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Calculus / Chinese

Area of a curved trapezoid

Charles队长 · Bilibili · 0:53

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The explanation, unpacked.

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The animation divides a curved region into vertical strips and explains the definite integral through sums of rectangle areas. For a continuous nonnegative function, the Riemann sums approach the geometric area as the maximum partition width tends to zero. A sign-changing function requires absolute values when computing total geometric area.

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Chapters

0:00The curved region0:15Rectangle approximations0:32Taking the Riemann-sum limit

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

Consider y=f(x)y=f(x) on [a,b], bounded by the graph, horizontal axis and the two endpoint lines. Assume f is continuous and nonnegative so its value gives the height of each vertical strip.

Divide the interval into small pieces and choose a sample point ξᵢ in each. A rectangle of height f(ξᵢ) and width Δxᵢ approximates that piece of area. Adding them gives the Riemann sum. The differential notation dA=f(x)dxf(x)dx summarizes this construction.

Refine the partition until its maximum width tends to zero. The sum approaches A=∫f(x)dxA=\int f(x)dx. The maximum width is essential: merely increasing the number of pieces is not enough. If f changes sign, the integral subtracts below-axis area; total geometric area is ∫\int |f(x)f(x)|dx.

Knowledge cards

01

Geometric versus signed area

A nonnegative continuous function integrates to its under-graph area. For sign-changing functions, use absolute values for total geometric area.

A=∫ab∣f(x)∣ dxA=\int_a^b |f(x)|\,dx
02

Area element

Use function value as height and horizontal increment as width. Finite rectangles approximate the area before a limit makes the answer exact.

dA=f(x) dxdA=f(x)\,dx
03

Riemann-sum limit

For a Riemann-integrable function, sums with arbitrary sample points approach the integral as the partition mesh tends to zero. More pieces alone do not guarantee this.

lim⁡∥P∥→0∑if(ξi)Δxi=∫abf(x) dx\lim_{\|\mathcal P\|\to0}\sum_i f(\xi_i)\Delta x_i=\int_a^b f(x)\,dx
04

Continuity is sufficient

Continuity on a closed interval guarantees Riemann integrability. Differentiability everywhere is not required.

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  • Definite integrals ExplanationAt 0:34
    Why this connection?

    Rectangle sums explain the definite integral: for a Riemann-integrable function, arbitrary-sample sums approach the integral as the partition mesh tends to zero. Continuity on a closed interval is sufficient. Nonnegative functions give under-graph area, while sign-changing functions require integrating the absolute value for total geometric area.

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