Check both hypotheses
For , continuity on [a,b] and differentiability on (a,b) guarantee an interior point where the tangent slope equals the secant slope.
The Organic Chemistry Tutor · YouTube · 19:39
Apply the mean value theorem carefully, distinguishing endpoint behavior from interior differentiability.
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For , continuity on [a,b] and differentiability on (a,b) guarantee an interior point where the tangent slope equals the secant slope.
For ²− on [1,5], the secant slope is ()/4=2. Solving gives , inside the interval.
The cusp of at the endpoint 0 does not violate differentiability on (0,1). By contrast || has a corner at inside (0,2), so the theorem does not apply there.
For , continuity on [a,b] and differentiability on (a,b) guarantee an interior point where the tangent slope equals the secant slope.
For ²− on [1,5], the secant slope is ()/4=2. Solving gives , inside the interval.
The cusp of at the endpoint 0 does not violate differentiability on (0,1). By contrast || has a corner at inside (0,2), so the theorem does not apply there.
For , continuity on [a,b] and differentiability on (a,b) guarantee an interior point where the tangent slope equals the secant slope. For ²− on [1,5], the secant slope is ()/4=2. Solving gives , inside the interval. The cusp of at the endpoint 0 does not violate differentiability on (0,1). By contrast || has a corner at inside (0,2), so the theorem does not apply there.