dense.; The maximum mesh size tends to zero.; The surface is smooth and continuous.